The sum of the squares of two consecutive odd positive integers is 74. Find the integers.

Answers

Answer 1
Answer: Let first odd number be x

Then that would be x^2 + (x+2)^2=74. We need to solve for x.

x^2 + (x+2)^2=74\n\ \nx^2 + x^2 + 4x+4 = 74\n\ \n2x^2 + 4x +4=74\n\ \n2x^2+4x-70 = 0\n\ \n2(x^2+2x-35)=0\n\ \n2(x+7)(x-5)=0\n\ \nx=-7\text{ or }5

But we need positive integers so we would have \boxed{x=5}, so then our integers would be x, x+2 = 5, 7

Check work:

5² + 7² = 25 + 49 = 74.

So our integers would be 5 and 7.

Hope this helps.
Answer 2
Answer: Let’s use a sample set.
Let’s use 5 and 7.
5•5=25
7•7=49
49+25=74
The integers are 5 and 7. The way I found this was by thinking of 9 and 11 at first. I knew that it would be entirely way too much, but 3 and 1 would be too little. 5 and 7 fit in the middle of those two samples.

Your answer is 5 and 7.

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A family buys 8 tickets to a show. They also pay a $5parking fee. They spend $61 to see the show.
What is the solution to the story?

13.80
10.60
07.00
8.25

Answers

Answer:

C. $7.00

Step-by-step explanation:

8 times 7 is 56 + 5 = 61

Jimmy purchased a government bond which has maturity value of $2500 after 9 months at 11 % simple interest. How much should he pay for this bond?

Answers

Answer: he should pay $23095 for this bond.

Step-by-step explanation:

We would apply the formula for determining simple interest which is expressed as

I = PRT/100

Where

I represents interest paid on the bond purchased.

P represents the principal or amount of bond purchased.

R represents interest rate

T represents the duration of the bond in years.

From the given information,

R = 11%

T = 9 months = 9/12 = 0.75

I = 25000 - P

Therefore

25000 - P = (P × 11 × 0.75)/100

25000 - P = 8.25P/100 = 0.0825P

P + 0.0825P = 25000

1.0825P = 25000

P = 25000/1.0825

P = $23095

Answer:$2706.25

Step-by-step explanation:

Principal(t)=$2500

Time(t)=9months=9/12=0.75year

Rate(r)=11%

Simple interest(si)=?

Si=(pxrxt)/100

Si=(2500x11x0.75)/100

Si=20625/100

Si=$206.25

Total amount=p + si

Total amount=2500+206.25

Total amount=$2706.25

Answer and I will give you brainiliest

Answers

Answer: You can buy 5 shirts if you buy 2 pair of pants.

Step-by-step explanation: Just out of curiosity, where do you live? I’m just wondering because I’ve never heard of the AED as a money unit... lol

Answer:

Step-by-step explanation:

Why are you so mean to me

A shipment to a warehouse consists of 500 PS4. The manager chooses a random sample of 50 PS4 and finds that 3 are defective. How many PS4 in the shipment are likely to be defective?

Answers

Answer:

30 PS4 in the shipment are likely to be defective

Step-by-step explanation:

We take the estimate from the sample and estimate to all the PS4 in store. This means that we can solve this question using a rule of 3.

From the sample of 50 PS4, 3 are defective. How many are expected to be defective out of 500?

50PS4 - 3 defective

500 PS4 - x defective

50x = 3*500

x = (1500)/(50)

x = 30

30 PS4 in the shipment are likely to be defective

Answer:

don't take my word but I think 150

Step-by-step explanation:

Find the sum of the first 8 terms of the geometric sequence if the first term is 9 and the common ratio is -3.

Answers


hmmmm let's see  \bf \textit{sum of a finite geometric sequence}=S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\n\n\begin{cases}n=n^(th)\ term\na_1=\textit{first term}\nr=\textit{common ratio}\end{cases}\qquad thus\implies S_8=9\left( \cfrac{1-(-3)^8}{1-(-3)} \right)


Veronique tried four different solutions to the matching problem shown. Which of her four answers would be thecorrect one?
Term
variable
Definition
a numerical factor of a term that has a
variable
a letter or symbol used to represent an
unknown quantity
a term without a variable
coefficient
constant
Definition
Term
a numerical factor of a term
that has a variable
variable
coefficient
a letter or symbol used to
represent an unknown quantity
a term without a variable
constant​

Answers

Answer:

the correct ansewer is C

Step-by-step explanation:

i took the unit test on edge the other guy is wrong