Answer:
To start add together all of the miles over 6 days. Added together it equals 30 miles.

Then take 30 miles divided by how many days.

30 divided by 6.

30 divided by 6=5

5 miles is the mean distance.

Then take 30 miles divided by how many days.

30 divided by 6.

30 divided by 6=5

5 miles is the mean distance.

On an intramural softball team, the proportion of hits to at bats for the entire team during the last season was 30% of 300 attempts. Estimate the true proportion of hits using a 90% CI. The answers need to be proportions (not percents) and rounded to the nearest hundredth (two (2) decimal places) to be counted as correct. (For example, if my CI is (0.1002, 0.2159) then they need to be input as 0.10 and 0.22 to be correct. **These are not the answers to this question :-) **)The lower bound is____ and the upper bound is ____

Please answer this, I am confused (5^2)(7^2)(3^2)

A basket of fruit contains 4 bananas, 3 apples, and 5 oranges. You intend to draw a piece of fruit from the basket, keep it, and then draw a 2nd piece of fruit from the basket. What is the probability of selecting two oranges in a row from the basket if you are blindfolded?

Please help I need these quickly. Please answer sensibly! I will give brainliest to the correct answer.

Would you use the Law of Sines or the law of cosines to solve a triangle if. given all three sides of the triangle?a. the Law of Sinesb. the Law of Cosinesâ€‹

Please answer this, I am confused (5^2)(7^2)(3^2)

A basket of fruit contains 4 bananas, 3 apples, and 5 oranges. You intend to draw a piece of fruit from the basket, keep it, and then draw a 2nd piece of fruit from the basket. What is the probability of selecting two oranges in a row from the basket if you are blindfolded?

Please help I need these quickly. Please answer sensibly! I will give brainliest to the correct answer.

Would you use the Law of Sines or the law of cosines to solve a triangle if. given all three sides of the triangle?a. the Law of Sinesb. the Law of Cosinesâ€‹

5. 4(5x + 2) + 11 = 18x + 3

6. 3x - 8x = -27 â€“ 13

Show Your Work

Answer:

4. x=4

5. x=-8

6. x=8

Step-by-step explanation:

It may take one extra step to get to the solution, but this method always works.

1. find the variable term that is smallest or most negative. Subtract all the terms on that side of the equation from both sides of the equation.

2. collect terms

3. divide the equation by the coefficient of the variable

4. add the opposite of the constant

___

4. The most negative variable term is -9x, which is on the left side. Subtracting (24-9x) from both sides of the equation, we have ...

0 = -3x -24 +9x

0 = -24 +6x

0 = -4 +x . . . . . divide by 6

4 = x . . . . . . . . add the opposite of -4

__

5. The smallest variable term is 18x, on the right. (The variable term on the left is 20x.)

4(5x +2) +11 -18x -3 = 0 . . . subtract the right side

2x +16 = 0 . . . collect terms

x +8 = 0 . . . . . . divide by 2

x = -8 . . . . . . . . add -8

__

6. All variables are on the left side, so we can just collect terms and divide by the coefficient of the variable.

-5x = -40 . . . collect terms

x = 8 . . . . . divide by -5

If you were to literally follow the steps above, you would recognize that -5x is less than 0x (the x-term on the right side of the equation), so you would subtract the left side, giving ...

0 = 5x -40

0 = x -8 . . . . . divide by 5

8 = x . . . . . . . . add 8

_____

Comment on this solution technique

You will often be told to solve these equations by separating the variable terms from the constant terms. This method actually puts the variable terms and constant terms together (and zero on the other side of the equal sign). The constant is separated from the variable as the last step of this solution process, rather than as one of the first steps. By doing this, we don't have to worry about which variable term or which constant term we're going to mess with.

The only reason for choosing the variable term with the smallest (least) coefficient in the first step is to ensure that the resulting variable coefficient is positive. This tends to reduce errors later on. You can also use that same strategy when solving the equation following the "separate constant terms and variable terms" approach.

**Answer:**

There are 2,000 grams left after 300 years.

**Step-by-step explanation:**

Giving the following information:

The half-life of a radioactive substance is 200 years. There are 8000 grams of the substance initially.

**First, we need to calculate the reduction of the substance each year:**

Yearly reduction= 8,000/400= 20 grams per year

**Now, for 300 years:**

300 year reduction= 20*300= 6,000

There are 2,000 grams left after 300 years.

x , y

If I understand the question correctly

If I understand the question correctly

O A. (-6,4)

B. (12,-4)

C. (4,-6)

O D. (-2, 4)

**Answer:**

c

**Step-by-step explanation:**

.

sure Yan pre

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398(100) = 39800.

52(10) = 52.

39800+ 52 = 39852

ANSWER: 39852

52(10) = 52.

39800+ 52 = 39852

ANSWER: 39852

**Answer:**

I think its 20.696

sorry if its wrong

**Step-by-step explanation:**

**Answer:**

B. -2t^2+3t+4

**Step-by-step explanation:**

The standard form as

ax^2 + bx + c

Option B meets that requirement, even though it has a '-' in front

All the given polynomials, A. t^4-1, B. -2t^2+3t+4 and C. 4t-7 are in standard form since their terms are written in descending order of their degrees.

In mathematical terms, a **polynomial** is in standard form if its terms are written in descending order of their degree, i.e. the power of the **variable**. This means the term with the highest power should be listed first, followed by the term with the next highest power, and so on. Let's look at the options:

- Option A: t^4-1 is in standard form because t^4 is the highest degree term and it is listed first.
- Option B: -2t^2+3t+4 is also in
**standard form**as the terms are arranged in descending order of degree: 2 (in t^2), 1 (in t) and then 0 (in 4). - Option C: 4t-7 is in standard form as well, with the degree of the term 4t being 1 and the degree of -7 being 0.

So, in conclusion, the polynomials in standard form from the provided options are A. t^4-1, B. -2t^2+3t+4 and C. 4t-7.

#SPJ11