# The image of a parabolic lens is traced onto a graph. The function f(x) = 1/4 (x+8)(x-4) represents the image. Atwhich points does the image cross the x-axis? O (-8, 0) and (4,0) (8,0) and (-4, 0) O (2, 0) and (-1,0) O (-2, 0) and (1, 0)

The image of the parabolic lens crosses the x axis at the points

(-8, 0) and (4, 0)

### How to find the points where the image cross x axis

To find the points where the graph of the function crosses the x axis we need to find the values of x that make f(x) equal to zero

hence we have that

f(x) = 1/4 (x + 8) (x - 4)

0  = 1/4 (x + 8) (x - 4)

x + 8 = 0

x = -8

OR

x - 4 = 0

x = 4

hence we can say that the image of the parabolic lens crosses the x axis at the points (-8, 0) and (4, 0)

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, where = Sample mean

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