Look at the picture below
Look at the picture below - 1

Answers

Answer 1
Answer:

Perimeter of the drawing is 22 inches, Perimeter of the garden is 770 inches and the Perimeter of Garden becomes 35 times the Perimeter of drawing when drawing length and breadth is multiply by 35.

What is Perimeter?

A closed route that covers, encircles, or outlines a one-dimensional length or a two-dimensional form is called a perimeter. A circle's or an ellipse's circumference is referred to as its perimeter.

Perimeter of Rectangle = 2 ( Length + Breadth)

(a) Here Length of Drawing is 7 inches and Breadth of Drawing is 4 inches.

So, Perimeter of the drawing = 2( 7 + 4 )

= 2 * 11

= 22 inches.

(b) According to question , Length and Breadth of actual garden is 35 times of the length and breadth of drawing.

Therefore, Length of Actual garden = 35 * 7 = 245 inches

and, Breadth of Actual garden = 35 * 5 = 140 inches.

So, Perimeter of the garden = 2( 245 + 140 )

= 2 * 385

= 770 inches.

(c) The perimeter of Garden becomes 35 times the perimeter of drawing when drawing length and breadth is multiply by 35.

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The 11th term of an progression is 25 and the sum of the first 4 terms is 49. The nth term of the progression is 491. Find the first term of the progression and the common difference
2. Find the value of n

Answers

Answer:

For 1: The first term is 10 and the common difference is (3)/(2)

For 2: The value of n is 27

Step-by-step explanation:

The n-th term of the progression is given as:

a_n=a_1+(n-1)d

where,

a_1 is the first term, n is the number of terms and d is the common difference

The sum of n-th terms of the progression is given as:

S_n=(n)/(2)[2a_1+(n-1)d]

where,

S_n is the sum of nth terms

  • For (1):

The 11th term of the progression:

25=a_1+10d               .......(1)

Sum of first 4 numbers:

49=(4)/(2)[2a_1+3d              ......(2)

Forming equations:

98=8a_1+12d

25=a_1+10d                  ( × 8)

The equations become:

98=8a_1+12d

200=8a_1+80d

Solving above equations, we get:

102=68d\n\nd=(102)/(68)=(3)/(2)

Putting value in equation (1):

25=a_1+10(3)/(2)\n\na_1=[25-15]=10

Hence, the first term is 10 and the common difference is (3)/(2)

  • For 2:

The nth term is given as:

49=10+(n-1)(3)/(2)

Solving the above equation:

39=(n-1)(3)/(2)\n\nn-1=26\n\nn=27

Hence, the value of n is 27

Final answer:

The value of n when the nth term of the progression is 49 is 22.

Explanation:

The 11th term of the progression (a11) is 25.

The sum of the first 4 terms (S4) is 49.

The nth term (an) is 49.

Let's find the answers to your questions:

Find the first term of the progression (a1) and the common difference (d):

We know that the nth term of an AP can be expressed as:

an = a1 + (n - 1)d

Substituting the values:

a11 = a1 + (11 - 1)d

25 = a1 + 10d

Now, we need to find a1 and d. We'll also use the information that the sum of the first 4 terms (S4) is 49. In an AP, the sum of the first n terms (Sn) can be expressed as:

Sn = (n/2)[2a1 + (n - 1)d]

For S4:

49 = (4/2)[2a1 + (4 - 1)d]

49 = 2[2a1 + 3d]

Now, we have two equations:

25 = a1 + 10d

49 = 2[2a1 + 3d]

Let's solve this system of equations to find a1 and d.

1. First, rearrange the first equation to isolate a1:

a1 = 25 - 10d

Now, substitute this expression for a1 into the second equation:

49 = 2[2(25 - 10d) + 3d]

Simplify and solve for d:

49 = 2[50 - 20d + 3d]

49 = 2[50 - 17d]

49 = 100 - 34d

34d = 100 - 49

34d = 51

d = 51/34

d = 3/2

2. Now that we have the common difference (d), we can find a1 using the first equation:

a1 = 25 - 10d

a1 = 25 - 10(3/2)

a1 = 25 - 15/2

a1 = (50 - 15)/2

a1 = 35/2

a1 = 17.5

So, the first term of the progression (a1) is 17.5, and the common difference (d) is 3/2.

Find the value of n when the nth term of the progression is 49:

We know that an = 49, and we can use the formula for an in an AP:

an = a1 + (n - 1)d

Substitute the values:

49 = 17.5 + (n - 1)(3/2)

49 - 17.5 = (n - 1)(3/2)

31.5 = (n - 1)(3/2)

To isolate n, multiply both sides by (2/3):

(n - 1)(3/2) = 31.5 * (2/3)

(n - 1) = 21

Now, add 1 to both sides to find n:

n = 21 + 1

n = 22

So, the value of n when the nth term of the progression is 49 is 22.

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A classroom board is 36 inches wide and 24 inches tall. Cherylis putting ribbon along the outside edge of the board. How
many inches of ribbon will she need?
24 inches
36 inches
A 156 inches B 120 inches
C90 inches
D 60 inches

Answers

The amount of ribbon needed is 120 inches

what is perimeter?

The perimeter formula for a rectangle states that P = (L + W) × 2, where P represents perimeter, L represents length, and W represents width.

Given:

length = 24 inches

width = 36 inches

So, amount of ribbon needed

=2(36+ 24)

=2(60)

=120 inches

Hence, the amount of ribbon needed is 120 inches

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Answer:

option B

Step-by-step explanation:

I need help with this! thanks​

Answers

Answer:

it should be about 6. try measuring the the 3 line with paper or something then put it on the other line

Step-by-step explanation:

Peggy is p years old maggie is 1 year less than 1/4 of peggys age what is maggies age in terms of p

Answers

Answer:

1/2m+100

Step-by-step explanation:

Equivalent expression for 18x-12x

Answers

Answer:

(18x - 12x) = (18 - 12)x = \boxed{6x}✓

Equivalent expression for (18x-12x) is 6x.

6x is the right answer.

6x will be your answer !!

For each pair of lines, determine whether they are parallel, perpendicular, or neither Line1 : 2y=5x+7
Line2: 4x+10y=8
Line3: y=5/2x-4

Answers

Answer: Lines 1 &3 are parallel with each other and line 2 is neither

Step-by-step explanation:

After singling out y for lines 1 & 2 you see they have the same slope 5/2 x

But for the second line it intersects worth both lines but does not make a 90 degree angle