# kim and courtney share a 20 ounce box of cereal. By the end of the week kim has eat 2/5 of the box and courtney has eaten 1/10 of the box of cereal what fraction of the box is left

Step-by-step explanation:

Kim ate 2/5 which is also equal to 4/10 and Courtney has eaten 1/10

4/10 + 1/10 = 5/10 = 1/2

## Related Questions

7th grade math help me plzzz

a. -7 + 3

b. draw 7 negatives + 7 positives

Step-by-step explanation:

3.a) -7 + 3

3.b) 4

I hope this helps!

A certain firm has plants a, b, and c producing respectively 35\%, 15\%, and 50\% of the total output. The probabilities of a nondefective product are, respectively, 0.75, 0.95, and 0.85. A customer receives a defective product. What is the probability that it came from plant c?

The proportion of production that is defective and from plant A is

... 0.35·0.25 = 0.0875

The proportion of production that is defective and from plant B is

... 0.15·0.05 = 0.0075

The proportion of production that is defective and from plant C is

... 0.50·0.15 = 0.075

Thus, the proportion of defective product that is from plant C is

... 0.075/(0.0875 +0.0075 +0.075) = 75/170 = 15/34 ≈ 44.12%

_____

P(C | defective) = P(C&defective)/P(defective)

The question required the use of Bayes' theorem to determine the probability of a defective product coming from plant c. Given the probabilities of defectiveness for each plant, the calculation indicated that there is approximately a 54.55% chance that a defective product came from plant c.

### Explanation:

The problem described can be solved using Bayes' theorem, which is a principle in Probability that is used when we need to revise/or update the probabilities of events given new data. Since a defective product is received, and we need to determine the probability of it coming from plant c, we apply Bayes' theorem for the probability of events a, b, and c (representative of the products from the respective plants).

The Bayesian formula we will use, given the probabilities of a, b and c respectively and the probability of receiving a nondefective product from these plants, is: P(c|defective) = [P(defective|c) * P(c)] / [P(defective|a) * P(a) + P(defective|b) * P(b) + P(defective|c) * P(c)].

First, calculate the probability of a defective product from each plant (1 minus the probability of a nondefective product): these are 0.25 for plant a, 0.05 for plant b, and 0.15 for plant c.

Then substitute the values: P(c|defective) = [0.15 * 0.50] / [(0.25 * 0.35) + (0.05 * 0.15) + (0.15 * 0.5)] = 0.075 / 0.1375 = 0.5454545.

So, given a defective product, there is approximately a 54.55% chance that it was produced by plant c.

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What is the value of x in the quadrilateral shown below?1250
959
1059
To
O A. 35°
OB. 45°
O C. 55°

Step-by-step explanation:

~

What is the 8th term of this sequence 2,8,18,36,66, 112,178

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कम्प्युटरको गति मापन गर्ने एकाइहरूलाई वर्णन गर्नुहोस् ।​

मापनको एकाईलाई हर्ट्ज (हर्ट्ज) भनिन्छ, जुन प्रति सेकंड टेक्निकली एक चक्र हो, घडीको गति मापन गर्न प्रयोग हुन्छ। ... कम्प्युटरको घडी गति सामान्यतया मेगाहेर्ट्झ (मेगाहर्ट्ज) वा गिगाहर्ट्ज (GHz) मा मापन गरिएको छ। एक मेगाहेर्ट्ज प्रति सेकेन्ड १० लाख टिक्स बराबर हुन्छ, र एक गिगाहर्ट्ज बराबर एक सेकेन्ड टिक टिक प्रति सेकेन्ड।

Figure A ~ Figure B
Find the volume of Figure A

9514 1404 393

1 m³

Step-by-step explanation:

The ratio of volumes is the cube of the ratio of corresponding linear dimensions.

Va/Vb = ((2 m)/(8 m))³ = (1/4)³ = 1/64

Va = Vb(1/64) = (64 cu. m)/(64) = 1 cu. m

The volume of figure A is 1 m³.

in the first box is 1 and the second one is 3