If a large marshmallow has a volume of 2.75 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.

Answers

Answer 1
Answer:
•   
Volume of the marshmallow:

V = 2.75 in^3          (but, 1 in^3 = 16.39 cm^3)

V = 2.75 × 16.39 cm^3

V = 2.75 × 16.39 cm^3

V = 45.0725 cm^3


•   Density:

d = 0.242 g/cm^3


•  Mass:

m = d × V

m = (0.242 g/cm^3) × (45.0725 cm^3)

m = (0.242 g/cm^3) × (45.0725 cm^3)

m = 10.907545 g

m ≈ 10.9 g   <———  this is the answer.


I hope this helps. =)

Answer 2
Answer:

Answer:

9.92g

Explanation:

2.50 in31×16.39 cm31 in3×0.242 gcm3=9.92 g


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Ocean water is the coldest at ​

Answers

The bottom of the ocean because it does not get sun light

Question 51 pts A breathalyzer is a device used to estimate the blood alcohol content of a suspected drunk driver by measuring the amount of alcohol in one's breath. The fuel cell breathalyzer employs the reaction below: CH3CH2OH(g)+O2(g)→HC2H3O2(g)+H2O(g) When a suspected drunk driver blows his or her breath through the fuel-cell breathalyzer, the device measures the current produced by the reaction and calculates the percent alcohol in the breath. How many moles of electrons are transferred per mole of ethanol, CH3CH2OH, in the reaction?

Answers

Answer:

Four moles of electrons

Explanation:

The reactions in a breathalyzer are redox reactions. Fuel cell breathalyzers consists of fuel cells with platinum electrodes. The current produced depends on the amount of alcohol in the breath. Detection of alcohol involves the oxidation of ethanol to ethanoic acid. The two half cells set in the process are;

Anode;

C2H5OH(aq) + 4OH^-(aq) ----------> CH3COOOH(aq) + 3H2O(l) + 4e

Cathode;

O2(g) + 2H2O(l) +4e--------> 4OH^-(aq)

Hence four electrons are transferred in the process.

Please help with this​

Answers

Answer:

4

Explanation:

Light refracts when it passes through something transparent at an angle so that eliminates the other 3.

or put differently

Light refracts whenever it travels at an angle into a substance with a different refractive index (optical density)

1.6x10^23 lead atoms. Find the weight in grams

Answers

Moles of lead(Pb) = 1.6x10^23/6.02x10^23 = 0.265 moles.

Weight of lead = moles x atomic weight of lead
                         =  0.265x207.2
                         =  54.908 grams.

Hope this helps!

A protein is Select one: a. a saturated ester of glycerol. b. a polysaccharide. c. an aromatic hydrocarbon. d. a polymer of amino acids. e. one of the units making up a nucleic acid.

Answers

Answer:

d. a polymer of amino acids

Explanation:

Got it right on the test.

Answer:

D

Explanation:

The building blocks or monomers of proteins are called amino acids. There are 20 different kinds of amino acids. The amino acids form long chains that are proteins. Therefore, proteins are polymers of amino acids.

Proteins are very important for the body because they have many different roles. They provide structure for tissues, act as enzymes, hormones and antibodies, aid in transportation and fluid regulation.

Therefore, the correct answer is D. a polymer of amino acids.

Consider the reaction: 2 HI (g) ⇌ H₂ (g) + I₂ (g) At equilibrium, the partial pressure of HI is 1.9 atm and the partial pressures of H₂ and I₂ are 7.9 and 2.3 respectively. What is Kp for this equilibrium?

Answers

Answer:

To determine the value of Kp for the given equilibrium, we need to use the partial pressures of the gases involved.

In the balanced equation: 2 HI (g) ⇌ H₂ (g) + I₂ (g), the stoichiometric coefficients are 2, 1, and 1 respectively.

At equilibrium, the expression for Kp is given by:

Kp = (P(H₂) * P(I₂)) / (P(HI)²)

Using the provided partial pressures:

P(HI) = 1.9 atm

P(H₂) = 7.9 atm

P(I₂) = 2.3 atm

Substituting these values into the expression for Kp:

Kp = (7.9 * 2.3) / (1.9²)

Kp ≈ 19.5 / 3.61

Calculating the result:

Kp ≈ 5.4

Therefore, the value of Kp for the given equilibrium is approximately 5.4.

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