A box is in the shape of a triangular prism. . The base of the triangular face of the box is 11 centimeters (cm). The height of the triangular face of the box is 7.5 cm. The length of the box is 15 cm. V =1/2hxbxl What is the volume of the box? A 277.5 cm B 577.5 cm C 618.75 cm D1237.5 cm

Answers

Answer 1
Answer:

Answer:

618.75  cm^(3)

Step-by-step explanation:

((11 cm)(7.5 cm)(15 cm))/(2) =618.75 cm^(3)


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What is 3 divided by 9,473

Answers

0.00031668953869. that's what it is
Exact Form - 3/9,473
Decimal Form - 0.00031668953869.

What is the result of 72 divided by 12? 6 8 9 12

Answers

Answer:

the answer is 6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Hope this helps!!!!!!

Find the prime factorization of
72

Answers

Answer:

72 = {2,2,2,3,3}

Step-by-step explanation:

72

89

2433

22

2. In an industrial training program, students have been averaging about 64 points on a standardized test. The lecture system was replaced by teaching machines with a lab instructor. There was some doubt as to whether the scores would decrease, increase, or stay the same. A sample of n = 60 students using the teaching machines was tested, resulting in a mean of 68 and a standard deviation of 12. Perform a hypothesis test to see if scores would decrease, increase, or stay the same. Use α = 0.05. Be sure to:1. State your hypotheses.
2. Find the value of the Test Statistic.
3. Find the p-value
4. State your decision (Reject or not)
5. State your conclusion.

Answers

Answer:

Case I

Null hypothesis:\mu = 64  

Alternative hypothesis:\mu \neq 64  

t=(68-64)/((12)/(√(60)))=2.582  

df=n-1=60-1=59  

Since is a two sided  test the p value would given by:  

p_v =2*P(t_((59))>2.582)=0.012  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v<\alpha so we can conclude that we have enough evidence to reject the null hypothesis.  

We can say that at 5% of significance the true mean is different from 64.

Case II

Null hypothesis:\mu \leq 64  

Alternative hypothesis:\mu > 64

The statistic not changes but the p value does and we have:

p_v =P(t_((59))>2.582)=0.006  

And we reject the null hypothesis on this case.

So we can conclude that the true mean is significantly higher than 64 at 5% of singnificance

Step-by-step explanation:

Data given and notation  

\bar X=68 represent the sample mean  

s=12 represent the sample standard deviation  

n=60 sample size  

\mu_o =64 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the population mean is different from 64 the system of hypothesis are :  

Null hypothesis:\mu = 64  

Alternative hypothesis:\mu \neq 64  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=(\bar X-\mu_o)/((s)/(√(n))) (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=(68-64)/((12)/(√(60)))=2.582  

P-value  

We need to calculate the degrees of freedom first given by:  

df=n-1=60-1=59  

Since is a two sided  test the p value would given by:  

p_v =2*P(t_((59))>2.582)=0.012  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v<\alpha so we can conclude that we have enough evidence to reject the null hypothesis.  

We can say that at 5% of significance the true mean is different from 64.

Now let's assume that we want to see if the mean is significantly higher than 64

Null hypothesis:\mu \leq 64  

Alternative hypothesis:\mu > 64

The statistic not changes but the p value does and we have:

p_v =P(t_((59))>2.582)=0.006  

And we reject the null hypothesis on this case.

So we can conclude that the true mean is significantly higher than 64 at 5% of singnificance

What is the median of this data set 14,18,31,34,44,50

Answers

The median is 31.83

Because:

14 + 18 + 31 + 34 + 44 + 50 = 191

191 / 6 = 31.83 (the median)

4s-12= 5s+51 what is the solution

Answers

Given data:

The given expression is 4s-12=5s+51.

The given expression can be written as,

4s-12=5s+51

4s-5s=51+12

-s=63

s=-63

Thus, the value of s is -63.