A construction worker is transporting pieces of plastic in two stacks with touching pieces. In Stack 1, both pieces of plastic are the same size. In Stack 2, the bottom piece is the same size as those in Stack 1, and the top piece is larger. The diagram above shows the energy of the molecules in the pieces of plastic before they touched.After a while, which of the two top plastic pieces will be cooler, and why?

Answers

Answer 1
Answer:

Answer:

The larger top plastic piece will be cooler than the smaller top plastic piece, because the energy that transferred to it was spread out over more molecules.

Explanation: I did the test


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A volume of 40.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2SO4). What was the molarity of the KOHKOH solution if 16.2 mLmL of 1.50 MM H2SO4H2SO4 was needed? The equation is 2KOH(aq)+H2SO4(aq)→K2SO4(aq)+2H2O(l)

Isopropyl methyl ether is slightly soluble with water because the oxygen atom of ethers with three or fewer carbon atoms can form a few hydrogen bonds with water.(A) True
(B) False

Answers

Isopropyl methyl ether is slightly soluble in water because the oxygen atom of ethers with 3 or lesser carbon atoms can form hydrogen bonds with water. Therefore, the given statement is true.

What is hydrogen bonding?

Hydrogen bonding is a special class of attractive intermolecular forces that arise because of the dipole-dipole interaction between hydrogen that is bonded to a highly electronegative atom and another highly electronegative atom that lies in the neighborhood of the hydrogen atom.

For example, in water, hydrogen is covalently bonded to the oxygen atom. Therefore, hydrogen bonding arises because of the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another water molecule.

The solubility of ether in water depends upon the extent of the formation of hydrogen bonds with water. Ether which contains three carbon atoms is soluble in water due to these lower hydrocarbon atoms can form hydrogen bonding with water.  

But the solubility of hydrocarbons or ethers decreases as increase the number of carbon atoms. This is because higher ethers or ethers with more carbons have more hydrophobic parts. Therefore they cannot be soluble in water as they cannot form hydrogen bonds with water molecules.

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Answer:

True

Hydrogen bond is a partial intermolecular bonding interaction between a lone pair on an electron rich donor atom, particularly the second-row elements nitrogen (N), oxygen (O), or fluorine (F), and the antibonding orbital of a bond between hydrogen (H) and a more

electronegative atom or group. Such an interacting system is generally denoted Dn–H···Ac, where the solid line denotes a polar covalent bond, and the dotted or dashed line indicates the hydrogen bond. The use of three centered dots for the hydrogen bond is specifically recommended by the IUPAC. While hydrogen bonding has both covalence and electrostatic contributions, and the degrees to which they contribute are currently debated, the present evidence strongly implies that the primary contribution is covelant.

Hydrogen bonds can be intermolecular (occurring between separate molecules) or

intramolecular (occurring among parts of the same molecule)

A sample of phosgene gas at an initial concentration of 0.500 m is heated at 527 °c in a reaction vessel. at equilibrium, the concentration of co (g) was found to be 0.046 m. calculate the equilibrium constant for the reaction at 527 °c.

Answers

Answer : The equilibrium constant will be - 0.454

Explanation : The reaction is given below;

COCl_(2)   \ \textless \ ----\ \textgreater \   CO + Cl_(2)

We  need to find Equilibrium constant - K_(c);

K_(c) = [CO] [Cl_(2)] / [COCl_(2) ]

So, K_(c) = [0.046] X [0.046] / [0.5 - 0.046] 

Therefore, K_(c) = 0.454

You have 0.500 L of an 0.250 M acetate buffer solution (i.e. [HC₂H₃O₂] + [C₂H₃O₂⁻] = 0.250 M) at pH 3.50. How many mL of 1.000 M NaOH must you add in order to change the pH to 5.07? Acetic acid has a pKa of 4.74.

Answers

Answer:

80mL of 1.00M NaOH

Explanation:

Using H-H equation, we can determine oH of a buffer as acetate buffer. First, we need to determine amount of acetate ion and acetic acid at pH 3.50 and 5.07. Then, with the reaction of NaOH with acetic acid we can find the amount of 1.00M NaOH that must be added:

At pH 3.50:

pH = pka + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

3.50 = 4.74 + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

0.057544 = [C₂H₃O₂⁻] / [HC₂H₃O₂] (1)

Using and replacing in (1):

[HC₂H₃O₂] + [C₂H₃O₂⁻] = 0.250 M

[HC₂H₃O₂] + 0.057544[HC₂H₃O₂] = 0.250 M

1.057544 [HC₂H₃O₂] = 0.250M

[HC₂H₃O₂] = 0.2364M * 0.500L = 0.1182 moles of acetic acid at first pH

At pH 5.07:

pH = pka + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

5.07 = 4.74 + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

2.13796= [C₂H₃O₂⁻] / [HC₂H₃O₂] (1)

Using and replacing in (1):

[HC₂H₃O₂] + 2.13796[HC₂H₃O₂] = 0.250 M

3.13796 [HC₂H₃O₂] = 0.250M

[HC₂H₃O₂] = 0.07967M * 0.500L = 0.0398 moles of acetic acid at first pH

Now, NaOH reacts with HC₂H₃O₂ as follows:

NaOH + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O

As moles of acetic acid decreases from 0,1198 moles - 0,0398 moles = 0,08 moles of acetic acid are consumed = 0,08 moles of NaOH

0,08 mol NaOH * (1L / 1mol) = 0,08L of 1.00M NaOH =

80mL of 1.00M NaOH

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressure of He would give a solubility of 0.730 M

Answers

We have that from the Question, it can be said that   The partial pressure of He would give a solubility of 0.730 M is

P_2=4.7atm

From the Question we are told

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressure of He would give a solubility of 0.730 M

Generally the equation for constant temperature  is mathematically given as

(C_2)/(C_1)=(P_2)/(P_1)\n\nTherefore\n\nP_2=(P_1C_1)/(C_1)\n\nP_2=(0.22*1.7)/(0.080)\n\nP_2=4.7atm\n\n

Therefore

The partial pressure of He would give a solubility of 0.730 M is

P_2=4.7atm

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Answer: Partial pressure of He that would give a solubility of 0.730 M is 15.5 atm

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_(He)=K_H* p_(liquid)

where,

K_H = Henry's constant =?

p_(He) = partial pressure = 1.7 atm

Putting values in above equation, we get:

0.080=K_H* 1.7atm\n\nK_H=0.047Matm^(-1)

To find partial pressure of He would give a solubility of 0.730 M

0.730=0.047Matm^(-1)* p_(liquid)

p_(liquid)=15.5atm

Thus partial pressure of He that would give a solubility of 0.730 M is 15.5 atm

Question 1Ernest Rutherford completed his famous gold foil experiment in 1911. In this experiment, alpha particles were fired at a thin sheet of gold foil. He observed that most of the alpha particles passed straight through the gold foil unimpeded, but a small number of alpha particles were deflected. Which of the following conclusions about atomic structure were made from Rutherford’s gold foil experiment?

Answers

The conclusions drawn by Ruthford after the experiment are that most of the atom is empty and that the nucleus of the atom is positively charged.

What is the atom?´

  • It is the particular mentor of the matter.
  • It is the element that makes up matter.

After the discovery of the atom, many scientists sought to understand this element more specifically, especially in relation to its composition. These discoveries were strengthened over time, and Rutherford was the one who established how the atom really is, with a positive charge in the nucleus and an electrosphere around it.

Complete question:

Ernest Rutherford completed his famous gold foil experiment in 1911. In this experiment, alpha particles were fired at a thin sheet of gold foil. He observed that most of the alpha particles passed straight through the gold foil unimpeded, but a small number of alpha particles were deflected. Which of the following conclusions about atomic structure were made from Rutherford’s gold foil experiment?

Most of the atom is empty.

The nucleus is positively charged.

The atom is a massive sphere.

The atom is indivisible.

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Answer: gold foil. It's in the experiment's name

What is the relationship between potential and kinetic energy?*As potential energy increases, kinetic energy increases.
O As potential energy increases, kinetic energy decreases.
As potential energy decreases, kinetic energy decreases.
O Potential and kinetic energy are two separate things and have no relationship.

Answers

Answer:

As potential energy increases, kinetic energy decreases

It's an inverse relationship

Final answer:

Potential energy and kinetic energy are related through the law of conservation of energy. When potential energy increases, kinetic energy decreases, and vice versa, as energy is simply converted between these two forms.

Explanation:

The relationship between kinetic energy and potential energy lies within the law of conservation of energy. This law states that energy cannot be created or destroyed, only converted from one form to another.

Potential energy is the energy stored in an object due to its position in a force field or due to its configuration. For example, when you lift a book off the ground, it gains potential energy because of the work done against the force of gravity.

On the other hand, kinetic energy is the energy of an object due to its motion. The same book, when dropped, loses potential energy and gains kinetic energy as it falls towards the ground.

Hence, when potential energy increases, kinetic energy decreases, and vice versa. This is because the total energy (potential + kinetic) must be conserved, assuming no energy is lost to other forms like heat or sound.

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