One number is 3 more than 3 times another. The sum of the numbers is 19. Find the two numbers.The two numbers are


Answer 1


number x

y = 3x +3

sum = x + y

19 = x + 3x + 3

19 = 4x + 3

19- 3 = 4x

16 = 4x

16/4 = x

x = 4

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The graph below represents a rock climbers height as she acends a hill. Part A- The above graph is (circle one) linear/ nonlinear. Part B- Is the above graph a function? Explain.​



Part A: its linear

Part B: it is a function

Step-by-step explanation:

Is the opposite of an opposite number always going to be positive?


No, the opposite of an opposite will not always be positive. the opposite of -4 is 4, and the opposite of that is -4, so the opposite of the opposite of the number -4 is -4, which is not positive. On the other hand, it CAN be positive. The opposite of 7 is -7, and opposite of that is 7, which is positive.
yes it is because if you reflect for a min, the opposite (which is a negative) of the opposite is always going to be a positive.

Mayumi plans to buy pencils and a notebook at the school store. A pencil costs $0.15, and a The notebook costs $1.59. Mayumi has $5.00. Which inequality could she use to find the number of pencils she can buy? in equation please ​


Answer: 0.15p+1.59n ≤ 5.00

Step-by-step explanation:

Given: A pencil costs $0.15, and a The notebook costs $1.59.

Let p = Number of pencils.

n = Number of notebooks.

Total cost of pencil and notebook = 0.15p+1.59n

Since Mayumi has $5.00.

So, Total cost of pencil and notebook ≤ $5.00

⇒ 0.15p+1.59n ≤ 5.00

Hence, the required inequality: 0.15p+1.59n ≤ 5.00

Need help please ASAP ! The options for the first blank is A.close price C.volume the options for second blank is B.month



Find two unit vectors orthogonal to both given vectors. i j k, 4i k


The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)*(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\n1&1&1\n4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

(\mathbf v)/(\|\mathbf v\|)=(\vec i+3\,\vec j-4\,\vec k)/(√(1^2+3^2+(-4)^2))=\frac1{√(26)}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.

In what order must you preform the operations indicated by a negative rational exponent?


The operations referred to are likely

• raising to a power (the numerator of the exponent)

• taking a root (the denominator of the exponent)

• finding a reciprocal (because the exponent is negative)

They can be performed in any convenient order. It often works well to deal with small positive integers, so if one or more of these operations lets you proceed with a small positive integer for the remaining operations, that would be the one you'd perform first.


A computer performing operations with a negative rational exponent may do so using logarithms. That is, the log of the base will be multiplied by the exponent, then the antilog found. The exponent itself will likely be treated as a floating point number, unless coding specifically indicates otherwise.