Answer:

**Answer:**

The probability of this event is represented by a value of 1.

**Step-by-step explanation:**

**Probability of a certain event:**

The probability of an event that is considered to be certain, that is, guaranteed to happen, is 100% = 1.

**You are certain to get a heart, diamond, club, or spade when selecting cards from a shuffled deck.**

This means that the probability of this event is represented by a value of 1.

The quality control manager at a light bulb manufacturing company needs to estimate the mean life of the light bulbs produced at the factory. The life of the bulbs is known to be normally distributed with a standard deviation (sigma) of 80 hours. A random sample of 16 light bulbs indicated a sample mean life of 1000 hours. What is a 95% confidence interval estimate (CIE) of the true mean life (m) of light bulbs produced in this factory

23 greater than b is at least -276

Divide write the quotient in lowest term 1 1/3 divided by 1 3/4

Find cardinality of set BB = {∅, {1}, {1, 2}, {1, 2,3}, · · · , {1, 2, · · · , m}}

(2x - y + 3) (2x - y - 3)using identities

23 greater than b is at least -276

Divide write the quotient in lowest term 1 1/3 divided by 1 3/4

Find cardinality of set BB = {∅, {1}, {1, 2}, {1, 2,3}, · · · , {1, 2, · · · , m}}

(2x - y + 3) (2x - y - 3)using identities

Bufhenjseuhrcubyfbtbvyx-p

Answer:

P2 affirms P1 and the conclusion is in the same direction.

P1--->P2--->C

This argument is valid.

Step-by-step explanation: using the syllogism rules.

Premises 1 (P1) = Some foreign emissaries are persons without diplomatic immunity,

Premises 2 (P2) = so some persons invulnerable to arrest and prosecution are foreign emissaries

Conclusion (C) = because no persons with diplomatic immunity are persons vulnerable to arrest and prosecution.

From the argument:

P1 uses "some", that means it's not "all" foreign emissaries person that does not have diplomatic immunity. This means that some other foreign emissaries have diplomatic immunity

P2 uses "some", that means it's affirms to that part of P1 which states that some foreign emissaries have diplomatic immunity.

The conclusion is valid because the part of P2 which states that some foreign emissaries are vulnerable to arrest, which affirms with P1 which states that Some foreign emissaries are persons without diplomatic immunity. That means no persons with diplomatic immunity are persons vulnerable to arrest and prosecution. This conclusion literally means that if you don't have diplomatic immunity, you are vulnerable to arrest and prosecution.

Therefore;

P2 affirms P1 and the conclusion is in the same direction.

P1--->P2--->C

This argument is valid.

**ANSWER:**

The value of x is 25

**STEP-BY-STEP EXPLANATION:**

We can calculate the value of x by means of the Pythagorean theorem that says the following:

replacing:

3.5 is 3 and one half

Fun fact

Banana

Fun fact

Banana

**Answer:**

3.5

**Step-by-step explanation:**

im a sophmore and i know this

please help

**Answer**

5-n

**Step-by-step explanation:**

**Answer:**

a. 248.14

b. 220.576

**Step-by-step explanation:**

The weighted mean can be calculated as

Xbarw= sumwx/sumw

where x are the observations and w are the weights of the observations.

a.

x w wx

248.13 3 744.39

248.06 1 248.06

248.18 2 496.36

248.15 3 744.45

sumwx=744.39+248.06+496.36+744.45=2233.26

sumw=3+1+2+3=9

Xbarw= sumwx/sumw

Xbarw= 2233.26/9

Xbarw= 248.14

The weighted mean for line BC is **248.14.**

b.

x w wx

248.13 1 248.13

248.06 1 248.06

248.18 3 744.54

248.15 3 744.45

sumwx=248.13+248.06+744.54+744.45=1985.18

sumw=3+1+2+3=9

Xbarw= sumwx/sumw

Xbarw= 1985.18/9

Xbarw= 220.576

The weighted mean for line BC is **220.576.**

The weighted mean of line BC for the first given weights is 248.13. The weighted mean for the revised weights is 248.14.

The weighted mean of a set of values is calculated by multiplying each value by its weight, summing those products, and then dividing the sum by the total of the weights. So we will first multiply each distance by its corresponding weight then add them all up and divide it by the sum of weights. Let's calculate.

- For the first case, the weights given are 3, 1, 2, and 3. The weighted mean of BC can be computed as ((248.13*3)+(248.06*1)+(248.18*2)+(248.15*3)) / (3+1+2+3), which equals
**248.13**. - For the second case, the weights are revised as 1, 1, 3, and 3. The weighted mean of BC in this case is ((248.13*1)+(248.06*1)+(248.18*3)+(248.15*3)) / (1+1+3+3), which gives
**248.14**.

#SPJ3