PLEASE ANSWER ASAP!!! FULL ANSWERS ONLY!!!!!! WILL GIVE BRAINLIEST!!!!!!!!! Two cyclists, 68 miles apart, start riding toward each other at the same time. One cycles 3 miles per hour faster than the other, and they meet after 4 hours of riding.

a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r to represent the speed of the slower cyclist.

b. What are the speeds of the two cyclists? _______________

Answers

Answer 1
Answer:

a) The given equation using the information as it is given above that can be solved to answer this problem is 4r + 4(r+3) = 68

b) The speed of both cyclists are 3mi/hr and 10mi/hr respectively

The formula for calculating the distance covered is expressed as:

Distance = speed * time

Let the speed covered by one cyclist be t

If one cycles 3 miles per hour faster than the other, the speed of the other will be t + 3

If both meet after 4 hours of riding, then their time will be 4 hours

Distance covered the first cyclist = 4r

Distance covered by the second = 4(r+3)

If the two cyclists are 68 miles apart, then:

4r + 4(r+3) = 68

a) The given equation using the information as it is given above that can be solved to answer this problem is 4r + 4(r+3) = 68

b) Expand the equation in a to get "r"

4r + 4r + 12 = 68

8r + 12 = 68

8r = 68 - 12

8r = 56

r = 56/8

r = 7miles per hour

Speed of the first cyclist = 7mi/hr

Speed of the second cyclist = 3 + 7mi/hr = 10mi/hr

Hence the speed of both cyclists are 3mi/hr and 10mi/hr respectively

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Answer 2
Answer:

Answer:

4r + 4(r + 3) = 68

r = 7 miles per hour

r + 3 = 10 miles per hour

Step-by-step explanation:

distance = rate * time

a)

4r + 4(r + 3) = 68

Distribute

4r + 4r + 12 = 68

8r + 12 = 68

8r = 56

r = 7 miles per hour

r + 3 = 10 miles per hour


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The linear equation of the initial (red ) incline would be y = __x +__

Find the length of the curve. R(t) = 2 i + t2 j + t3 k, 0 ≤ t ≤ 1

Answers

Length of a curve is the length of its plot its curve. The length of the given curve for given range of t is: L = 1.44 units approx.

How to find the length of a curve?

If the curve has position vector p(x) for value of x ranging from x = a to x = b,

then, the curve's length is calculated as:

L = \int_a^b ||p'(x)||dx\n units.

For the given case, we have:

Position vector =  R(t) = 2\hat i + t^2 \hat j + t^3 \hat k

Its differentiation gives:

R'(t) = 2t\hat j + 3t^2\hat k

Its non negative magnitude is: ||R'(t)|| = √((2t)^2 + (3t^2)^2) = t√(4+9t^2)

Thus, as t ranges from a = 0 to b = 1, thus, length of the curve is:

L = \int_0^1 (t√(4+9t^2))dt\n\n\text{Let v = 4+9}t^2, \text{then dv = 18tdt}\nand\nt=0\implies v = 4\nt=1 \implies v = 13\nThus,\nL = \int_4^(13)((√(v))/(18))dv = (1)/(18) [(2(v)^(3/2))/(3)]^(13)_4 \approx (38.87)/(27) \approx 1.44 \: \rm units

Thus,

The length of the given curve for given range of t is: L = 1.44 units approx.

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brainly.com/question/4464059

curve equation is

\n \vec{R}\left ( t \right ) = 2\hat{i}+t^(2)\hat{j} + t^(3)\hat{k}  ,0≤ t≤ 1

now taking the differentiation

\n{R}'t = 2t\hat{i} + 3t^(2)\hat{j}

now taking the modulus

\left \| {R}'(t) \right \|=\sqrt{4t^(2) +9t^(4)}

                                      = \sqrt{4 + 9 t^(2) } .t

now taking the integration

length of the curve =   \n\int t\sqrt{4 + 9 t^(2)} dt\n

now put the value v=  4 + 9t²

                              dv= 18 tdt

now put this value in the above equation

we get

length of the curve =\n(1)/(18)\int √(v)dv\n

now taking integation we get and put the value of the v

we get

= (1)/(18)× (2)/(3)×(4 + 9t^(2) )^{(3)/(2) }

= (1)/(27) ( 4 + 9 t^(2) )^{(3)/(2) }

now find out the length of the curve in the interval from 0 to 1.

length of the curve = (1)/(27) (13^{(3)/(2)} -4^{(3)/(2)} )\n=(1)/(27) (13√(13) -8)

Hence proved

How do I find the x and the y

Answers

Answer:

x = 22

y = 35

Step-by-step explanation:

Because its an isosceles triangle, you know the base angles are equal so:

3x - 11 = 2x + 11

Solving:

subtract 2x from both sides

x-11=11

add 11 to both sides

x = 22

Next, find the angle measures of the two base angles:

3*22-11\n66-11\n55

To find y, you know that the interior angles of the whole triangle add up to 180, so you have

55 + 55 + 2y = 180

solving,

110 + 2y = 180

subtract 110 from both sides

2y = 70

divide both sides by 2

y = 35

Answer:

x =22°

y =35°

Step-by-step explanation:

3x-11 = 2x+11

then x =22°

and 2y = 180-(55+55)

2y = 70

y = 45°

If each of the numbers in the following data set were multiplied by 22, what would be the new median of the data set? 14, 20, 18, 58, 71, 36

Answers

The new median of the data set will be 616.

What is Multiplication?

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

The data set is,

⇒ 14, 20, 18, 58, 71, 36

Now,

Since, The data set is,

⇒ 14, 20, 18, 58, 71, 36

Multiply by 22 in each number , we get;

⇒ 14 × 22, 20 × 22, 18 × 22, 58 × 22, 71 × 22, 36 × 22

⇒ 308, 440, 396, 1276, 1562, 792

Arrange the number is ascending order we get;

⇒ 308, 396, 440, 792, 1276, 1562

So, The median of data set = (440 + 792) / 2

                                          = 1232/2

                                          = 616

Thus, The new median of data set = 616

Learn more about the median visit:|

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Answer:

If each of the numbers in the following data set were multiplied by 31, what would be the median of the data set?

28, 58, 20, 14, 18, 71, 36

A. 558

B. 1116

C. 434

D. 868

answer

D.868

Need help...,.......

Answers

\large\begin{array}{I} \mathtt{ ( √(9x^2))/( √(18y^2))= (3x)/( 3√(2)y)= (x)/( √(2)y)}= ( √(2)x)/(2y) \end{array}

Answer is A
A. 3x /3ysqrtof2. Multiply numerator and denominator by sqrt of 2
Then you have 3xsqrt of 2 /. 6y reduce by 3 both numerator and denominator
You have x sqrt of 2 / 2y

A shipping container will be used to transport several 60-kilogram crates across the country by rail. The greatest weight that can be loaded into the container is 26000 kilograms. Other shipments weighing 13200 kilograms have already been loaded into the container. What is the greatest number of 60-kilogram crates that can be loaded into the shipping container?

Answers

Answer:

213 crates

Step-by-step explanation:

There is enough space for 26000 kg - 13200 kg = 12800 kg. Divide this by 60 and you get 213 and 1/3. You cannot put 1/3 of a crate, so it is 213 crates.

Which equations have a value less than 6,766?A. one fourth x 6,766 = ________

B. 6 x 6,766 = ________

C. one half x 6,766 = ________

D. 1 x 6,766 = ________

A and C
D and B
A and B
C and D
please help giving brainlyest

Answers

A and C are the correct answers.

I hope this helps.

A and C I Think......