Answer:

**Answer:**

m_cable = 2,676 kg

**Explanation:**

For this exercise we must look for the acceleration with the kinematic ce relations

v² = v₀² + 2 a x

since the block starts from rest, its initial velocity is vo = 0

a = v² / 2x

a = 4.2² /(2 2.0)

a = 4.41 m / s²

now we can use Newton's second law

Note that the mass that the extreme force has to drag is the mass of the block plus the mass of the cable.

F = (m + m_cable) a

m_cable = F / a -m

m_cable = 100 / 4.41 - 20

m_cable = 2,676 kg

Answer:
### Final answer:

### Explanation:

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Unfortunately, the information given does not provide enough data to determine the mass of the **steel cable**. This is because the force, acceleration, and distance information given only involve the mass of the block, not the cable.

The question is requesting the mass of the steel cable. However, given the information in the question, we don't actually have **enough data** to determine this. The application of the force, the acceleration of the block, and the distance it covers are all connected through **Newton's second law** (F = ma) and the equations of motion, but these only involve the mass of the block, not the mass of the cable. Even if we assumed the cable applies the entire 100 N force to the block, this would only allow us to solve for the acceleration of the block, not the mass of the cable. Therefore, the mass of the steel cable cannot be determined with the **information** provided in the question.

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The _______ principle encourages us to resolve a set of stimuli, such as trees across a ridgeline, into smoothly flowing patternsA.) depth perception. B.) perception. C.) similarity. D.) continuity.

The position of a particular particle as a function of is given by r=(8.5t i+5.6j-2tk )m (a) Determine the particle’s velocity and acceleration as a function of time.(b) Find the instantaneous velocity and acceleration of the particle at t=3.0 s.

What is the average velocity if the initial velocity is at rest and the final velocity is 16 m/s

A 50.0-kg box is being pulled along a horizontal surface by means of a rope that exerts a force of 250 n at an angle of 32.0° above the horizontal. the coefficient of kinetic friction between the box and the surface is 0.350. what is the acceleration of the box?

One of two nonconducting spherical shells of radius a carries a charge Q uniformly distributed over its surface, the other carries a charge -Q, also uniformly distributed. The spheres are brought together until they touch.A.) What does the electric field look like, both outside and inside the shells?B.) How much work is needed to move them far apart?

The position of a particular particle as a function of is given by r=(8.5t i+5.6j-2tk )m (a) Determine the particle’s velocity and acceleration as a function of time.(b) Find the instantaneous velocity and acceleration of the particle at t=3.0 s.

What is the average velocity if the initial velocity is at rest and the final velocity is 16 m/s

A 50.0-kg box is being pulled along a horizontal surface by means of a rope that exerts a force of 250 n at an angle of 32.0° above the horizontal. the coefficient of kinetic friction between the box and the surface is 0.350. what is the acceleration of the box?

One of two nonconducting spherical shells of radius a carries a charge Q uniformly distributed over its surface, the other carries a charge -Q, also uniformly distributed. The spheres are brought together until they touch.A.) What does the electric field look like, both outside and inside the shells?B.) How much work is needed to move them far apart?

**Answer:**

**Explanation:**

Given that,

Vector A points in the -x direction with a magnitude of 21.

Let the x component is making an angle of 60 degrees with negative x axis. The x component of a vector is given by :

A = -42 units

The y component of a vector is given by :

**So, the y component of vector A is (-36.37) degrees. Hence, this is the required solution.**

30 m

30 in

What is Greta's average velocity over the 240s period?

m/s

What is Greta's average speed over the 240s period?

m/s

**Average velocity**: 0 m/s. Average speed: 0.25 m/s. Greta returns to her starting point, so her displacement is 0m.

Greta's average velocity is 0 m/s because she ends up at the same point where she started. Her **displacement** is 0 meters, and since velocity is displacement divided by time, her average velocity is 0 / 240 = 0 m/s.

Her average speed, on the other hand, is calculated using the formula: Average Speed = **Total****Distance** / Total Time.

Initially, Greta walks 30 meters away from her truck, and then she returns 30 meters back to her starting point. So, the total distance she covers is 30 + 30 = 60 meters. Her total travel time is 240 seconds.

**Average****Speed** = 60 meters / 240 seconds = 0.25 m/s.

In summary, Greta's average velocity is 0 m/s because her net displacement is 0 meters. Her average speed is 0.25 m/s because she covers a total distance of 60 meters in 240 seconds.

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**Answer:**

**0** | for Velocity

**.25** | for speed

**Explanation:**

Rewrite the amounts as improper fractions:

9 2/3 = 29/3

3 7/8 = 31/8

Rewrite both fractions with a common denominator

29/3 = 232/24

31/8 = 93/24

Now subtract: 232/24 - 93/24 = 139/24

Rewrite as a proper fraction: 5 19/24

Answer 5 19/24

Light has **wavelength** 600 nm in a vacuum ,the **frequency** of the light is 2 × Hz.

The separation between such a wave motion's crests and troughs would be known as the **wavelength **of photons.

The total number of waves that pass a specific location in a predetermined amount of time is known as **frequency**.

Calculation of **frequency**

Given data:

**wavelength** = 600 nm = 600 × m

index of refraction = 1.5.

**Frequency **can be calculated by using the formula:

v = f × **wavelength**

f = wavelength / v

Where, f = **Frequency** , v is velocity.

put the given data in above equation.

f = **wavelength** / v

f = 600 × m / 3 ×

f = 200 × .

f = 2 ×

Therefore, the **frequency** of the light is 2 × Hz.

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v = f lambda

in vac ... 3X10^8 = 600x10^-9xf

in glass speed slower, poss 2/3 that of vacuum

C) The distance between the minima stays the same.

D) The distance between the minima increases.

E) The distance between the maxima increases.

**Answer:**

The correct statements are D and E.

**Explanation:**

The fringe width is given by the following formula as :

Here,

is wavelength of light

D is distance between slit and the screen

d is slit width.

**If the between these slits is decreased, the fringe width increases. As a result, the distance between the minima increases and also the distance between the maxima increases.**

**Answer:**

**σ = 0.8 N/m**

**Explanation:**

Given that

L = 12 cm

We know that 1 m = 100 cm

L = 0.12 m

The force ,F= 0.096 N

Lets take surface tension = σ

We know that surface tension is given as

Therefore the surface tension σ will be 0.8 N/m .

**σ = 0.8 N/m**

The **surface tension **of the liquid in air is 0.8 N/m.

To determine the surface tension of the liquid, we need to use the formula F = yL, where F is the force needed to move the wire, y is the surface tension, and L is the length of the wire. In this case, F = 0.096 N and L = 12 cm. We can rearrange the formula to solve for y: y = F / L. Plugging in the values, we get y = 0.096 N / 0.12 m = 0.8 N/m. So, the surface tension of the **liquid **in air is 0.8 N/m.

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