Answer:
26,500 * .25 = 6625

26,500 - 6625 = $19875 ---------> Price after 1 year

Price after 2 years:

19875 * .25 = 4968.75

19875 - 4968.75 = $14,906.3 ---------> Price after 2 years

Price after 3 years:

14,906.3 * .25 = 3726.58

14,906.3 - 3725.58 = $11,179.7 ----------> Price after 3 years

Price after 4 years:

11,179.7 * .25 = 2794.93

11,179.7 - 2794.93 = $8384.77 ------> Price after 4 years, rounded to the nearest dollar = $8385

26,500 - 6625 = $19875 ---------> Price after 1 year

Price after 2 years:

19875 * .25 = 4968.75

19875 - 4968.75 = $14,906.3 ---------> Price after 2 years

Price after 3 years:

14,906.3 * .25 = 3726.58

14,906.3 - 3725.58 = $11,179.7 ----------> Price after 3 years

Price after 4 years:

11,179.7 * .25 = 2794.93

11,179.7 - 2794.93 = $8384.77 ------> Price after 4 years, rounded to the nearest dollar = $8385

Answer:
26,000 * 35% = 910. So $910 would be subtracted from 26,000 for each year

Please help ASAP! Thank you!

Help me with this this is confusing give me the answer

Mr. Gordon has 13 girls and 14 boys in his fourth period algebra class. One person is chosen at random.What is the probability that the person chosen is a boy?A. 1/14 B. 1/27C. 13/14D. 13/27E. 14/27

Enter the symbol (<, >, or =) that correctly completes this comparison.0.147 0 0.174

Deanna and Lise are playing game at the arcade. Deanna started with $20 and the the game she is playing costs $0.25 each game. Lise started with $40, and her machine costs $0.75 per game. How many games will it be before they both have the same amount of money left? Make an expression the solves the problem.

Help me with this this is confusing give me the answer

Mr. Gordon has 13 girls and 14 boys in his fourth period algebra class. One person is chosen at random.What is the probability that the person chosen is a boy?A. 1/14 B. 1/27C. 13/14D. 13/27E. 14/27

Enter the symbol (<, >, or =) that correctly completes this comparison.0.147 0 0.174

Deanna and Lise are playing game at the arcade. Deanna started with $20 and the the game she is playing costs $0.25 each game. Lise started with $40, and her machine costs $0.75 per game. How many games will it be before they both have the same amount of money left? Make an expression the solves the problem.

a. If the sample variance is s^2=32 , are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha=.05

b. If the sample variance is s^2=72 , are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha=.05 ?

c. Comparing your answer for parts a and b, how does the variability of the scores in the sample influence the outcome of a hypothesis test?

A hypothesis test was conducted to evaluate the treatment's effect. For both variances, we failed to reject the null hypothesis, so we can't conclude that the treatment had a significant effect. The variability of scores plays a crucial role, as more variability makes it harder to identify a significant effect.

To determine if the treatment has a significant effect, we perform a **hypothesis test** using the **sample mean** (M), **sample variance** (s^2), and **population mean** (μ). The null hypothesis is that there's no effect from the treatment (μ=M), while the alternative hypothesis is that there is an effect (μ≠M).

a. For sample variance s^2=32, we can use the formula for the t score: t = (M - μ)/(s/√n) = (35 - 40)/(√32/√8) = -2.24. Based on a two-tailed t-distribution table, the critical t values for α=.05 and 7 degrees of freedom (n-1) are approximately -2.365 and 2.365. Our t value (-2.24) lies within this range, so we fail to reject the null hypothesis. We cannot conclude that the treatment has a significant effect.

b. Repeat the same process with sample variance s^2=72. The t value is now (35 - 40)/(√72/√8) = -1.48, again falling within the range of the critical t values. We can't conclude that the treatment has a significant effect.

c. As the variability (s^2) of the **sample scores** increases, it becomes more difficult to find a significant effect. Higher variability introduces more uncertainty, which can mask actual changes caused by the treatment.

#SPJ12

To evaluate the effect of a treatment using a **two-tailed **test with alpha = 0.05, we compare the calculated t-value to the critical t-value. The sample variance influences the outcome of the hypothesis test, with a larger variance leading to a wider critical region.

a. To test if the treatment has a significant effect, we will conduct a two-tailed hypothesis test using the t-distribution. The null hypothesis states that the treatment has no effect (μ = 40), while the alternative hypothesis states that the treatment has an effect (μ ≠ 40). With a **sample** size of 8, degrees of freedom (df) will be n-1 = 7. We will use the t-test formula to calculate the t-value, and compare it to the critical t-value from the t-table with α = 0.05/2 = 0.025. If the calculated t-value falls outside the critical region, we reject the null hypothesis and conclude that the treatment has a significant effect.

b. Similar to part a, we will conduct a two-tailed t-test using the same null and alternative hypotheses. With a sample size of 8, df = n-1 = 7. We will calculate the t-value using the sample mean, population mean, and sample variance. Comparing the calculated t-value to the critical t-value with α = 0.05/2 = 0.025, if the calculated t-value falls outside the critical region, we reject the null hypothesis and conclude that the treatment has a significant effect.

c. The variability of the scores in the sample, as indicated by the sample variance, influences the outcome of the hypothesis test. In both parts a and b, the sample variance is given. A larger sample variance (s^2 = 72 in part b) indicates more variability in the data, meaning the scores in the sample are more spread out. This leads to a larger t-value and a wider **critical** region. Therefore, it becomes easier to reject the null hypothesis and conclude that the treatment has a significant effect.

#SPJ11

Vegan 85.00 5.20 1.08

Omnivore 91.00 5.65 1.10

Calculate a 99% CI for the difference between the population mean total cholesterol level for vegans and population mean total cholesterol level for omnivores. (Use μvegan−μomnivore). Round to three decimal places.)

Interpret the interval.

a. We are 99% confident that the true average cholesterol level for vegans is less than that of omnivores by an amount within the confidence interval.

b. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount within the confidence interval.

c. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount outside the confidence interval.

d. We cannot draw a conclusion from the given information.

Answer: hey

Step-by-step explanation:

**Answer:**

Therefore, the solution is:

**Step-by-step explanation:**

We calculate the given integral. We use the substitution t = 7x.

Therefore, the solution is:

13

4x+1

2x+y

8x-2y

Enter the number that belongs in

the green box

Enter

**Answer:**

x = 3

**Step-by-step explanation:**

If the triangles are congruent then

4x + 1 = 13

4x = 12

**x = 3**

Eight times the **difference **of y and nine will be **8(y - 9).**

It should be noted that eight times the** difference **of y and nine simply means that one has to** subtract **9 from y and then **multiply **the difference by 8.

Therefore, eight times the** difference **of y and nine will be **8(y - 9).**

In conclusion, the correct option is **8(y - 9).**

Read related link on:

**Answer:**

(y-9)8

**Step-by-step explanation:**

you first solve 8-9, and then multiply is by 8.

**Answer:**

Hi

**Step-by-step explanation:**

Good bye. ;) (Stranger-Danger!) :)