Modify methionine, below to show its zwitterion form. How do I make Methionine into a zwitterion?

Answers

Answer 1
Answer:

Explanation :

Zwitter ion : An ion or molecule having separate negatively and positively charged groups.

Methionine is an amino acid with sulfur atom in its molecule .The proton from carboxylic group with get attached to amino group present in the methionine and negative charge will be generated on oxygen atom of a carboxylic group which will get in conjugation with an another oxygen atom of the carboxylic group.

The positive charge will generated on the nitrogen atom due  attachment of the proton from the carboxylic group.

As shown in the image attached.



Answer 2
Answer: Methionine is an amino acid and like some amino acid, it has a zwitterion form. A zwitterion form is a form of molecule showing separate positive and negative charges. The hydrogen from the carboxylic acid group will transfer to the amino group producing a negative charge at the carboxyl group and a positive charge at the amino group.

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Ascorbic acid (vitaminc.Does not contain a traditional carboxylic acid group, but it is, nevertheless, still fairly acidic (pka = 4.2). Identify the acidic proton and explain your choice using resonance structures, if necessary:

Answers

Let us see the structure of ascorbic acid


As shown there is no COOH group however the OH group can lose a proton and forms conjugate base

The conjugate base formed is stabilized due to resonance

More the stability of conjugate base more the strength of acid

Hence ascorbic acid behaves as an acid

15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.60 atm. What is the new volume in liters

Answers

Answer:

V_2=11.6L

Explanation:

Hello!

In this case, since we volume, pressure and temperature which are all changing, we can use the combined ideal gas law to write:

(P_1V_1)/(T_1) =(P_2V_2)/(T_2)

Thus, since the final volume V2 is required, by solving for it, we write:

V_2=(P_1V_1T_2)/(T_1P_2)

In such a way, we plug in the given data to obtain:

V_2=(3.36atm*15.0L*383K)/(298K*5.60atm)\n\nV_2=11.6L

Which means that the process compressed the gas.

Best regards.

Final answer:

To find the new volume, we can use the combined gas law equation.

Explanation:

To solve this problem, you can use the combined gas law equation, which relates the initial and final conditions of pressure, volume, and temperature.

The combined gas law equation is: P1 * V1 / T1 = P2 * V2 / T2

Substituting the given values into the equation, we can solve for the new volume:

(3.36 atm * 15.0 L) / 298 K = (5.60 atm * V2) / 383 K

Simplifying and solving for V2, the new volume, we find V2 = 11.78 L.

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Approximately what mass of 90sr (ti / 2 = 28.8 yr.) has the same activity as 1 g of 60co (ti / 2 = 5.26 yr.)?

Answers

Activity (A) of an element is related to the number of atoms of that element N as follows:

A = k*N --------(1)

k = rate constant = 0.693/t1/2--------(2)

N = # moles of that element * Avogadro's number Na

For Sr: t1/2 = 28.8 yr

A(Sr) = 0.693/28.8 * N(Sr) = 0.0241 * N(Sr)

A(Sr) = 0.0241*(mass Sr/90)*Na= 0.000268 *mass Sr *Na ------------(3)

For Co : t1/2 = 5.26 yr

A(Co) = 0.693/5.26 *N(Co) = 0.1317 *N(Co)

A(Co) = 0.1317 * (1/60)*Na = 0.00219 * Na -------(4)

It is given that:

A(Sr) = A(Co)

0.000268 *mass Sr *Na = 0.00219 * Na

mass Sr = 0.00219/0.000268 = 8.17 g


Write the full ionic equation and net ionic equation for sodium dihydrogen phosphate + calcium carbonate, sodium oxilate + calclium carbonate, and sodium hydrogen phosphate + calcium carbonate

Answers

Answer:

Sodium dihydrogen phosphate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + 2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

Net ionic equation

2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

Sodium oxalate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + C₂O₄²⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + CaC₂O₄(s)

Net ionic equation

C₂O₄²⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + CaC₂O₄(s)

Sodium hydrogen phosphate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + 2 Na⁺(aq) + CO₃²⁻(aq)

Net ionic equation

HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + CO₃²⁻(aq)

Explanation:

Let's consider two kind of equations:

  • Full ionic equation: includes all ions and species that do not dissociate in water.
  • Net ionic equation: includes only ions that participate in the reaction (not spectator ions) and species that do not dissociate in water.

Which particle is negatively charged?A. proton
B. atom
C. neutron
D. electron

Answers

Answer:

D. electron

Explanation:

Electrons have a negative charge

To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN?

Answers

Answer:

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

Explanation:

Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.

In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a solution it is fulfilled:

Ci* Vi = Cf* Vf

where:

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

In this case:

  • Ci= 1.40 M
  • Vi= 20 mL
  • Cf= 0.088 M
  • Vf= ?

Replacing:

1.40 M* 20 mL= 0.088 M* Vf

Solving:

Vf=(1.40 M* 20 mL)/(0.088 M)

Vf= 318.18 mL

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

Final answer:

To make a 0.0880 M solution of LiCN, you would need to dilute 20.0 mL of the 1.40 M solution to a final volume of 318.18 mL.

Explanation:

To dilute a solution, you can use the formula:

M1V1 = M2V2

where M1 and V1 are the initial molarity and volume, and M2 and V2 are the final molarity and volume. Rearranging the formula, we can solve for V2:

V2 = (M1 · V1) / M2

Plugging in the values given:

V2 = (1.40 M · 20.0 mL) / 0.0880 M = 318.18 mL

To make a 0.0880 M solution of LiCN, you would need to dilute 20.0 mL of the 1.40 M solution to a final volume of 318.18 mL.

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