Answer:

**Answer:**

please give me brainlist and follow

**Explanation:**

Whilst first impressions can be important, your body language during the interview can make or break your overall performance. With experts saying that between 75-90% of communication is non-verbal, it is important to think about what your body is saying about you during an interview.

A hot-air balloon is descending at a rate of 2.3 m>s when a pas- senger drops a camera. If the camera is 41 m above the ground when it is dropped, (a) how much time does it take for the cam- era to reach the ground, and (b) what is its velocity just before it lands? Let upward be the positive direction for this problem.

A 0.26-kg stone is held 1.2 m above the top edge of a water well and then dropped into it. The well has a depth of 4.5 m. (a) Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone−Earth system before the stone is released?

Neptunium. In the fall of 2002, scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237 is about 60 kg. The critical mass of a fissionable material is the minimum amount that must be brought together to start a nuclear chain reaction. Neptunium-237 has a density of 19.5 g/cm3. What would be the radius of a sphere of this material that has a critical mass?

Given a double slit apparatus with slit distance 1 mm, what is the theoretical maximum number of bright spots that I would see when I shine light with a wavelength 400 nm on the slits

Assume: The bullet penetrates into the block and stops due to its friction with the block. The compound system of the block plus the bullet rises to a height of 0.13 m along a circular arc with a 0.23 m radius. Assume: The entire track is frictionless. A bullet with a m1 = 30 g mass is fired horizontally into a block of wood with m2 = 4.2 kg mass. The acceleration of gravity is 9.8 m/s2 . Calculate the total energy of the composite system at any time after the collision. Answer in units of J. Taking the same parameter values as those in Part 1, determine the initial velocity of the bullet. Answer in units of m/s.

A 0.26-kg stone is held 1.2 m above the top edge of a water well and then dropped into it. The well has a depth of 4.5 m. (a) Relative to the configuration with the stone at the top edge of the well, what is the gravitational potential energy of the stone−Earth system before the stone is released?

Neptunium. In the fall of 2002, scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237 is about 60 kg. The critical mass of a fissionable material is the minimum amount that must be brought together to start a nuclear chain reaction. Neptunium-237 has a density of 19.5 g/cm3. What would be the radius of a sphere of this material that has a critical mass?

Given a double slit apparatus with slit distance 1 mm, what is the theoretical maximum number of bright spots that I would see when I shine light with a wavelength 400 nm on the slits

Assume: The bullet penetrates into the block and stops due to its friction with the block. The compound system of the block plus the bullet rises to a height of 0.13 m along a circular arc with a 0.23 m radius. Assume: The entire track is frictionless. A bullet with a m1 = 30 g mass is fired horizontally into a block of wood with m2 = 4.2 kg mass. The acceleration of gravity is 9.8 m/s2 . Calculate the total energy of the composite system at any time after the collision. Answer in units of J. Taking the same parameter values as those in Part 1, determine the initial velocity of the bullet. Answer in units of m/s.

**Answer:**

**Explanation:**

Energy falling on 1 m² surface of earth per second = 1050

Energy in one million years on 1 m²

= 1050 x 60 x 60 x 24 x 365 x 10⁶ = 3.311 x 10¹⁶ J

In order to calculate total energy coming out of the surface of the sun , we shall have to sum up this energy for the while spherical surface of imaginary sphere having radius equal to distance between sun and earth.

Area of this surface = 4π R² = 4 X 3.14 X (149.6 X 10⁹ )²

= 2.8 X 10²³ m²

So total energy coming out of the sun = 2.8 x 10²³ x 3.311 x 10¹⁶

= 9.271 x 10³⁹ J

From the formula

E = mc² { energy mass equivalence formula }

m = E / c² =

1.03 x 10²³ kg

mass of earth = 5.972 x 10²⁴

Answer in percentage of mass of earth

=

= 1.72 %

**Answer:**

A neap tide. Hope this helps

**Explanation:**

**Answer:**

**Explanation:**

a)

d = separation of the slits = 0.30 mm = 0.30 x 10⁻³ m

λ = wavelength of the light = 496 nm = 496 x 10⁻⁹ m

n = order of the bright fringe

D = screen distance = 130 cm = 1.30 m

= Position of nth bright fringe

Position of nth bright fringe is given as

For n = 1

For n = 2

For n = 3

b)

Position of nth dark fringe is given as

For n = 1

For n = 2

For n = 3

This question involves the concepts of **derivative**, **apparent temperature**, **actual temperature**,and **wind speed**.

The drop in **apparent temperature **will be **"1.25°C"**.

The **apparent temperature (W) **is given in terms of **actual temperature (T)** and **wind speed (v)** is given by the following function:

Taking the **derivative **with respect to **actual temperature**, we get:

where,

dW = drop in **apparent temperatures** = ?

dT = drop in **actual temperature** = - 1°C

v = **wind speed **= 18 km/h

Therefore,

**dW = - 1.25°C**

Learn more about **derivatives** here:

**Answer:**

** Δw=1.25°C**

**Explanation:**

Given that

Given that T= 12°C and v=19 km/h

Now to find the drop in the apparent temperature w

So

Now by putting the values v=19 km/hr and ΔT=1

** Δw=1.25°C**

**So we can say that when temperature is decrease by 1°C then apparent temperature will decrease by 1.25°C at given velocity.**

**Answer:**

for the body to float, the density of the body must be less than or equal to the density of the liquid.

**Explanation:**

For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.

Weight is

W = mg

let's use the concept of density

ρ_body = m / V

m = ρ_body V

W = ρ_body V g

The thrust of the body is given by Archimedes' law

B = ρ_liquid g V_liquid

as the body floats the submerged volume of the liquid is less than or equal to the volume of the block

ρ_body V g = ρ_liquid g V_liquid

ρ_body = ρ liquid Vliquido / V_body

As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.

**Answer:**

the statements, the correct one is A

a downward force of gravity and an upward force exerted by the surface

**Explanation:**

When the disc is hit, a thrust force is exerted in the direction of movement, at the moment the disc moves this force loses contact and becomes zero.

When the movement is already established there are two main forces: **gravity **that acts downwards and the reaction force to the support of the disk called **normal **that acts upwards.

As it is not mentioned that there is friction, this force that opposes the movement is zero.

Analyzing the statements, the correct one is A