Which of the following solutions are correct?
Which of the following solutions are correct? - 1

Answers

Answer 1
Answer:

Answer:

A and C are the answer

Step-by-step explanation:

hope it helps bye!!


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Which expression is equivalent to 6x+8 PLZZZZZZZZZZZZ HEWLPPP!2(3x-4)
2(3x+4)
2(4x+6)
2(3x+8)

Answers

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

Expand them all to see if you get the expression:

2(3x - 4) ==> 6x - 8

2(3x + 4) ==> 6x + 8

2(4x + 6) ==> 8x + 12

2(3x + 8) ==> 6x + 16

As you can see, the correct option is B. 2(3x + 4)

Hope This Helps You!

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Answer:

So the second one

Step-by-step explanation:

2(3x-4) =6x-8

2(3x+4)=6x+8   2x3=6    2x4=8

2(4x+6)=8x+12

2(3x+8)=6x+16

How many different simple random samples of size 5 can be obtained from a population whose size is 51​? The number of simple random samples which can be obtained is 281887200281887200. ​(Type a whole​ number.)

Answers

Answer:

2349060

Step-by-step explanation:

Given that :

Population size (n)= 51

Number of simple random samples (r) = 5

Using the combination formula :

nCr = n! ÷ (n-r)! r!

51C5 = 51! ÷ (51 - 5)!5!

51C5 = 51! ÷ 46!5!

51C5 = (51*50*49*48*47)*46! / 46! * (5*4*3*2*1)

51C5 = (51*50*49*48*47) / (5*4*3*2*1)

51C5 = 281887200 / 120

= 2349060

find the t values that form the boundaries of the critical region for a two-tailed test with a=.05 for n=6 n=12

Answers

Answer:

n=6

"=T.INV(1-0.025,5)", and we got the critical values given by: t_(critical)=\pm 2.5706  

n=12

"=T.INV(1-0.025,11)", and we got the critical values given by: t_(critical)=\pm 2.201  

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For n=6

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=6-1=5 degrees of freedom, a value that accumulates 0.05/2=0.025 of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:  

"=T.INV(1-0.025,5)", and we got the critical values given by: t_(critical)=\pm 2.5706  

For n=12  

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=12-1=11 degrees of freedom, a value that accumulates 0.05/2=0.025 of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:  

"=T.INV(1-0.025,11)", and we got the critical values given by: t_(critical)=\pm 2.201  

PLEASE HELP- 25 points-what is the circumference of the circle. Diameter =9cm

Answers

Answer:

9π cm - exact value

28.26 cm - approximate value

Step-by-step explanation:

C = πd =9π cm - exact value

or

C=9π≈ 28.26 cm - approximate value

A basketball player averages 22.5 points scored per game with a standard deviation of 6.2 points. In one game, the number of points the athlete scored was 1.2 standard deviations below his mean. How many points below average was this value?

Answers

Using the normal distribution, it is found that this value was 7.5 points below the average.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation\sigma is given by:

Z = (X - \mu)/(\sigma)

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 22.5, \sigma = 6.2.

In one game, the number of points the athlete scored was 1.2 standard deviations below his mean, hence Z = -1.2 and the score was of X, so:

Z = (X - \mu)/(\sigma)

-1.2 = (X - 22.5)/(6.2)

X - 22.5 = -1.2 x 6.2

X = 15.

15 - 22.5 = 7.5.

This value was 7.5 points below the average.

More can be learned about the normal distribution at brainly.com/question/24663213

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Answer:

7.44 is the answer

Step-by-step explanation:

What is the square root of 64y16?
o 44
O 4y
o 8
o gy

Answers

Answer:

B is the answer of the question

Answer:

The answer is 4y8

Step-by-step explanation: