Answer:

**Answer:**

hmmm thats too hard for me.

**Explanation:**

A hot-air balloon is descending at a rate of 2.3 m>s when a pas- senger drops a camera. If the camera is 41 m above the ground when it is dropped, (a) how much time does it take for the cam- era to reach the ground, and (b) what is its velocity just before it lands? Let upward be the positive direction for this problem.

Early in the morning, when the temperature is 5.5 °C, gasoline is pumped into a car’s 53-L steel gas tank until it is filled to the top. Later in the day the temperature rises to 27 °C. Since the volume of gasoline increases more for a given temperature increase than the volume of the steel tank, gasoline will spill out of the tank. How much gasoline spills out in this case?

Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 48.0 kg/s. Find the magnitude of the average force exerted on the water by the blade.

A skater has rotational inertia 4.2 kg-m2 with his fists held to his chest and 5.7 kg?m2 with his arms outstretched. The skater is spinning at 3.0 rev/s while holding a 2.5-kg weight in each outstretched hand; the weights are 76 cm from his rotation axis. If he pulls his hands in to his chest, so they�re essentially on his rotation axis, how fast will he be spinning? Express your answer using two significant figures. ?f=

How long would it take a 500. W electric motor to do 15010 J of work?

Early in the morning, when the temperature is 5.5 °C, gasoline is pumped into a car’s 53-L steel gas tank until it is filled to the top. Later in the day the temperature rises to 27 °C. Since the volume of gasoline increases more for a given temperature increase than the volume of the steel tank, gasoline will spill out of the tank. How much gasoline spills out in this case?

Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 48.0 kg/s. Find the magnitude of the average force exerted on the water by the blade.

A skater has rotational inertia 4.2 kg-m2 with his fists held to his chest and 5.7 kg?m2 with his arms outstretched. The skater is spinning at 3.0 rev/s while holding a 2.5-kg weight in each outstretched hand; the weights are 76 cm from his rotation axis. If he pulls his hands in to his chest, so they�re essentially on his rotation axis, how fast will he be spinning? Express your answer using two significant figures. ?f=

How long would it take a 500. W electric motor to do 15010 J of work?

B. 2 cm/s2

C. 5 cm/s2

D. 6 cm/s2

The **asteroid **234 Ida has a mass of about 4×1016 kg and an average radius of about 16 km. The **acceleration **due to gravity will be 1.04 cm/s². Hence, option A is correct.

The **acceleration **an object experiences as a result of **gravitational force **is known as acceleration due to gravity. M/s² is its SI unit. Its vector nature—which includes both **magnitude **and **direction**—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of **g **on the earth's surface is** 9.8** m/s².

The formula for the acceleration due to gravity is g=GM/r².

According to the question, the given values are :

Mass, M = 4 × 1016 kg or

M = 4 × 10¹⁶.

Radius, r = 16 km or,

r = 16000 meter.

G = 6.67 × 10⁻¹¹ Nm²/kg²

g = (6.67 × 10⁻¹¹ ) (4 × 10¹⁶) / 16000²

g = 0.0104 m/s² or,

g = 1.04 cm/s².

Hence, the **acceleration **due to gravity will be 1.04 m/s²

To get more information about **Acceleration due to gravity** :

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**Answer:**

1 cm/s²

**Explanation:**

I just took the quiz

b. counterclockwise

c. There is no induced current in the coil.

**Answer:**

Option B

**Explanation:**

As per the Lenz’s law of electromagnetism the current induced in a conductor due to any change has a tendency to oppose the change which is causing this induces current.

Thus, when a constant magnetic field with an electric circuit is varied, it produces and induced current which flow in a direction such that its sets a magnetic field that tries to restore the flux

Hence, option B is correct

b. What is the distance Δymax-min between the second maximum of laser 1 and the third minimum of laser 2, on the same side of the central maximum?

**Answer:**

a)Δy = 81.7mm

b)Δy = 32.7cm

**Explanation:**

To calculate the distance between any point of the interference pattern, simply use the trigonometric ratio of the tangent:

where D is the separation between the slits and the screen where the interference pattern is observed.

a) In this case:

Δy = |y1max (λ1) − y1max (λ2)|

Δy =

Δy =

Δy =

Δy =

Δy = 81.7mm

The separation between these maxima is 81.7 mm

b)

Δy = |y₂max (λ1) − y₂max (λ2)|

Δy =

Δy =

Δy = 32.7cm

The separation between the maximum interference of the 2nd order (2nd maximum) of the pattern produced by the laser 1 and the minimum of the 2nd order (3rd minimum) of the pattern produced by the laser 2 is 32.7 cm.

We can solve the problem using the concepts of **wave****interference **and the formulas for maxima and minima positions (i.e., y = L*m*λ/d and y = L*(m+1/2)*λ/d respectively). The difference between the first maxima of the two patterns is 4.9/60 m and the difference between the second maximum of laser 1 and the third minimum of laser 2 is also 4.9/60 m.

The problem described deals with wave **interference **and can be addressed using the formulas for path difference and **phase****difference**.

To answer part a, we need to find the difference between the **positions** of the first maxima for the two lasers. The position of any maxima in an interference pattern can be found using the formula: y = L * m * λ / d, where L is the distance from the slits to the screen, m is the order of the maxima, λ is the wavelength, and d is the slit separation.

So for the first laser (λ1=d/20) the position of the first maxima would be y1 = 4.9m * 1 * (d/20) / d =4.9/20 m.

And for the second laser (λ2 = d/15) the position of the first maxima would be y2= 4.9m * 1 * (d/15) / d =4.9/15 m.

Then, the distance Δ **ymax**-**max **between the first maxima of the two patterns is y2-y1= 4.9/15 m - 4.9/20 m = 4.9/60 m.

Answering part b involves finding the positions of the second maximum of **laser **1 and the third minimum of laser 2. The position of any minimum in an **interference pattern** can be calculated using the formula: y = L * (m+1/2) * λ / d. For the second maximum of laser 1, we have y1max2 = 4.9 m * 2 * (d/20) / d = 4.9/10 m. For the third minimum of laser 2, we have y2min3 = 4.9m * (3.5) * (d/15)/d = 4.9*7/30 m. The **difference **Δymax-min is y2min3-y1max2= 4.9*7/30 m - 4.9/10 m = 4.9/60 m.

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Answer:

the second derivative of y with respect to time gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string

Explanation:

This is because the transverse wave movement of particles take place in direction 90° to direction of movement of the wave (x) itself, so second derivative of y with respect to time (t)is what will be required

**Answer:**

**Ionization potential of C⁺⁵ is 489.6 eV.**

**Wavelength of the transition from n=3 to n=2 is 1.83 x 10⁻⁸ m. **

**Explanation:**

The ionization potential of hydrogen like atoms is given by the relation :

.....(1)

Here *E* is ionization potential, *Z* is atomic number and *n* is the principal quantum number which represents the state of the atom.

In this problem, the ionization potential of Carbon atom is to determine.

So, substitute 6 for *Z* and 1 for *n* in the equation (1).

* E = ***489.6 eV**

The wavelength (λ) of the photon due to the transition of electrons in Hydrogen like atom is given by the relation :

......(2)

R is Rydberg constant, n₁ and n₂ are the transition states of the atom.

Substitute 6 for Z, 2 for n₁, 3 for n₂ and 1.09 x 10⁷ m⁻¹ for R in equation (2).

= 5.45 x 10⁷

**λ = 1.83 x 10⁻⁸ m**

You should obtain e/m = 2V/(B^2)(r^2)

3. The magnetic field on the axis of a circular current loop a distance z away is given by

B = mu I R^2 / 2(R^2 + z^2)^ (3/2)

where R is the radius of the loops and I is the current. Using this result , calculate the magnetic field at the midpoint along the axis between the centers of the two current loops that make up the Helmholtz coils, in terms of their number of turns N, current I, and raidus R.Helmholtz coils are separated by a distance equal to their raidus R. You should obtain:

|B| = (4/5)^(3/2) *mu *NI/R = 9.0 x 10^-7 NI/R

where B is magnetic field in tesla, I is in current in amps, N is number of turns in each coil, and R is the radius of the coils in meters

**Answer:**

**Explanation:**

Magnetic field creates a force perpendicular to a moving charge in its field which is equal to Bev where B is magnetic field , e is amount of charge on the moving charge and v is the velocity of charge particle .

This force provides centripetal force for creation of circular motion. If r be the radius of the circular path

Bev = mv² / r

r = mv / Be

2 ) If an electron is accelerated by an electric field created by potential difference V then electric field

= V / d where d is distance between two points having potential difference v .

force on charged particle

electric field x charge

= V /d x e

work done by field

= force x distance

= V /d x e x d

V e

This is equal to kinetic energy created

V e = 1/2 mv²

= 1/2 m (r²B²e² / m² )

V = r²B²e/ 2 m

e / m = 2 V/ r²B²

3 )

B =

In Helmholtz coils , distance between coil is equal to R so Z = R/2

B =

For N turns of coil and total field due to two coils

B =

=

= 9.0 x 10^-7 NI/R