# A particular frozen yogurt has 75 cal into ounces how many calories are in 8 ounces of the yogurt

Answer: I'm guessing you mean 75 calories in 2 ounces.
In that case... you would do
75 / 2 = 37.5
37.5 x 8 = 300 calories in 8 ounces of yogurt

Hope I helped!

## Related Questions

I am a decimalIf you double me,my double is between 0.6 and 0.7,
But closer to 0.6.

My Thousandths digit is not a 2.
But the thousandths digit of my double is.
What decimal might I be?

0.6<2x<0.65 (because it's closer to 6)
0.3<x<0.325

Since the thousandths digit of 2x is 2, then the thousandths digit of x is 1 or 6, so the decimal could be 0.301, 0.302, 0.311, 0.312, 0.321

Hope this helps :)

Numbers greater than 0.3 and less then 0.35 are between .6 and .7 when doubled.

Lets assume it is a decimal that goes up to the thousandths.
0.310 to 0.324 Would be closer to .6 than .7. We know the thousands digit has to be a 1 or a 6 because its double ends in a two. So it looks like our options are
.311, .316 and .321.

5. Find the equation of the line through the point (1, 3) with a slope of 2 in both pointslope form and slope-intercept form. Sketch a graph of the function.

point slope form: y-3=2(x-1)

Slope-intercept form: y=2x+1

Step-by-step explanation:

y-y=m(x-x)

y-3=2(x-1)

y-3=2x-2

y=2x-2+3

y=2x+1

2
Multiple choice. How many solutions does the equation 6 + 1 = -6x+ 10 have?

x = 0.5, one solution

Step-by-step explanation:

6+1 = -6x + 10

7 = -6x + 10

-3 = -6x

6x = 3

x = 3/6

x = 1/2

x = 0.5

The numbers on a football field indicate 10 yard increments. You walk around the perimeter of a football field between the pylons. You walk a distance of 306 and 2/3 yards. Find the area and perimeter of the indicated regions. Write your answers as mixed numbers, if necessary. One end zone

Answer: 126.67 is the perimeter walked

Step-by-step explanation:

Given data:

Distance walked on the field = 306 2/3 yards.

Increments on the field = 10 yards.

Solution:

We know a pitch has 4 sides let make it A, B,C,D = 306.67yards.

each has an increment of 10

= 10 x 10 + 10 x 10 = 200

Therefore

= 306.67 yards – 200

= 106.67 yards.

For both end zones Perimeter

= 106.67 + 10 + 10

= 126.67 yards

The area of the end zone is 6400 square yards and the perimeter is 326 and 2/3 yards.

### Explanation:

To find the area and perimeter of the end zone of a football field, we need to know the dimensions of the end zone. If the end zone has a width of 53 and 1/3 yards, we multiply the width by the length of the field, which is 120 yards, to find the area. So the area of the end zone is (53 and 1/3) x 120 = 6400 square yards. The perimeter is found by adding the dimensions together, so the perimeter of the end zone is (2 x 53 and 1/3) + (2 x 120) = 326 and 2/3 yards.