A 50 kg child on a skateboard experiences a 75-N force as shown.What is the expected acceleration of the child?

F = 75 N

A. 0.67 m/s2
B. 1.50 m/s2
C. 6.70 m/s2
D. 25.0 m/s2


Answer 1


1.50 m/s²


The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a = (f)/(m) \n

f is the force

m is the mass

From the question we have

a = (75)/(50) = (3)/(2) \n

We have the final answer as

1.50 m/s²

Hope this helps you

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A 0.454-kg block is attached to a horizontal spring that is at its equilibrium length, and whose force constant is 21.0 N/m. The block rests on a frictionless surface. A 5.30×10?2-kg wad of putty is thrown horizontally at the block, hitting it with a speed of 8.97 m/s and sticking.Part AHow far does the putty-block system compress the spring?


The distance the putty-block system compress the spring is 0.15 meter.

Given the following data:

  • Mass = 0.454 kg
  • Spring constant = 21.0 N/m.
  • Mass of putty = 5.30* 10^(-2)\;kg
  • Speed = 8.97 m/s

To determine how far (distance) the putty-block system compress the spring:

First of all, we would solver for the initialmomentum of the putty.

P_p = mass * velocity\n\nP_p = 5.30* 10^(-2)* 8.97\n\nP_p = 47.54 * 10^(-2) \;kgm/s

Next, we would apply the law of conservation of momentum to find the final velocity of the putty-block system:

P_p = (M_b + M_p)V\n\n47.54* 10^(-2) = (0.454 + 5.30* 10^(-2))V\n\n47.54* 10^(-2) = 0.507V\n\nV = (0.4754)/(0.507)

Velocity, V = 0.94 m/s

To find the compression distance, we would apply the law of conservation of energy:

U_E = K_E\n\n(1)/(2) kx^2 = (1)/(2) mv^2\n\nkx^2 =M_(bp)v^2\n\nx^2 = (M_(bp)v^2)/(k) \n\nx^2 = ((0.454 + 5.30* 10^(-2)) * 0.94^2)/(21)\n\nx^2 = ((0.507 * 0.8836))/(21)\n\nx^2 = ((0.4480))/(21)\n\nx=√(0.0213)

x = 0.15 meter

Read more: brainly.com/question/14621920



Force constant of spring K = 21 N /m

we shall find the common velocity of putty-block system from law of conservation of momentum .

Initial momentum of putty

= 5.3 x 10⁻² x 8.97

= 47.54 x 10⁻² kg m/s

If common velocity after collision be V

47.54 x 10⁻² = ( 5.3x 10⁻² + .454) x V

V = .937 m/s

If x be compression on hitting the putty

1/2 k x² = 1/2 m V²

21 x² = ( 5.3x 10⁻² + .454) x .937²

x² = .0212

x = .1456 m

14.56 cm

A spectroscope breaks light up into its colors, allowing scientists to analyze light from the solar system and universe. By studying the spectral line patterns, widths, strengths and positions, scientists can determine the speed, position, and _____ of celestial bodies.A) age
B) origin
C) rotation
D) temperature


It is D - temperature

Final answer:

A spectroscope analyses light to determine various parameters of celestial bodies. The missing parameter in this context is the 'temperature' of the celestial body (option D). The spectral lines, based on their pattern and strengths helps in determining this.


A spectroscope decomposes or breaks white light into its spectrum of colors, allowing scientists to study them and understand various aspects of celestial bodies. When scientists analyze the spectral line patterns, widths, strengths, and positions, they can discern essential parameters. These parameters include the speed and position of the celestial body, and more importantly, the correct answer to your question, its temperature (option D). This is because every element when heated, absorbs or emits light at characteristic wavelengths, that give us the 'spectral lines'. By studying these we can determine the temperature of the celestial body.

Learn more about Spectroscope here:



When the frequency of an electromagnetic wave increases, its energy A. increases.
B. decreases.
C. stays the same.
D. It depends on the exact type of electromagnetic wave.


At the time when the frequency of an electromagnetic wave increases, its energy increased.

The following information should be considered:

  • When the electromagnetic wave increases so the energy should be increased.
  • Due to all this, the speed, wavelength all should be decreased.

Therefore we can conclude that At the time when the frequency of an electromagnetic wave increases, its energy increased.

Learn more: brainly.com/question/6201432

When the frequency of an electromagnetic wave increases, its energy also must increase. As this occurs, its speed, wavelength, and amplitude all decreases. So, the correct choice would be A. Increases. 

I hope I was able to satisfyingly answer your question. :) 

The table below shows the mass and velocity of four objects. Which object has the least inertia?A. Y
B. Z
C. X
D. W


The object with the least inertia is Z.

option B is the correct answer.

What is Newton's first law of motion?

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless it is acted upon by an external force and it will move in the direction of applied force.

The Newton's first law of motion is also called the law of inertia because it depends on the mass of the object.

Inertia is defined as the reluctancy of an object to move when a force is applied to it.

As the mass of an object increase, the inertia of the object increases because the object will be more reluctant to move when a force is applied to it.

Thus, the more massive an object is, the greater the object's inertia and vice versa.

Learn more about inertia here: brainly.com/question/1140505


A circular coil lies flat on a horizontal surface. A bar magnet is held above the center of the coil with its north pole pointing downward, and is released from rest. What is the direction of the induced current in the coil, as viewed from above, as the magnet approaches the coil in free fall?a. clockwise
b. counterclockwise
c. There is no induced current in the coil.



Option B


As per the Lenz’s law of electromagnetism the current induced in a conductor due to any change has a tendency to oppose the change which is causing this induces current.  

Thus, when a constant magnetic field with an electric circuit is varied, it produces and induced current which flow in a direction such that its sets a magnetic field that tries to restore the flux

Hence, option B is correct

How does an increase in cold working effect Modulus of Elasticity and why?



There is a decrease in modulus of elasticity


Young's Modulus of elasticity also known as elastic modulus is the deformation of a body along a particular axis under the action of opposing forces along that axis. at atomic levels, it depends on bond energy or strength.

In cold working processes, plastic deformation a metal occurs below its re-crystallization temperature due to which crystal structure of metal gets distorted and as a result of dislocations fractures also occur resulting in hardening of metal but bonds at atomic levels defining elasticity are temporarily affected.

Thus an increase in cold working results in a decrease in modulus of elasticity.