Question: Looking at the above visual of "Atmospheres of the Solar System" What are two patternsyou can find? PLEASE HELP DUE TONIGHT!
question: Looking at the above visual of "Atmospheres of the - 1


Answer 1


The first and most obvious pattern I see is that all gas giants have an atmosphere mainly made up of hydrogen

The second thing I notice is that all the rocky planets have a significant amount of Nitrogen in their atmospheres except Mercury.

The third thing I notice is that all planets have one element that makes up 75% or more of its atmosphere except Mercury.

(If this is good, may I have brainliest, please? I'm kinda poor..)

Answer 2


It's hard to find patterns in the solar system's atmosphere but I think above found a lot of them.

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Calculate the concentration of OH in a solution that contains 3910-4 M H30 at 25°C. Identify the solution as acidic, basic or neutral OA) 2.6 10-11 M, acidic OB)26 10-11 M. basic O c) 3.9 x 10-4 M, neutral OD) 2.7 * 10-2 M
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What mass of Nz will be needed to produce 31.5 grams of N2O5?4N2 + 502 --> 2N2O5
a) 158.3 grams
b) 38.64 grams
c) 4.96 grams
d) 16.34 grams


Answer: d) 16.34 grams


To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  

\text{Moles of} N_2O_5=(31.5g)/(108.01g/mol)=0.292moles

The balanced chemical reaction given is:

4N_2+5O_2\rightarrow 2N_2O_5  

According to stoichiometry :

As 2 moles of N_2O_5 are produced by= 4 moles of N_2

Thus 0.292 moles of N_2O_5 are produced by=  =(4)/(2)* 0.292=0.584moles of N_2

Mass of N_2=moles* {\text {Molar mass}}=0.584moles* 28g/mol=16.34g

Thus 16.34 g of N_2 will be needed

Which beat describes heat



I assume you mean which best describes heat.

The answer is The energy transferred between samples of matter because of a difference in their temperatures.

To explain this further, heat is total energy of an object, temperature is average energy. The change in temperature between two objects is called heat!

Think about transfers of heat in everyday terms: if you put an ice cube in your tea (I don't know, just bear with me), the cold does not transfer to the tea. The heat of the tea is transferred to the ice cube! And this is clearly a difference in heat.

The dry solute has a mass of 0.086 g. 0.113 g of water evaporated while heating. What is the concentration in G solute / mL solvent at 30.1 C? Remember: 1 g = 1 ml for waterA. 0.88
B. 0.0860
C. 0.113
D. 0.761


The dry solute has a mass of 0.086 g. 0.113 g of water evaporated while heating, the concentration in G solute / mL solvent at 30.1 C is 0.88.

To find the concentration in g solute / mL solvent, we first need to find the mass of the solvent left after evaporation:

Mass of water before evaporation = 0.113 g

Mass of water after evaporation = 0.113 g - 0.086 g = 0.027 g

Since 1 g of water has a volume of 1 mL, the volume of water after evaporation is also 0.027 mL.

Next, we need to convert the temperature to Kelvin:

T = 30.1 + 273.15 = 303.25 K

We can now use the formula:

concentration = (mass of solute / mass of solvent) / (1 - (mass of water evaporated / mass of solvent))

Plugging in the values we get:

concentration = (0.086 g / (0.027 g)) / (1 - (0.113 g / (0.086 g + 0.027 g)))

concentration = 0.88 g/mL

Therefore, the answer is A. 0.88.

For more details regarding concentration, visit:





worked for me on acellus

Calculate the wavelength of A 75 kg athlete running a 7.0-minute mile



\lambda =2.31x10^(-36)m



In this case, since the Broglie's wavelength for bodies is defined via:

\lambda =(h)/(mv)

Whereas h accounts for the Planck's constant, m the mass and v the velocity, which is:


Thus, the wavelength turns out:

\lambda =(6.63x10^(-34)kg(m^2)/(s) )/(75kg*3.83(m)/(s) ) \n\n\lambda =2.31x10^(-36)m

Best regards.

For the following reaction at equilibrium, which gives a change that will shift the position of equilibrium to favor formation of more products? 2NOBr(g) 2NO(g) + Br 2(g), ΔHº rxn = 30 kJ/mol



Based on the given reaction, it is evident that the reaction is endothermic as indicated by a positive sign of enthalpy of reaction. Thus, it can be stated that the favoring of the forward reaction will take place by upsurging the temperature of the reaction mixture.  

Apart from this, based on Le Chatelier’s principle, any modification in the quantity of any species is performed at equilibrium and the reaction will move in such an orientation so that the effect of the change gets minimized. Therefore, a slight enhancement in the concentration of the reactant will accelerate the reaction in the forward direction and hence more formation of the product takes place.  

What is the formula for nickel (II) carbonate