Answer:

**Answer:**

ok

**Explanation:**

A smart phone charger delivers charge to the phone, in the form of electrons, at a rate of -0.75. How many electrons are delivered to the phone during 27 min of charging?

Two resistors are to be combined in parallelto form an equivalent resistance of 400Ω. The resistors are takenfrom available stock on hand as acquired over the years. Readily available are two common resistorsrated at 500±50 Ωand two common resistors rated at 2000 Ω±5%. What isthe uncertainty in an equivalent 400 Ωresistance?(Hint: the equivalent resistance connected in parallel can be obtained by 1212TRRRRR=+)

What is the force required to accelerate 1 kilogram of mass at 1 meter per second per second.1 Newton 1 pound 1 kilometer 1 gram

Part A (4 pts) Consider light of wavelength λ = 670nm traveling in air. The light is incident at normal incidence upon a thin film of oil with n2 =1.75. On the other side of the thin film is glass with n3 =1.5. What is the minimum non-zero value of the film thickness d that will cause the reflections from both sides of the film to interfere constructively?

Find the magnitude and direction of an electric field that exerts a 4.80×10−17N westward force on an electron. (b) What magnitude and direction force does this field exert on a proton?

Two resistors are to be combined in parallelto form an equivalent resistance of 400Ω. The resistors are takenfrom available stock on hand as acquired over the years. Readily available are two common resistorsrated at 500±50 Ωand two common resistors rated at 2000 Ω±5%. What isthe uncertainty in an equivalent 400 Ωresistance?(Hint: the equivalent resistance connected in parallel can be obtained by 1212TRRRRR=+)

What is the force required to accelerate 1 kilogram of mass at 1 meter per second per second.1 Newton 1 pound 1 kilometer 1 gram

Part A (4 pts) Consider light of wavelength λ = 670nm traveling in air. The light is incident at normal incidence upon a thin film of oil with n2 =1.75. On the other side of the thin film is glass with n3 =1.5. What is the minimum non-zero value of the film thickness d that will cause the reflections from both sides of the film to interfere constructively?

Find the magnitude and direction of an electric field that exerts a 4.80×10−17N westward force on an electron. (b) What magnitude and direction force does this field exert on a proton?

0.67 m/s2

0.075 m/s2

54 m/s2

4.0 m/s2

it's 9 squared divided by 6

it's 9 squared divided by 6

the answer is B 4.0 m/s2

-Calculate the net work Wnet in J done on the bucket of water by the two forces F1 and Fg.

To **calculate **the work done by gravity on the bucket of water as it is lifted up the well, multiply the weight of the bucket by the lifting distance. The net work done on the bucket by the force applied by the farmer and gravity is the sum of the work done by both forces. The net work is represented by the equation Wnet = W1 + Wg.

To calculate how much work gravity does on the **bucket **filled with water as the farmer lifts it up the well, we need to multiply the force of gravity (weight) by the vertical distance the bucket is lifted. The equation for work is W = Fd, where W is the work done, F is the force, and d is the distance. In this case, the force of gravity is the weight of the bucket, which can be calculated by multiplying the mass by the acceleration due to gravity (9.8 m/s^2).

So, the work done by gravity (Wg) on the bucket is Wg = Fg * d = (m * g) * d = (3.9 kg * 9.8 m/s^2) * d = 38.22 d Joules.

To calculate the net work done on the bucket by the two forces, we can use the equation Wnet = W1 + Wg, where W1 is the work done by force F1 and Wg is the work done by gravity. Since force F1 and the displacement (lifting distance) are both vertical, the work done by F1 is given by W1 = F1 * d.

Therefore, the net work done on the bucket by forces F1 and gravity is Wnet = F1 * d + Fg * d = (57.5 N) * d + (3.9 kg * 9.8 m/s^2) * d = (57.5 N + 38.22 d) Joules.

#SPJ12

**Answer:**

The magnetic field at the center of the solenoid is approximately **0.0117 T**

**Explanation:**

Given;

length of the solenoid, L = 15 cm = 0.15 m

number of turns of the solenoid, N = 350 turns

current in the solenoid, I = 4.0 A

The magnetic field at the center of the solenoid is given by;

Therefore, the magnetic field at the center of the solenoid is approximately **0.0117 T**.

**Answer:**

R = 8.94 10⁻² Ω/m, R_sp / R_total = 44.8

**Explanation:**

The resistance of a metal cable is

R = ρ L / A

The area of a circle is

A = π R²

The resistivity of copper is

ρ = 1.71 10⁻⁸ ohm / m

Let's calculate

R = 1.71 10⁻⁸ 4.27 / (π (0.51 10⁻³)²)

R = 8.94 10⁻² Ω/m

Each bugle needs two wire, phase and ground

The total wire resistance is

R_total = 2 R

R_total = 17.87 10⁻² Ω

Let's look for the relationship between the resistance of the bugle and the wire

R_sp / R_total = 8 / 17.87 10⁻²

R_sp / R_total = 44.8

The resistance of the speaker wire can be calculated using the formula for the **resistance **of a wire, taking into account the resistivity of copper, the length and thickness of the wire, and whether a single or pair of wires is used.

The question is asking you to find the minimum resistance of a **copper **wire given its diameter and length, plus the resistance of the speaker it's connected to. Resistance of a wire is calculated using the formula R=ρL/A, where R is the resistance, ρ (rho) is the resistivity of the material (in this case, copper), L is the length of the wire, and A is the cross-sectional area of the wire.

First, you need to find the area of the 0.51 mm diameter wire. The area (A) of a wire is given by the formula π(d/2)^2 where d is the diameter of the wire. After calculating the area, use the formula R=ρL/A to calculate the resistance. For copper wire at 20°C, ρ is approximately 1.68 × 10^-8 Ω·m. Substituting these values into the formula will give you the resistance of the wire in ohms.

Note: you may need to consider whether you have just a single wire or a **pair**, since two wires are typically required to connect a speaker. If a pair is used, each wire will carry half the current, which affects the total resistance.

#SPJ12

**Answer:**

**3.27 turns**

**Explanation:**

To find how many turns (θ) will the stone make before coming to rest we will use the following equation:

__Where:__

: is the final angular velocity = 0

: is the initial angular velocity = 71.150 rpm

α: is the angular acceleration

*First, we need to calculate the **angular acceleration (α)**. To do that, we can use the following equation:*

__Where:__

I: is the moment of inertia for the disk

τ: is the torque

**The moment of inertia is:**

__Where:__

m: is the mass of the disk = 105.00 kg

r: is the radius of the disk = 0.297 m

**Now, the torque is equal to:**

__Where:__

F: is the applied force = 46.650 N

μ: is the kinetic coefficient of friction = 0.451

The minus sign is because the friction force is acting opposite to motion of grindstone.

**Having the moment of inertia and the torque, we can find the angular acceleration: **

**Finally, we can find the number of turns that the stone will make before coming to rest:**

I hope it helps you!

**Answer:**

**Explanation:**

Given

Length of string =2.15 m

mass of ball =5.49 kg

speed of ball=4.65 m/s

Here

Tension provides centripetal acceleration

-----1

------2

Divide 2 & 1