Jan raised $120.75 at the car wash. If each wash costs $5.75, how many cars did she wash?

Answers

Answer 1
Answer:

Answer:

She washed 21 cars

Step-by-step explanation:

Answer 2
Answer:

Answer:

Jan washed 21 cars

Step-by-step explanation:

120.75 / (Divided) 5.75=21

If you were to times 5.75 by 21 you will get the amount she rasied at the car wash


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PLEASE HELPIf u can’t read it good it says: which equation matches this graph? 1. Y= -4x + 32. Y= 4x + 33. Y= -(1/4) x +34. Y=- (1/4)x + 3

The tread life of tires mounted on light-duty trucks follows the normal probability distribution with a mean of 60,000 miles and a standard deviation of 4,000 miles. Suppose you bought a set of four tires, what is the likelihood the mean tire life of these four tires is between 57,000 and 63,000 miles

Answers

Answer:

86.64% probability that the mean tire life of these four tires is between 57,000 and 63,000 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = (\sigma)/(√(n))

In this problem, we have that:

\mu = 60000, \sigma = 4000, n = 4, s = (4000)/(√(4)) = 2000

Suppose you bought a set of four tires, what is the likelihood the mean tire life of these four tires is between 57,000 and 63,000 miles

This is the pvalue of Z when X = 63000 subtracted by the pvalue of Z when X = 57000. So

X = 63000

Z = (X - \mu)/(\sigma)

By the Central Limit Theorem

Z = (X - \mu)/(s)

Z = (63000 - 60000)/(2000)

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

X = 57000

Z = (X - \mu)/(s)

Z = (57000 - 60000)/(2000)

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.9332 - 0.0668 = 0.8664

86.64% probability that the mean tire life of these four tires is between 57,000 and 63,000 miles

A set X is said to be closed under multiplication if for every X1, X2 E X we have X1X2 E X. Let A be the union of all bounded subsets X CR that are closed under multiplication. Does inf(A) exist? If it does, find it.

Answers

Answer:

inf(A) does not exist.

Step-by-step explanation:

As per the question:

We need to prove that A is closed under multiplication,

If for everyX_(1), X_(2)\in X

X_(1)X_(2)\in X

Proof:

Suppose, x, y \in A

Since, both x and y are real numbers thus xy is also a real number.

Now, consider another set B such that:

B = {xy} has only a single element 'xy' and thus [B] is bounded.

Since, [A] represents the union of all the bounded sets, therefore,

B\subset A

⇒ xy \in A

Therefore, from x, y \]in A, we have xy \]in A.

Hence, set a is closed under multiplication.

Now, to prove whether inf(A) exist or not

Proof:

Let us assume that inf(A) exist and inf(A) = \beta

Thus \beta is also a real number.

Let C be another set such that

C = { \beta - 1}

Now, we know that C is a bounded set thus { \beta - 1} is also an element of A

Also, we know:

inf(A) =  \beta

Therefore,

n(A)\geq \beta

But

\beta - 1 is an element of A and  \beta - 1 \leq \beta

This is contradictory, thus inf(A) does not exist.

Hence, proved.

Using the figure below, what is the trigonometric ratio of cos C?

Answers

Answer:

8/9 (choice b)

Step-by-step explanation:

The trigonometric ratios are based on the ratios of different sides.

If you remember SOH CAH TOA =

sine (sin) opposite hypotenuse

cosine (cos) adjacent hypotenuse

tangent (tan) opposite adjacent

__________________________

This is a nuemonic for these ratios.

the opposite side is the side that is directly across from the reference angle, the hypotenuse is the longest side, and the adjacent side is the side other than these two.

So cos C = adjacent side / hypotenuse side.

Since 18 is greater than 16 and 9, 18 is the hypotenuse.

the adjacent side is the side other than the opposite side and the hypotenuse which is 16

therefore cos C = 16 / 18 = 8 / 9.

PLEASE HELP RLLY NEED IT GUYS

Answers

Answer:

156.95

Step-by-step explanation:

length x width x height

(-1, 1), (5,-5)
Midpoint formula

Answers

Answer:

(4,-4)

Step-by-step explanation:

(X,y)=(x1+X2) ,(y1+ y2)

= (-1+5), ( 1-5)

= (4, -4)

The number of milligrams of a certain medicine a veterinarian gives to a dog varies directly with the weight of the dog.If the veterinarian gives a 30-pound dog 5 milligram of the medicine, which equation relates the weight, w, and the
dosage, o?

Answers

Question: The number of milligrams of a certain medicine a veterinarian gives to a dog varies directly with the weight of the dog. If the veterinarian gives a 30-pound dog 3/5 milligram of the medicine, which equation relates the weight,w, and the dosage, d?

Answer: d= 1/50w

Explanation: I took the test in Edgenuity.

Hope this helps!