-7/3 x = 7 solve for x

Answers

Answer 1
Answer:

Answer:

x=  -3

Step-by-step explanation:


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PLEASE HELP!!! ILL GIVE BRANLIEST *EXTRA POINTS* dont skip :((

Answers

Answer:

it is point B

Step-by-step explanation:

because im smart

Answer:

Point B

Step-by-step explanation:

√11 is 3.3

And A is about 2. Something and inbetween D and E is 4 which means C will be 3.5

So it leaves it at B

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second). (a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

Answers

Answer:

The probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day is P(Y>190)=\frac{1}{e^{(19)/(10)}}\approx 0.1496

Step-by-step explanation:

Let Y be the water demand in the early afternoon.

If the random variable Y has density function f (y) and a < b, then the probability that Y falls in the interval [a, b] is

P(a\leq Y \leq b)=\int\limits^a_b {f(y)} \, dy

A random variable Y is said to have an exponential distribution with parameter \beta > 0 if and only if the density function of Y is

f(y)=\left \{ {{(1)/(\beta)e^{-(y)/(\beta) }, \quad{0\:\leq \:y \:\leq \:\infty}   } \atop {0}, \quad elsewhere} \right.

If Y is an exponential random variable with parameter β, then

mean = β

To find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day, you must:

We are given the mean = β = 100 cubic feet per second

P(Y>190)=\int\limits^(\infty)_(190) {(1)/(100)e^(-y/100) } \, dy

Compute the indefinite integral \int (1)/(100)e^{-(y)/(100)}dy

(1)/(100)\cdot \int \:e^{-(y)/(100)}dy\n\n\mathrm{Apply\:u \:substitution}\:u=-(y)/(100)\n\n(1)/(100)\cdot \int \:-100e^udu\n\n(1)/(100)\left(-100\cdot \int \:e^udu\right)\n\n(1)/(100)\left(-100e^u\right)\n\n\mathrm{Substitute\:back}\:u=-(y)/(100)\n\n(1)/(100)\left(-100e^{-(y)/(100)}\right)\n\n-e^{-(y)/(100)}

Compute the boundaries

\int _(190)^(\infty \:)(1)/(100)e^{-(y)/(100)}dy=0-\left(-\frac{1}{e^{(19)/(10)}}\right)

\int _(190)^(\infty \:)(1)/(100)e^{-(y)/(100)}dy=\frac{1}{e^{(19)/(10)}}\approx 0.1496

The probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day is P(Y>190)=\frac{1}{e^{(19)/(10)}}\approx 0.1496

The sum of three consecutive odd numbers is 69. What is the smallest of the three numbers?

Answers

Answer:

21

Step-by-step explanation:

Let the smallest of the numbers be N

The other two numbers (consecutive) would be written as (n + 2), (n + 4)

Expressing these as an equation gives : (n) + (n+2) + (n+4) = 69

opening the bracket and collecting like terms, we have:

n+n+n+2+4=69

3n + 6 = 69

3n = 69 - 6

3n = 63

Dividing both sides by 3 or making n the subject formular, we get:

n = 63/3

n = 21.

Note, the other numbers are: 21, 23, and 25

They are all odd numbers

Their sum equals to 69

An ANOVA procedure is used for data obtained from four populations. Four samples, each comprised of 30 observations, were taken from the four populations. The numerator and denominator (respectively) degrees of freedom for the critical value of F are _____.

Answers

Answer:

Step-by-step explanation:

Given that an ANOVA procedure is used for data obtained from four populations. Four samples, each comprised of 30 observations, were taken from the four populations.

Hence total observations are 30*4 =120

No of groups = 3

Hence numerator df = 3-1 =2

Now total degrees of freedom = 120-1 =119

So denominator degrees of freedom = 119-2 = 117

Thus F statistic will have numerator as 2 degrees of freedom and denominator as 117 degrees of freedom.

The ratio between the number of red and green marbles in a box is 3:7. How many marbles are in the box if there are 20 fewer red marbles than green marbles?PLS HELP QUICK LIKE IN 1 SECOND!!

Answers

there are 50 marbles

Answer:

50

Step-by-step explanation:

difference of ratio=7-3=4

sum of ratio=3+7=10

if difference 4 total=10

if difference 20 total=10/4×20=50

A ladder is leaning against the side of a 10 m house. If the base of the ladder is 3 m awayfrom the house, how long is the ladder? Please draw a diagram.

Answers

Answer: It depends on how you round but about 10.44 m.

Step-by-step explanation: