How long would it take a 500. W electric motor to do 15010 J of work?

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Answer 1
Answer: time = energy / power = 15010 / 500 = .... seconds

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Answer all three parts and show work.

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The distance for both Parts A and B are given in the question.

A balloon drifts 140m toward the west in 45s.

The wind suddenly changes and the balloon flies 90m toward the east in the next 25s.

To find the total distance, we can just add.

140 + 90 = 230m

Best of Luck!

A 0.060 ???????? tennis ball, moving with a speed of 5.28 m/???? , has a head-on collision with a 0.080 ???????? ball initially moving in the same direction at a speed of 3.00 m/ ???? . Assume that the collision is perfectly elastic. Determine the velocity (speed and direction) of both the balls after the collision.

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Explanation:

It is given that,

Mass of the tennis ball, m_1=0.06\ kg

Initial speed of tennis ball, u_1=5.28\ m/s

Mass of ball, m_2=0.08\ kg

Initial speed of ball, u_2=3\ m/s

In case of elastic collision, the momentum remains conserved. The momentum equation is given by :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v_1\ and\ v_2 are final speed of tennis ball and the ball respectively.

0.06* 5.28+0.08* 3=0.06v_1+0.08v_2

0.06v_1+0.08v_2=0.5568..............(1)

We know that the coefficient of restitution is equal to 1. It is given by :

(v_2-v_1)/(u_1-u_2)=1

(v_2-v_1)/(5.28-3)=1

{v_2-v_1}=2.28.................(2)

On solving equation (1) and (2) to find the values of velocities after collision.

v_1=5.28\ m/s

v_2=3\ m/s

So, the speed of both balls are 5.28 m/s and 3 m/s respectively. Hence, this is the required solution.

Two bullets of the same size, mass and horizontal velocity are fired at identical blocks, only one is made of steel and the other is made of rubber. The steel bullet has a perfectly inelastic collision with the block, while the rubber bullet has an elastic collision. Which bullet is more likely to knock over the block, or are both equally likely to do so? Justify your choice based on physics principles.

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Answer and Explanation:

  • Since we're discussing shots, the significant thing is the way the energy is changed over as there is deceleration of the bullet to a halt when it hits something.
  • Kinetic Energy is relative to mass times speed squared, so in reality, the 2 cases given have practically indistinguishable Kinetic energy. The measure of energy is authoritative, so the two cases will do generally a similar harm given, obviously we look at situations when all the kinetic energy is spent.
  • One contrast that will be effectively obvious is that the weapon in the case of heavy bullet will recoil more.  
  • One can consider energy assimilation as force times separation distance, and energy ingestion as a product of force and time.
  • Henceforth, the heavier yet more slow bullet with a similar energy will venture to every part of a similar separation in the engrossing material, but since of bigger force, will take a more drawn out time doing it.
  • It will along these lines, additionally, give a more noteworthy "kick" to the object that absorbs.

You know that you sound better when you sing in the shower. This has to do with the amplification of frequencies that correspond to the standing-wave resonances of the shower enclosure. A shower enclosure is created by adding glass doors and tile walls to a standard bathtub, so the enclosure has the dimensions of a standard tub, 0.75 m wide and 1.5 m long. Standing sound waves can be set up along either axis of the enclosure. What are the lowest two frequencies that correspond to resonances on each axis of the shower? These frequencies will be especially amplified. Assume a sound speed of 343 m/s.

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Answer: Length axis f= 114.3 Hz, Width axis f=228.67 Hz

Explanation:

We are given that,

Length of tub= 1.5 m

Width of tub= 0.75 m

Sound speed= 343 m/s

Now, we are also given shower is closed.

So, frequency is given as:

f= m* (v)/(2L)

For length axis

Put v= 343 m/s, m=1 and L=1.5 m

f= 1 * (343)/(2*1.5)

f= 114.3 Hz

For next resonant frequency, m=2

f= 2* (343)/(2*1.5)

f= 228.67

For width axis

Put v= 343 m/s, m=1 and L= 0.75 m

f= 1* (343)/(2*0.75)

f= 228.67 Hz

For next frequency, m=2

f= 2* (343)/(2*0.75)

f= 457.34 Hz

Can you guys please help me out

Answers

The answer is A I’m pretty sure it is

"Which gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string?"

Answers

Answer:

the second derivative of y with respect to time gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string

Explanation:

This is because the transverse wave movement of particles take place in direction 90° to direction of movement of the wave (x) itself, so second derivative of y with respect to time (t)is what will be required