# PLEASE HELP ASAP :))) 1. Consider the following standard:Understand that polynomials form a system analogous to the integers, namely, theyare closed under the operations of addition, subtraction, and multiplication; add,subtract, and multiply polynomials.What does it mean to say that polynomials form a system analogous to integers, asrelated to closure?

Answer: It’s 367 tell me if I’m wrong

## Related Questions

HELPPPPPPPP MEEEEEEE

Answer: The first choice should be correct

Step-by-step explanation:

Well I hope this is correct

Option C or they are alternate interior angles is correct.

When two lines are crossed by another line (called the Transversal): Alternate Interior Angles are a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal

￼ Find 5 consecutive whole numbers if it is known that the sum of the squares of the first 3 numbers is equal to the sum of the squares of the last 2 numbers.

so... our numbers... let's say the first one is hmmm "a"
so the second and subsequent are
a
a+1
a+2
a+3
a+4

there, 5 consecutive whole numbers or integers for that matter

now, we know the sum of the square of the first three,
is the same as the sum of the square of the last two

so

do a binomial theorem expansion on those, solve for "a"

A flower delivery driver is 8 1/2 miles west of a city's zoo when she receives a call to pick up flowers from the flower store. The flower store is 14.35 miles east of the zoo. Assume the driver takes the most direct route to the flower store. How will the driver drive to the flower store? Select from the drop-down menus to correctly complete the statement. The driver will drive Choose... miles Choose... .

Step-by-step explanation:

Took the test and got a 100%

Step-by-step explanation:

if she starts out 8.5 mile WEST of a zoo, and has to go 14.35 miles EAST of the zoo, then add both of those numbers, and you get, 22.85 miles

Two vectors are said to be parallel if they point in the same direction or if they point in opposite directions. Part A Are these two vectors parallel? Show your work and explain. Part B Are these two vectors parallel? Show your work and explain.

Knowing that those vectors start at the point (0,0) we can "think" them as lines.

As you may know, two lines are parallel if the slope is the same, then we can find the "slope" of the vectors and see if it is the same.

A) the vectors are: (√3, 1) and (-√3, -1)

You may remember that the way to find the slope of a line that passes through the points (x1, y1) and (x2, y2) is s = (y2 - y1)/(x2 - x1)

Because we know that our vectors also pass through the point (0,0)

then the slopes are:

(√3, 1) -----> s = (1/√3)

(-√3, -1)----> s = (-1/-√3) =  (1/√3)

The slope is the same, so the vectors are parallel.

Part B:

The vectors are: (2, 3) and (-3, -2)

the slopes are:

(2, 3) -----> s = 3/2

(-3, -2)----> s = -2/-3 = 2/3

the slopes are different, so the vectors are not parallel.

∥v∥=√((6)^2+(-8)^2)=√(36+64)=√100=10. Dividing v by its magnitude, we get the unit vector u=(v/∥v∥)=(6i−8j)/10=(3/5)i−(4/5)j. Therefore, two unit vectors parallel to v are (3/5)i−(4/5)j and −(3/5)i+(4/5)j.

a. Two unit vectors parallel to v=6i−8j can be found by dividing the vector v by its magnitude. The magnitude of v can be calculated using the formula ∥v∥=√(v1^2+v2^2), where v1 and v2 are the components of v in the x and y directions, respectively. In this case, v1=6 and v2=−8. Thus,

b. To find the value of b when v=⟨1/3,b⟩ is a unit vector, we need to calculate the magnitude of v and set it equal to 1. The magnitude of v is given by ∥v∥=√((1/3)^2+b^2). Setting this equal to 1, we have √((1/3)^2+b^2)=1. Squaring both sides of the equation, we get (1/3)^2+b^2=1. Simplifying, we have 1/9+b^2=1. Rearranging the equation, we find b^2=8/9. Taking the square root of both sides, we get b=±(2√2)/3. Therefore, the value of b when v is a unit vector is b=(2√2)/3 or b=−(2√2)/3.

c. To find all values of a such that w=ai−a/3j is a unit vector, we need to calculate the magnitude of w and set it equal to 1. The magnitude of w is given by ∥w∥=√(a^2+(-a/3)^2). Setting this equal to 1, we have √(a^2+(-a/3)^2)=1. Simplifying, we get a^2+(a^2/9)=1. Combining like terms, we have (10/9)a^2=1. Dividing both sides by 10/9, we get a^2=(9/10). Taking the square root of both sides, we have a=±√(9/10). Therefore, the values of a such that w is a unit vector are a=√(9/10) or a=−√(9/10).

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HELP PLEZ TRIGONOMETRY!

Solution:

Given that we have to simplify:

---- eqn 1

We know that,

Substitute the above identity in eqn 1

Simplify the above expression

------- eqn 2

By the trignometric identity,

Substitute the above identity in eqn 2

Cancel the common factors in numerator and denominator

Thus the simplified expression is:

C

Step-by-step explanation:

3x+2-x>8

2x+2>8

2x>8-2

2x>6

x>3