I need soon this is due at 10:30 pm its curently 6:00 pm
What is parasitism?


Answer 1


the practice of living as a parasite in or on another organism.

Hope this HELPS!!!


Related Questions

Sulfonation of naphthalene, C10H8, results in two products. One product is kinetically favored and predominates in the beginning of the reaction. Because the reaction is reversible, eventually the kinetically slower but thermodynamically favored product predominates. Draw the structure of these two products. (The naphthalene ring is already drawn for you. Do not change the double bond configuration in the given structures.)
Convert a distance of 150 ft to its equivalent in cm​
If a 0.2g of oil consumed 1ml of sodium thiosulphate, calculate its iodine value and classify the oil?
Solve for x . 875 = 5 x 3 Express the answer to the hundredths place (i.e., two digits after the decimal point).
An element is to a __ as an organ is to a ___

It is possible for gases in the atmosphere to change the behavior of energy on earth. Agree or disagree


The green house gases in the atmosphere can change the behavior of energy on earth. Thus i agree with this statement.

What is green house effect?

The green house effect is defined as a process by which the radiations from the sun are absorbed by the green house gases like methane, Chloro fluoro carbons and not reflected back into the space. This makes the surface as insulator and prevents it from freezing.

Due to the increased level of green house gases, the temperature of the earth increases considerably and thereby causes global warming, depletion of ozone layer, smog and air pollution, etc.

It is the natural green house effect which affect the behaviour of heat energy radiated by the sun. The green house gases never let the radiations escape from the earth and increase the surface temperature of earth. This leads to global warming.

Thus green house gases affects the solar energy.

To know more about Global warming, visit;




I agree


because the sunlight passes through the atmosphere and is absorbed by earth's surface.

When 1-iodo-1-methylcyclohexane is treated with NaOCH2CH3 as the base, the more highly substituted alkene product predominates. When KOC(CH3)3 is used as the base, the less highly substituted alkene predominates. Give the structures of the two products and offer an explanation.



See explanation


In this case, we have 2 types of reactions. CH_3CH_2ONa is a strong base but only has 2 carbons therefore we will have less steric hindrance in this base. So,  the base can remove hydrogens that are bonded on carbons 1 or 6, therefore, we will have a more substituted alkene (1-methylcyclohex-1-ene).

For the  KOC(CH_3)_3 we have more steric hindrance. So, we can remove only the hydrogens from carbon 7 and we will produce a less substituted alkene (methylenecyclohexane).

See figure 1

I hope it helps!

What would be the effect on the observed melting point of sample were poorly packed?


if a sample is packed poorly, the sample will not heat evenly and will take longer to melt.

Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V

An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:


Calculate the cell potential under these nonstandard concentrations.

Express the cell potential to two decimal places and include the appropriate units.



Cell potential under non standard concentration is 4.09 v


To solve this problem we need to use Nernst Equation because concentrations of the components of the chemical reactions are differents to 1 M (normal conditions:  1 M , 1 atm).

Nernst equation at 25ºC is:

E = E^(0) - [((0.0592)/(n) · log Q)]


E: Cell potential (non standard conditions)

E^(0) = Cell potential (standard conditions)

n: Number of electrons transfered in the redox reaction

Q: Reaction coefficient (we are going to get it from the balanced chemical reaction)

For example, consider the following general chemical reaction:

aA + bB --> cC + dD


a, b, c, d: coefficient of balanced chemical reaction

A,B,C,D: chemical compounds in the reaction.

Using the previous general reaction, expression of Q is:

Q = (C^(c) * D^(d) )/(A^(a)*B^(b)  )

Previous information is basic to solve this problem. Let´s see the Nernst equation, we need to know: E^(0), n and Q

Let´s  calcule potential in nomal conditions  (E^(0)):

1. We need to know half-reactions (oxidation and reduction), we take them from the chemical reaction given in this exercise:

Half-reactions:                               Eo (v):

(VO_(2))^(2+) + e- --> (VO_(2))^(+)                -0.23

Ni --> Ni^(2+)  + 2 e-                   +0.99    

Balancing each half-reaction, first we are going to balance mass and then we will balance charge in each half-reaction and then charge between half-reactions:

Half-reactions:                                                                Eo (v):

2 * [ (VO_(2))^(2+) + e- --> (VO_(2))^(+)]                                          -0.23

1 * [Ni --> Ni^(2+)  + 2 e-     ]                                         +0.99  

-------------------------------------------------------------------         -------------

2 (VO_(2))^(2+) + 2e- + Ni  --> 2(VO_(2))^(+) + Ni^(2+) + 2e-              0.76 v  


Then global balanced chemical reaction is:

2 (VO_(2))^(2+) + Ni  --> 2(VO_(2))^(+) + Ni^(2+)      

 and the potential in nomal conditions is:

E^(0) = 0.76 v

Also from the balanced reaction, we got number of electons transfered:

n = 2

2. Calculate Q:

Now using previous information, we can establish Q expression and we can calculate its value:

Q = ([(VO_(2)+]^(2)* [Ni^(2+)   )/([VO_(2+)]^(2) * Ni )]

From the exercise we know:

[VO_(2) ^(2+)] = 2.5 M

[VO_(2)+] = 0.083 M

[Ni^(2+)] = 2.5 M

[Ni] = 1 M, it is a pure solid, so its activity in Q is unit (1). It is also applied for pure liquids.

Q = ((2.5)^(2)* 2.5 )/((0.083)^(2) * 1) = 2,268.11

3. Use Nernst equation:

Finally, we replace all these results in the Nernst equation:

E = E^(0) - ((0.0592)/(n) - log Q)\n  \nE = 0.76 - ((0.0592)/(2)-log (2,268.11) \nE = 0.76 - (0.0296 - 3.36)\nE = 4.09 v

Cell potential under non standard concentration is 4.09 v

Final answer:

To calculate the cell potential under nonstandard conditions, we need to apply the Nernst Equation. This involves finding the reaction quotient (Q) from the given concentrations and then subtracting a value derived from Q and the number of electrons transferred, from the cell potential under standard conditions.


For calculating the cell potential under nonstandard conditions for an electrochemical cell, we need to use the Nernst equation. In this case, the Nernst Equation is Ecell = E∘cell - (0.0592/n) * logQ, where Q, the reaction quotient, is the ratio of the concentrations of the products to the reactants raised to their stoichiometric coefficients.

Given the half-cell reduction potentials, we can calculate the cell potential under standard conditions (E°cell) by subtracting the potential of the anode from the potential of the cathode (E°cell = Ecathode - Eanode = 0.99V - (-0.23V), resulting in E°cell = 1.22V.

Next, Q = [Ni2+]/([VO2+]×[H+]²), substituting the given concentrations, Q = (2.5)/(0.083×1.1²).

After calculating Q, we substitute all known values into the Nernst Equation and solve for Ecell. Hence, the cell potential under these nonstandard conditions can be calculated.

Learn more about Nernst Equation here:



How did altitude affect the freezing, melting, and boiling points of water?



First of all altitude, is the height of anything especially above sea level. So when your at different altitudes its hotter or colder. Like outside the higher that water gets it freezes cause it going all the way up to the cold mountains and as you go down in altitude depending on the day it gets warmer and evaporates.

Sorry, I don't know if I explained it well, hope I helped you out! :)

For the following reaction at equilibrium, which gives a change that will shift the position of equilibrium to favor formation of more products? 2NOBr(g) 2NO(g) + Br 2(g), ΔHº rxn = 30 kJ/mol



Based on the given reaction, it is evident that the reaction is endothermic as indicated by a positive sign of enthalpy of reaction. Thus, it can be stated that the favoring of the forward reaction will take place by upsurging the temperature of the reaction mixture.  

Apart from this, based on Le Chatelier’s principle, any modification in the quantity of any species is performed at equilibrium and the reaction will move in such an orientation so that the effect of the change gets minimized. Therefore, a slight enhancement in the concentration of the reactant will accelerate the reaction in the forward direction and hence more formation of the product takes place.