Answer:

A speed skater moving across** frictionless** ice at 8.8 m/s hits a 6.0 m -wide patch of rough ice. Her **acceleration** on the rough ice is -3.65 m/s².

v² - u² = 2 a ∆x, where u and v are** initial **and final velocities, respectively; a is **acceleration. **

and ∆x is the distance **traveled **(because the skater moves in only one **direction).**

Thus, (5.8 m/s)² - (8.8 m/s)² = 2 a (6.0 m)

a = ((5.8 m/s)² - (8.8 m/s)²) / (12 m)

**a = -3.65 m/s².**

Thus, A speed skater moving across** frictionless** ice at 8.8 m/s hits a 6.0 m -wide patch of rough ice. Her **acceleration** on the rough ice is -3.65 m/s².

Learn more about** Acceleration,** refer to the link:

#SPJ3

Answer:

Recall that

*v*² - *u*² = 2 *a* ∆*x*

where *u* and *v* are initial and final velocities, respectively; *a* is acceleration; and ∆*x* is the distance traveled (because the skater moves in only one direction).

So we have

(5.8 m/s)² - (8.8 m/s)² = 2 *a* (6.0 m)

*a* = ((5.8 m/s)² - (8.8 m/s)²) / (12 m)

*a*** = -3.65 m/s²**

A 81.0 kg diver falls from rest into a swimming pool from a height of 4.70 m. It takes 1.84 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

At a stop light, a truck traveling at 10.5 m/s passes a car as it starts from rest. The truck travels at constant velocity and the car accelerates at 3 m/s2. How much time does the car take to catch up to the truck?

According to the Heisenberg uncertainty principle, quantum mechanics differs from classical mechanics in that: Select the correct answer below: Quantum mechanics involves particles that do not move. It is impossible to calculate with accuracy both the position and momentum of particles in classical mechanics. The measurement of an observable quantity in the quantum domain inherently changes the value of that quantity. All of the above

A student and his lab partner create a single slit by carefully aligning two razor blades to a separation of 0.530 mm. When a helium–neon laser at 543 nm illuminates the slit, a diffraction pattern is observed on a screen 1.55 m beyond the slit. Calculate the angle θdark to the first minimum in the diffraction pattern and the width of the central maximum.

why did thomson's from experermenting with cathode rays cause a big change in scientific thought about atoms

At a stop light, a truck traveling at 10.5 m/s passes a car as it starts from rest. The truck travels at constant velocity and the car accelerates at 3 m/s2. How much time does the car take to catch up to the truck?

According to the Heisenberg uncertainty principle, quantum mechanics differs from classical mechanics in that: Select the correct answer below: Quantum mechanics involves particles that do not move. It is impossible to calculate with accuracy both the position and momentum of particles in classical mechanics. The measurement of an observable quantity in the quantum domain inherently changes the value of that quantity. All of the above

A student and his lab partner create a single slit by carefully aligning two razor blades to a separation of 0.530 mm. When a helium–neon laser at 543 nm illuminates the slit, a diffraction pattern is observed on a screen 1.55 m beyond the slit. Calculate the angle θdark to the first minimum in the diffraction pattern and the width of the central maximum.

why did thomson's from experermenting with cathode rays cause a big change in scientific thought about atoms

**Answer:**

s = 6.25 10⁻²² m

**Explanation:**

Polarizability is the separation of electric charges in a structure, in the case of the atom it is the result of the separation of positive charges in the nucleus and the electrons in their orbits, macroscopically it is approximated by

p = q s

s = p / q

let's calculate

s = 1 10⁻⁴⁰ / 1.6 10⁻¹⁹

s = 0.625 10⁻²¹ m

s = 6.25 10⁻²² m

We see that the result is much smaller than the size of the atom, therefore this simplistic model cannot be taken to an atomic scale.

Fastener because a fastener is something that connects to objects and usually can come apart but can also be permanent

**Answer:**

**- z direction**

**Explanation:**

To find the direction of the magnetic field, you take into account that the magnetic force over a charge, is given by the following cross product:

(1)

F_B: magnetic force

q: charge of the particle

v: velocity of the charge

B: magnetic field

In this case you have that the electron is moving along x-axis. You can consider this direction as the **^i** direction. The electron experiences a magnetic deflection in the -y direction, that is, in the **-^j **direction.

By the cross products between unit vectors, you have that:

**-^j = ^i X ^k**

That is, the cross product between two vectors, one in the +x direction, and another one in the +z direction, generates a vector in the -y direction. However, it is necessary to take into account that the negative charge of the electron change the sign of the result of the cross product, which demands that the second vector is in the -z direction. That is:

** -^i X -k^ = ^i X ^k = - ^j**

**Hence, the direction of the magnetic field is in the -z direction**

B) 5 J

C) 50 J

D) 1 J

E) 10 J

**Answer:**

**option C**

**Explanation:**

given,

Force on the object = 10 N

distance of push = 5 m

Work done = ?

we know,

work done is equal to Force into displacement.

W = F . s

W = 10 x 5

**W = 50 J **

Work done by the object when 10 N force is applied is equal to 50 J

Hence, the correct answer is **option C**

The work done on an object when a force of 10 N pushes it 5 m is 50 Joules, calculated by multiplying the force and the displacement. So, the correct option is C.

The question is asking about **work**, which in physics is the result of a force causing a displacement. The formula for work is defined as the product of the force (in Newtons) and the displacement (in meters) the force causes. If a **force of 10 N** pushes an object a distance of **5 m**, the work done is calculated by multiplying the force and the displacement (10 N * 5 m), yielding **50 Joules** of work.

Therefore, the correct answer is 50 J (C).

#SPJ6

(a) The **acceleration **of the bird is . The negative sign indicated the opposite direction of **motion**. (b) The final speed is .

Given:

Initial speed,

Final speed,

Time,

The acceleration can be computed from the **velocities **and time. The standard unit of acceleration is a meter per second square.

(a)

The acceleration is computed as:

Hence, the acceleration of the bird is . The negative sign indicated the opposite direction of motion.

(b)

The final **speed **as the given time can be computed from the first equation of motion. The first equation of motion gives the relation between final and initial speed, acceleration, and **time**.

The **final speed **at time 1.2 seconds is equal to:

Hence, the final **speed **is .

To learn more about **Acceleration**, here:

#SPJ12

False

A pressure antinode in a sound wave is not a region of high pressure, while a pressure node is not a region of low pressure.

The answer is false

The answer is false

A pressure antinode in a sound wave is indeed a region of high pressure, while a pressure node is a region of low pressure. These definitions hold** true for all types of waves.**

That's true. In terms of sound waves, a **pressure antinode** is a region of high pressure, while a **pressure node** is a region of low pressure. **This is true for all types of waves, **not only sound waves. In essence, a wave moves through a medium (in case of a sound wave, that medium is typically air) by creating areas of high and low pressure - the high pressure areas are called antinodes, and **the low pressure areas are called nodes.**

#SPJ2