What is the answer to a
What is the answer to a - 1

Answers

Answer 1
Answer:

Answer: a = b*r/n

Step-by-step explanation: Hope this helps :^)


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The sum of x and -15 is 23

Answers

Answer: x=38

Step-by-step explanation:

x+(-15)=23

x-15=23

+15  +15

x=38

When there is a positive and negative sign the negative sign cancels the positive sign.

Answer:

38

Step-by-step explanation:

23+15=38 because in order to get 23 from -15 a negative number you need to have 38 to silence the -15.

Find the value of X.

Answers

2+3x=62

3x=60

x=20

Hope this helps! Brainliest? :D

The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0, 0.3, 0.4, and 0.6, respectively. The probabilities of no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0.8, 0.02, 0.08, and 0.1, respectively. a. Determine the probability of high ink viscosity given poor print quality.
b. Given poor print quality, what problem is most likely?

Answers

Answer and explanation:

Given : The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0, 0.3, 0.4, and 0.6, respectively.

The probabilities of no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0.8, 0.02, 0.08, and 0.1, respectively.

Let the event E denote the poor print quality.

Let the event A be the no printer problem i.e. P(A)=0.8

Let the event B be the misaligned paper i.e. P(B)=0.02

Let the event C be the high ink viscosity i.e. P(C)=0.08

Let the event D be the printer-head debris i.e. P(D)=0.1

and the probabilities of poor print quality given printers are

P(E|A)=0,\ P(E|B)=0.3,\ P(E|C)=0.4,\ P(E|D)=0.6

First we calculate the probability that print quality is poor,

P(E)=P(A)P(E|A)+P(B)P(E|B)+P(C)P(E|C)+P(D)P(E|D)

P(E)=(0)(0.8)+(0.3)(0.02)+(0.4)(0.08)+(0.6)(0.1)

P(E)=0+0.006+0.032+0.06

P(E)=0.098

a. Determine the probability of high ink viscosity given poor print quality.

P(C|E)=(P(E|C)P(C))/(P(E))

P(C|E)=(0.4* 0.08)/(0.098)

P(C|E)=(0.032)/(0.098)

P(C|E)=0.3265

b. Given poor print quality, what problem is most likely?

Probability of no printer problem given poor quality is

P(A|E)=(P(E|A)P(A))/(P(E))

P(A|E)=(0* 0.8)/(0.098)

P(A|E)=(0)/(0.098)

P(A|E)=0

Probability of misaligned paper given poor quality is

P(B|E)=(P(E|B)P(B))/(P(E))

P(B|E)=(0.3* 0.02)/(0.098)

P(B|E)=(0.006)/(0.098)

P(B|E)=0.0612

Probability of printer-head debris given poor quality is

P(D|E)=(P(E|D)P(D))/(P(E))

P(D|E)=(0.6* 0.1)/(0.098)

P(D|E)=(0.06)/(0.098)

P(D|E)=0.6122

From the above conditional probabilities,

The printer-head debris problem is most likely given that print quality is poor.

Answer:

Answer of Part(a) is 16/49

and Answer of Part(b) is Printer-head debris

Step-by-step explanation:

Answer is in the following attachment

(x^2-6) (x+6) + 25
plz someone answer correctly

Answers

Answer:

x^3+6x^2-6x-11

Step-by-step explanation:

PLEASE GIVE BRAINLIEST

(x² - 6) (x + 6) + 25

x²(x + 6) + -6(x + 6) + 25

x³ + 6x² - 6x - 36 + 25

x³ + 6x² - 6x - 11

What is the square root of -1?

Answers

It is i

......................

Need Assistance With This
*Please Show Work*​

Answers

Answer:

a =7.5

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2+ b^2 = c^2  where a and b are the legs and c is the hypotenuse

a^2 + 10 ^2 = 12.5^2

a^2 + 100  =156.25

Subtract 100 from each side

a^2 = 56.25

Take the square root of each side

sqrt(a^2) = sqrt( 56.25)

a =7.5