Which is a characteristic of thermal energy transfer through convection

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Answer 1
Answer:

Answer:  The thermal energy transfer is When a fluid, such as air or a liquid, is heated and then travels away from the source, it carries the thermal energy along.

Explanation: heat transfer is called convection.  hopefully this was helpful.


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A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse

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The amount of work done per second by the horse exerting a force of 1800 N on a wagon moving with a speed of 0.4 m/s  is 720 J/s.

What is power?

Power is the workdone by a body in one second.

To calculate the work done by the horse in one seconds, we use the formula below

Formula:

  • P = Fv................ Equation 1

Where:

  • P = work done on the horse in one second
  • F = Force of the horse
  • v = Velocity of the wagon

From the question,

Given:

  • F = 1800 N
  • v = 0.4 m/s

Substitute these values into equation 1

  • P = 1800×0.4
  • P = 720 J/s

Hence, the amount of work done per second by the horse is 720 J/s.

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Complete question: A wagon is pulled at a speed of 0.40 m/s by a horse exerting 1800 Newtons of horizontal Force. how much work was done by the horse per second.

What is an atomic nucleus​

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Answer:

The atomic nucleus is the small, dense region consisting of protons and neutrons at the center of an atom, discovered in 1911 by Ernest Rutherford based on the 1909 Geiger–Marsden gold foil experiment.

Explanation:

An isotropic point source emits light at wavelength 500 nm, at the rate of 185 W. A light detector is positioned 380 m from the source. What is the maximum rate ∂B/∂t at which the magnetic component of the light changes with time at the detector's location?

Answers

Answer:

(dB)/(dt) = 3.49 *10^(6) \ \ T/s

Explanation:

Given that

An isotropic point source emits light at a wavelength \lambda = 500 nm

Power = 185 W

Radius = 380 m

Let's first calculate the The intensity  of the wave , which is = (Power )/(Area)

= (Power)/(4 \pi r ^2)

=  (185 \ W)/( 4 \pi (380)^2)

= 1.0195*10^(-4) \ W/m^2

Now;

The amplitude of the magnetic field is calculated afterwards by using poynting vector

i.e

I = ((c)/(2 \mu_0 ))B_(max^2)

B_(max^2) =  ((2 \mu_0   I)/( c))

B_(max^2) =  ((2 *4 \pi *10^(-7)*1.0195*10^(-4))/( 3*10^8))

B_(max^2) = 8.5409*10^(-19)

B_(max) = \sqrt {8.5409*10^(-19)}

B_(max) = 9.242*10^(-10)

The magnetic field wave equation can now be expressed as;

B = B_(max) sin (kx - \omega t)

Taking the differentiation

(dB)/(dt)= - \omega B_(max) \ cos ( kx - \omega t)

The maximum value ;

(dB)/(dt) = \omega B _(max)

where ;

\omega = 2 \pi f\n\omega = (2 \pi c)/(\lambda)

then

(dB)/(dt) = (2 \pi c)/(\lambda) B _(max)

(dB)/(dt) = (2 \pi 3*10^8*9.242*10^(-10))/(500*10^(-9))

(dB)/(dt) = 3484751.917

(dB)/(dt) = 3.49 *10^(6) \ \ T/s

The maximum rate(∂B/∂t) at which the magnetic component of the light changes with time at the detector's location is approximately6.8 x 10^9 Tesla per second (T/s).

To find the maximum rate at which the magnetic component of the light changes with time at the detector's location, you can use the formula for the rate of change of magnetic field due to an electromagnetic wave. The formula is given by:

∂B/∂t = (2π / λ) * E * c

Where:

∂B/∂tis the rate of change of the magnetic field.

λ is the wavelength of the light.

E is the electric field strength.

c is the speed of light in a vacuum, approximately3 x 10^8 m/s.

You have the wavelength (λ) as 500 nm, which is 500 x 10^-9 meters, and the electric field strength (E) can be calculated using the power (P) and the distance (r) from the source. The power emitted by the source is 185 W, and the distance from the source to the detector is 380 m.

First, calculate the electric field strength (E):

E = sqrt(P / (2π * r^2))

E = sqrt(185 W / (2π * (380 m)^2))

E = sqrt(185 W / (2π * 144400 m^2))

E ≈ 6.325 x 10^-5 N/C

Now, you can calculate the rate of change of the magnetic field:

∂B/∂t = (2π / λ) * E * c

∂B/∂t = (2π / (500 x 10^-9 m)) * (6.325 x 10^-5 N/C) * (3 x 10^8 m/s)

∂B/∂t ≈ (3.77 x 10^15 Hz) * (6.325 x 10^-5 N/C) * (3 x 10^8 m/s)

∂B/∂t ≈ 6.8 x 10^9 T/s

So, the maximum rate at which the magnetic component of the light changes with time at the detector's location is approximately6.8 x 10^9Tesla per second (T/s).

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A certain lightning bolt moves 40 C of charge. How many fundamental units of charge |qe| is this?

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Answer to A certain lightning bolt moves 40.0 C of charge. How many fundamental units of charge | qe | is this? . ... charge, N is the total number of electron or protons that constitute total charge Q.

Which of the following is a description of the Remote Associates Test (RAT)?

Answers

Answer:

The description is outlined throughout the clarification section following, and according to the given word.

Explanation:

  • Throughout the 1960s, Sarnoff Mednick created the RAT as a tool used for testing imaginative convergent thought. Through each RAT test query lists a set of terms, which demands that we have a single additional term that will tie any of the others around.  
  • Those other words may also be related in something like a variety of ways, such as through creating a compound word or perhaps a semantic connexon.

What sound frequency could a human detect

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Answer:

People can hear sounds at frequencies from about 20 Hz to 20,000 Hz,

20 Hz up to 20,000 Hz

Brain pls