PLEASE HELP QUICK I NEED THIS DONE FAST
PLEASE HELP QUICK I NEED THIS DONE FAST - 1

Answers

Answer 1
Answer: The first one: This answer has no solution because it can be rewritten as 0=0

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Geometry, 1 question

Answers

It’s b trust me bro

What does the graph tell us about the humidity in any given location on Earth?

Answers

Answer:

A

Step-by-step explanation:

Answer: A.) The warmer the air temperature, the greater the humidity.

Step-by-step explanation: This is simply what the graph is conveying. As you can see, the line goes up with water vapor and temperature signifying that when the temperature goes up so does the humidity.

What’s the simplified fraction is equal to 0.17

Answers

Answer:

17/100

Step-by-step explanation:

Step 1:

0.17 = 17/100

Answer:

17/100

Hope This Helps :)

Does Anyone Know This?​

Answers

Answer:

Pretty sure its B

Step-by-step explanation:

Set up a double integral for calculating the flux of the vector field ????⃗ (????⃗ )=????⃗ , where ????⃗ =⟨x,y,z⟩, through the part of the upward oriented surface z=3(x2+y2) that lies above the disk x2+y2≤25.

Answers

Answer:

-937.5π

Step-by-step explanation:

F (r) = r = (x, y, z) the surface equation z = 3(x^2 + y^2) z_x = 6x, z_y = 6y the normal vector n = (- z_x, - z_y, 1) = (- 6x, - 6y, 1)

Thus, flux ∫∫s F · dS is given as;

∫∫ <x, y, z> · <-z_x, -z_y, 1> dA

=∫∫ <x, y, 3x² + 3y²> · <-6x, -6y, 1>dA , since z = 3x² + 3y²

Thus, flux is;

= ∫∫ -3(x² + y²) dA.

Since the region of integration is bounded by x² + y² = 25, let's convert to polar coordinates as follows:

∫(θ = 0 to 2π) ∫(r = 0 to 5) -3r² (r·dr·dθ)

= 2π ∫(r = 0 to 5) -3r³ dr

= -(6/4)πr^4 {for r = 0 to 5}

= -(6/4)5⁴π - (6/4)0⁴π

= -937.5π

Final answer:

To set up a doubleintegral for calculating the flux of the vector field through the given surface, parameterize the surface using the equation provided and the given condition. Calculate the cross product of the partial derivatives of x and y to find the normal vector. Finally, set up the double integral for the flux using the vector field and the normal vector.

Explanation:

To set up a double integral for calculating the flux of the vector field through the given surface, we first need to parameterize the surface. Given the equation of the surface z = 3(x^2 + y^2) and the condition x^2 + y^2 ≤ 25, we can parameterize the surface as follows:

x = rcosθ, y = rsinθ, z = 3r^2

We can now calculate the cross product of the partialderivatives of x and y to find the normal vector, which is: n = (3rcosθ, 3rsinθ, 1)

Finally, the double integral for calculating the flux through the surface is:

∬ F · n dA = ∬ (x, y, z) · (3rcosθ, 3rsinθ, 1) dA

Learn more about Calculating flux of a vector field here:

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N - 4 = 3n + 6 Yikesss

Answers

Answer: n=-5

Step-by-step explanation:

Answer:

N=-5

Step-by-step explanation:

N - 4 = 3n + 6

Add 4 to both sides

n-4+4=3n+6+4

Simplify

n=3n+10

subtract 3n from both sides

n-3n=3n+10-3n

Simplify

-2n=10

Divide -2 from both sides

-2n/-2=10/-2

Simplify

n=-5