Answer: The first one: This answer has no solution because it can be rewritten as 0=0

## Related Questions

Geometry, 1 question

It’s b trust me bro

What does the graph tell us about the humidity in any given location on Earth?

A

Step-by-step explanation:

Answer: A.) The warmer the air temperature, the greater the humidity.

Step-by-step explanation: This is simply what the graph is conveying. As you can see, the line goes up with water vapor and temperature signifying that when the temperature goes up so does the humidity.

What’s the simplified fraction is equal to 0.17

17/100

Step-by-step explanation:

Step 1:

0.17 = 17/100

17/100

Hope This Helps :)

Does Anyone Know This?​

Pretty sure its B

Step-by-step explanation:

Set up a double integral for calculating the flux of the vector field ????⃗ (????⃗ )=????⃗ , where ????⃗ =⟨x,y,z⟩, through the part of the upward oriented surface z=3(x2+y2) that lies above the disk x2+y2≤25.

-937.5π

Step-by-step explanation:

F (r) = r = (x, y, z) the surface equation z = 3(x^2 + y^2) z_x = 6x, z_y = 6y the normal vector n = (- z_x, - z_y, 1) = (- 6x, - 6y, 1)

Thus, flux ∫∫s F · dS is given as;

∫∫ <x, y, z> · <-z_x, -z_y, 1> dA

=∫∫ <x, y, 3x² + 3y²> · <-6x, -6y, 1>dA , since z = 3x² + 3y²

Thus, flux is;

= ∫∫ -3(x² + y²) dA.

Since the region of integration is bounded by x² + y² = 25, let's convert to polar coordinates as follows:

∫(θ = 0 to 2π) ∫(r = 0 to 5) -3r² (r·dr·dθ)

= 2π ∫(r = 0 to 5) -3r³ dr

= -(6/4)πr^4 {for r = 0 to 5}

= -(6/4)5⁴π - (6/4)0⁴π

= -937.5π

To set up a doubleintegral for calculating the flux of the vector field through the given surface, parameterize the surface using the equation provided and the given condition. Calculate the cross product of the partial derivatives of x and y to find the normal vector. Finally, set up the double integral for the flux using the vector field and the normal vector.

### Explanation:

To set up a double integral for calculating the flux of the vector field through the given surface, we first need to parameterize the surface. Given the equation of the surface z = 3(x^2 + y^2) and the condition x^2 + y^2 ≤ 25, we can parameterize the surface as follows:

x = rcosθ, y = rsinθ, z = 3r^2

We can now calculate the cross product of the partialderivatives of x and y to find the normal vector, which is: n = (3rcosθ, 3rsinθ, 1)

Finally, the double integral for calculating the flux through the surface is:

∬ F · n dA = ∬ (x, y, z) · (3rcosθ, 3rsinθ, 1) dA

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N - 4 = 3n + 6 Yikesss

Step-by-step explanation:

N=-5

Step-by-step explanation:

N - 4 = 3n + 6

n-4+4=3n+6+4

Simplify

n=3n+10

subtract 3n from both sides

n-3n=3n+10-3n

Simplify

-2n=10

Divide -2 from both sides

-2n/-2=10/-2

Simplify

n=-5