Answer:

**Answer:**

A. 20 B. 25

**Step-by-step explanation:**

A. Perimeter equals the all the side lengths added together, so 5+5+5+5=20

B. Area equals (for a square) two side lengths multiplied by one another, so 5x5=25

Is (0,5) a solution to the equation y=2x?

Use Gauss's approach to find the following sum (do not use formulas):5+11+17+23...+83

What pair of numbers shows a common factor and a common multiple of 15 and 18?

Let C be the unit circle in the xy-plane, oriented counterclockwise as seen from above. The divergence of the vector field F~ = (z, x, y) is zero, and as a result the flux through every surface with boundary C should be the same. Confirm that this is the case with the upper half of the unit sphere, the lower half of the unit sphere, and the unit disk in the xy-plane

What are the quotient and remainder of (3x^4+ 2x^2 - 6x + 1) = (x + 1)

Use Gauss's approach to find the following sum (do not use formulas):5+11+17+23...+83

What pair of numbers shows a common factor and a common multiple of 15 and 18?

Let C be the unit circle in the xy-plane, oriented counterclockwise as seen from above. The divergence of the vector field F~ = (z, x, y) is zero, and as a result the flux through every surface with boundary C should be the same. Confirm that this is the case with the upper half of the unit sphere, the lower half of the unit sphere, and the unit disk in the xy-plane

What are the quotient and remainder of (3x^4+ 2x^2 - 6x + 1) = (x + 1)

98

76

100

88

82

70

What is the range of their test scores?

The answer is 30. Range: largest number - smallest number = range

The **measure **of each side of the cube will be **15 **inches.

The **Volume **of the cone is the amount of quantity, which is obtained in the 3-dimensional space. **Volume **is defined as the space **occupied** by an object in the three-Dimensions. All three parameters are required for the **volume **like length, width, and height of the **cube **or Cuboid

The cube has all the **sides **equal means that the length, width, and height of the cube will be the same. Let's **suppose **the length, width, and **height **of the cube is a.

The **volume **of a cube will be given by the **formula**:-

Volume = side³ = a³

a³ = 3375

a = ∛3375

a = ∛( 15 x 15 x 15 )

a = 15 cubic inches.

Therefore, the **measure **of each side of the cube will be **15 **inches.

To know more about **volume **follow

#SPJ5

**Answer:**

l=w=h=15

**Step-by-step explanation:**

Volume of a cube= l*w*h

where l=w=h

15*15*15=3375

Hope this helps ;) ❤❤❤

**Answer:**

**Step-by-step explanation:**

Note that we have in total 18 items. Even though we are given information regarding the amounts of items per type, the general question asks the total number of ways in which you can pick 5 out of the 18 objects, without any restriction on the type of chosen items. Therefore, the information regarding the type is unnecessary to solve the problem.

Recall that given n elements, the different ways of choosing k elements out of n is given by the binomial coefficient .

Therefore, in this case the total number of ways is just

**Answer:**

Given:

Number of objects: n = 18

Type A objects: 10

Type B objects: 5

Type C objects: 3

To find:

In how many ways can you Pick 5 of the 18 objects (order does not matter)

**Step-by-step explanation:**

When the order does not matter we use Combination.

Formula to calculate combination:

C(n,r) = n! / r! ( n - r )!

n = 18

r = 5

Putting the values:

C(n,r)

= C(18,5)

= 18! / 5! ( 18 - 5 )!

= 18! / 5! ( 13 )!

**=** ( 18 * 17 * 16 * 15 * 14 * 13 * 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 ) **/** ( 5 * 4 * 3 * 2 * 1 ) ***** (13 * 12 * 11 * 10 *9* 8 * 7 *6 * 5 * 4 * 3 * 2 *1 )

Cancel 13!

= (18 * 17 * 16 * 15 * 14 ) / ( 5 * 4 * 3 * 2 * 1 )

= 1028160 / 120

**= 8568**

So you can pick 5 of the 18 objects in 8568 ways.

**Answer:**

**y = 64°**

**Step-by-step explanation:**

From the picture attached,

m(∠E) = 90°

m(∠E) = m(∠D)

m(∠B) + 67° = 180° [pair of linear angles]

m(∠B) = 113°

m(∠C) + 75° = 180°

m(∠C) = 180° - 75°

= 105°

Since, sum of interior angles of a polygon = (n - 2) × 180°

Here, n = number of sides

For n = 5,

Sum of interior angles = (5 - 2) × 180°

= 540°

m(∠A) + m(∠B) + m(∠C) + m(∠D) + m(∠E) = 540°

m(∠A) + 113° + 105° + m(∠D) + 90° = 540°

(m∠D) + m(∠D) = 540 - 308 [Since, m(∠A) = m(∠D)]

2(m∠D) = 232

**m(∠D) = 116°**

m(∠D) + y° = 180° [Linear pair of angles]

116 + y = 180

**y = 64°**

I can’t see the whole problem but The triangle is SAS and it it is translated

**Answer:**

79.24% probability that the average weight of rock and soil brought back by these rovers will be between 48 pounds and 52 pounds

We use the sampling distribution of the sample means of size 10 to solve this question, by the Central Limit Theorem. They are normally distributed with mean 50 and standard deviation 1.58.

**Step-by-step explanation:**

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

**Normal probability distribution**

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

**Central Limit Theorem**

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

**In this problem, we have that:**

**What is the probability that the average weight of rock and soil brought back by these rovers will be between 48 pounds and 52 pounds? **

This is the pvalue of Z when X = 52 subtracted by the pvalue of Z when X = 48. So

**X = 52**

By the Central Limit Theorem

has a pvalue of 0.8962

**X = 48**

has a pvalue of 0.1038

0.8962 - 0.1038 = 0.7924

79.24% probability that the average weight of rock and soil brought back by these rovers will be between 48 pounds and 52 pounds

**What sampling distribution should we use to compute this probability?**

We use the sampling distribution of the sample means of size 10 to solve this question, by the Central Limit Theorem. They are normally distributed with mean 50 and standard deviation 1.58.