3.Ms. Taylor is doing an art project with her class. She has a 3 foot piece of ribbon. If she gives each student an eighth of a foot of ribbon, how many students will receive a piece of ribbon

Answers

Answer 1
Answer:

Answer:

24

Step-by-step explanation:

To solve this problem, first you would need to figure out how many eighths of a foot are in 3 foot. If the pieces she gave away were 1/8 of a foot, 8 pieces would be in 1 foot. Next, multiply 8 by the number of feet there are (3).

8 x 3 = 24

So, 24 students would receive a peice.


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Ninety-nine is what percent of 150?
9 + 1.34 + .5 (3.50 +1.74) How would you simplify the expression? Explain your steps.
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Find the greatest common factor of 108d^2 and 216d
a.Find a linear approximation of 4√14 . b. Justify visually whether your approximation is an over- or underestimate.

In figure, MN : NP = 9:1. If MP = 2. Find the distance from M to point K that is 1/4 the distance from M to N?(A) 1 (B) 1 1/3 (C) 9/20 (D) 1 8/10

Answers

The distance MN is 9/(9+1) = 9/10 of the distance MP, so is

... MN = (9/10)×MP = (9/10)×2 = 9/5

The distance MK is 1/4 that, so is ...

... MK = (1/4)×(9/5) = 9/20 . . . . . matches selection (C)

Answer:

C

Step-by-step explanation:

the answer is C. give the person the brainly :) ignore this answer

Suppose the sequence StartSet a Subscript n Baseline EndSet is defined by the recurrence relation a Subscript n plus 1equalsnegative 2na Subscript n​, for nequals​1, ​2, 3,..., where a1equals5. Write out the first five terms of the sequence.

Answers

Answer:

-10, 40, -240, 1,920 and -19, 200

Step-by-step explanation:

Given the recurrence relation of the sequence defined as aₙ₊₁ = -2naₙ for n = 1, 2, 3... where a₁ = 5, to get the first five terms of the sequence, we will find the values for when n = 1 to n =5.

when n= 1;

aₙ₊₁ = -2naₙ

a₁₊₁ = -2(1)a₁

a₂ = -2(1)(5)

a₂ = -10

when n = 2;

a₂₊₁ = -2(2)a₂

a₃ = -2(2)(-10)

a₃ = 40

when n = 3;

a₃₊₁ = -2(3)a₃

a₄ = -2(3)(40)

a₄ = -240

when n= 4;

a₄₊₁ = -2(4)a₄

a₅ = -2(4)(-240)

a₅ = 1,920

when n = 5;

a₅₊₁ = -2(5)a₅

a₆ = -2(5)(1920)

a₆ = -19,200

Hence, the first five terms of the sequence is -10, 40, -240, 1,920 and -19, 200

David is having a cookout. Hot dogs and buns are sold based on the following quantities per package.Item
Amount Per Package
Hot dog buns
12
Hot dogs
10
A
David thought that he would have to buy 12 packages of hot dog buns and 10 packages of hot dogs to have one bun for each hot dog.
What is the LEAST amount of each David would need to buy to have an equal number of hot dogs and buns?
David should buy 2 packages of buns and 2 packages of hot dogs,
David should buy 6 packages of buns and 5 packages of hot dogs.
с David should buy 5 packages of buns and 6 packages of hot dogs,
D David should buy 22 packages of buns and 22 packages of hot dogs
B

Answers

Answer:  Choice C)  David should buy 5 packages of buns and 6 packages of hot dogs.

========================================================

Explanation:

Focus on the hot dog buns for now

1 package = 12 hot dog buns

2 packages = 24 hot dog buns  (multiply both sides by 2)

3 packages = 36 hot dog buns (multiply original equation by 3)

We can see that the multiples of 12 are being listed. So we have

12, 24, 36, 48, 60, 72, 84, ...

as the possible number of hot dog buns we could get if we buy 1,2,3... packages.

The possible number of hot dogs we can get are

10, 20, 30, 40, 50, 60, 70, 80, ...

which are multiples of 10. Simply add 10 to each item to get the next one.

--------------------------------

Considering these two sets

12, 24, 36, 48, 60, 72, 84, ...

10, 20, 30, 40, 50, 60, 70, 80, ...

what is the lowest common multiple? That would be 60 since it is found in both lists and it is the smallest in common.

The LCM of 12 and 10 is 60.

If he wanted 60 hot dog buns, then 60/12 = 5 packages of buns is what he needs.

If he wanted 60 hot dogs, then he needs 60/10 = 6 packages of hot dogs.

Therefore, David should buy 5 packages of buns and 6 packages of hot dogs. The answer is choice C.

--------------------------------

Side note: a different way to find the LCM is to multiply 10 and 12 to get 10*12 = 120. Then we divide by the GCF 2 getting 120/2 = 60.

-8.9(-3.1) what is the product

Answers

Answer:

27.59

Step-by-step explanation:

Just multiply.

A train travels 45 feet in 1/10 if a second. How far will it travel in 3.5 seconds

Answers

The distance covered by the train in 3.5 seconds will be 1575 feet.

What is speed?

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

Speed = Distance/Time

A train travels 45 feet in 1/10 in a second.

Then the speed will be

Speed = 45 / (1/10)

Speed = 45 x 10

Speed = 450 feet per second

The distance covered by the train in 3.5 seconds will be

Distance = 450 x 3.5

Distance = 1575 feet

More about the speed link is given below.

brainly.com/question/7359669

#SPJ2

Answer:

1575 ft

Step-by-step explanation:

Convert 1/10 to decimal to make the math simpler.

1/10 = 0.1

Divide 3.5 by 0.1.

3.5/0.1 = 35

Multiply 35 by 45.

35 × 45 = 1575

The train will travel 1575 feet in 3.5 seconds.

Determine the truth value of each of these statements if the domain of each variable consists of all real numbers.a) ∀x∃y(x2 = y)

Answers

The statement ∀x∃y(x² = y) is true for all real numbers, as for each real number x, there exists a real number y such that x² = y.

How to determine the truth value of a statement?

The statement ∀x∃y(x² = y) is true as explained below:

For every real number x, there exists a real number y such that x² = y.

For example:

If x = 2, then y = 4 because 2² = 4.

If x = -3, then y = 9 because (-3)² = 9.

Since you can always find a real number y that satisfies the equation x² = y for any real number x, the statement is true for all real numbers in its domain.

Learn more about truth value on:

brainly.com/question/28562089

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The statement is true. If x and y are both real numbers, the statement is:

"for every x, there exist y such that x^2=y"

This is true, because you can pick any real number, square it, and obtain another real number, y. The relation is not surjective, i.e. we will not use all possible values for y, but it doesn't matter. The statement is only asking to find a value for x^2, which we can always do.