Answer:

**Answer:**

The gases will expand **8.2 L** against the constant pressure of 710 torr.

**Explanation:**

Given that:

the original volume V₁ = 35 cm³ = 35 × 10⁻⁶ m³

Since the combustion of the mixture releases energy then :

the work W = - 775 J

Pressure = 710 torr

Since 1 torr = 133.322 Pa

710 torr = 94658.62 Pa

We all know that:

W = -PdV

-775 = - 94658.62 Pa ( V₂ - V₁ )

-775 = - 94658.62 ( V₂ - 35 × 10⁻⁶)

-775/ - 94658.62 = V₂ - 35 × 10⁻⁶

0.008187 = V₂ - 35 × 10⁻⁶

V₂ = 0.008187 + 35 × 10⁻⁶

V₂ = 0.008222 m³

The change in volume dV = V₂ - V₁

The change in volume dV = 0.008222 m³ - 35 × 10⁻⁶ m³

The change in volume dV = 0.008187 m³

To litres

The change in volume dV = 8.2 L

Thus, the gases will expand 8.2 L against the constant pressure of 710 torr.

What are two causes of soil loss?

Base your answers on the graph below, which represents uniform cooling of a sample of a pure substance, starting as a gas. Solid and liquid phases can exist in equilibrium between points

Perform the calculation and report the answer using the proper number of significant figures. Make sure the answer is rounded correctly. 1.012×10^-3 J/(0.015456 g)(298.3682−298.3567)K

A Carbon-10 nucleus has 6 protons and 4 neutrons. Through radioactive beta decay, it turns into a Boron-10 nucleus, with 5 protons and 5 neutrons, plus another particle. What kind of additional particle, if any, is produced during this decay

What isotope has a mass number of 18 and an atomic number of 7

Base your answers on the graph below, which represents uniform cooling of a sample of a pure substance, starting as a gas. Solid and liquid phases can exist in equilibrium between points

Perform the calculation and report the answer using the proper number of significant figures. Make sure the answer is rounded correctly. 1.012×10^-3 J/(0.015456 g)(298.3682−298.3567)K

A Carbon-10 nucleus has 6 protons and 4 neutrons. Through radioactive beta decay, it turns into a Boron-10 nucleus, with 5 protons and 5 neutrons, plus another particle. What kind of additional particle, if any, is produced during this decay

What isotope has a mass number of 18 and an atomic number of 7

**Answer:**

**The ration of the molar solubility is 165068.49.**

**Explanation:**

The solubility reaction of the magnesium hydroxide in the pure water is as follows.

Initial 0 0

Equili +S +2S

Final S 2S

Solubility of in 0.180 M NaOH is a follows.

Initial 0 0

Equili +S +2S

Final S 2S+0.180M

**Therefore, The ration of the molar solubility is 165068.49.**

**Answer:**

**Explanation:**

From the given information:

The equation for the reaction can be represented as:

The I.C.E table can be represented as:

2SO₂ O₂ 2SO₃

Initial: 14 2.6 0

Change: -2x -x +2x

Equilibrium: 14 - 2x 2.6 - x 2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction = 0.8325;

If we want to find:

Then:

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

**0.629 moles** will be present in moles of atoms are in 9.00 g of 13 carbon **atom.**

One **mole **of any substance is the amount of the substance which contain 6.023 × 10²³ **atoms** or molecule if the substance is atomic or molecular in nature and known as gram atomic** mass.**

Number of **atoms** in carbon is 9.00 grams and isotope are 13C,

Number of moles = weight of substance / mass of substance

Substituting the value in formula,

Number of moles = 9.00 grams / 13

Number of moles = **0.629 moles**

Therefore, **0.629 moles** will be present in moles of atoms are in 9.00 g of 13 carbon **atom.**

Learn more about **moles**, here:

#SPJ2

The atomic weight of 13C should be pretty close to 13.0. (If you have the exact mass, use it in the problem.) So, 9.00 g / 13.0 g/mol = 0.692 moles Therefore, the answer should be 0.692 moles are in 9.00 g of 13C.

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**Explanation:**

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**Answer:**

Polyethylene glycol

**Explanation:**

Because of the corrosive nature of Brine solution (solution of NaCl) , we can use organic liquid polyethylene glycol .

The conjugate **acid**and **base** and the term would be **Amphoteric.**

Conjugate acid-

Amphoteric is described as the term employed to denote a **substance **that possesses the characteristics of both an **acid**, as well as, a **base.**

Given** equilibrium**:

→

Therefore, the **dissolution** of in water leads to the display acid that is **conjugate** and the conugate base .

In case, the properties of both are reflected, it shows **amphoteric nature.**

Learn more about "**Acid**" here:

Answer:

Conjugate acid- H^+

Conjugate base- SO4^2-

Terminology- Amphoteric

Explanation:

Consider the equilibrum shown below;

HSO4^-(aq)<-------> H^+(aq) + SO4^2-(aq)

Hence, When HSO4^- is dissolved in aqueous solution, it's conjugate acid is H^+ and it's conjugate base is SO4^2- as shown in the equation above.

If a substance behaves both as an acid and as a base, then the substance is Amphoteric in nature.