# Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 35 cm3. If the combustion of this mixture releases 775 J of energy, to what volume will the gases expand against a constant pressure of 710. torr if all the energy of combustion is converted into work to push back the piston

The gases will expand 8.2 L against the constant pressure of 710 torr.

Explanation:

Given that:

the original volume V₁ = 35 cm³ = 35 × 10⁻⁶ m³

Since the combustion of the mixture releases energy then :

the work W = - 775 J

Pressure = 710 torr

Since 1 torr = 133.322 Pa

710 torr = 94658.62 Pa

We all know that:

W = -PdV

-775 = - 94658.62 Pa ( V₂ - V₁ )

-775 = - 94658.62 ( V₂ - 35 × 10⁻⁶)

-775/ - 94658.62 =  V₂ - 35 × 10⁻⁶

0.008187 = V₂ - 35 × 10⁻⁶

V₂ = 0.008187 + 35 × 10⁻⁶

V₂ = 0.008222 m³

The change in volume dV = V₂ - V₁

The change in volume dV = 0.008222 m³ - 35 × 10⁻⁶ m³

The change in volume dV = 0.008187   m³

To litres

The change in volume dV = 8.2 L

Thus, the gases will expand 8.2 L against the constant pressure of 710 torr.

## Related Questions

Mg(OH)2 is a sparingly soluble salt with a solubility product, Ksp, of 5.61×10−11. It is used to control the pH and provide nutrients in the biological (microbial) treatment of municipal wastewater streams. What is the ratio of solubility of Mg(OH)2 dissolved in pure H2O to Mg(OH)2 dissolved in a 0.180 M NaOH solution? Express your answer numerically as the ratio of molar solubility in H2O to the molar solubility in NaOH.

The ration of the molar solubility is 165068.49.

Explanation:

The solubility reaction of the magnesium hydroxide in the pure water is as follows.

Initial      0          0

Equili     +S       +2S

Final      S          2S

Solubility of in 0.180 M NaOH is a follows.

Initial      0          0

Equili     +S       +2S

Final      S          2S+0.180M

Therefore, The ration of the molar solubility is 165068.49.

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 50.0L tank with 14. mol of sulfur dioxide gas and 2.6 mol of oxygen gas, and when the mixture has come to equilibrium measures the amount of sulfur trioxide gas to be 1.6 mol. Calculate the concentration equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.

Explanation:

From the given information:

The equation for the reaction can be represented as:

The I.C.E table can be represented as:

2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction = 0.8325;

If we want to find:

Then:

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

How many moles of atoms are in 9.00 g of 13c?

0.629 moles will be present in moles of atoms are in 9.00 g of 13 carbon atom.

### What is a mole?

One mole of any substance is the amount of the substance which contain 6.023 × 10²³ atoms or molecule if the substance is atomic or molecular in nature and known as gram atomic mass.

Number of atoms in carbon is 9.00 grams and isotope are 13C,

Number of moles = weight of substance / mass of substance

Substituting the value in formula,

Number of moles = 9.00 grams / 13

Number of moles = 0.629 moles

Therefore, 0.629 moles will be present in moles of atoms are in 9.00 g of 13 carbon atom.

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#SPJ2

The atomic weight of 13C should be pretty close to 13.0. (If you have the exact mass, use it in the problem.) So, 9.00 g / 13.0 g/mol = 0.692 moles Therefore, the answer should be 0.692 moles are in 9.00 g of 13C.

Draw a well-labelled diagram showing how your body digests food​

i too used it

i thought it will help

nice time. .....

Explanation:

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Suppose one was doing this experiment in the real world and the stockroom ran out of NaCl solutions. Which other solutions of similar concentration could be used in place of NaCl(aq)

Polyethylene glycol

Explanation:

Because of the corrosive nature of Brine solution (solution of NaCl) , we can use organic liquid polyethylene glycol .

What are the conjugate base and conjugate acid for HSO4−? What is the term used to describe species that can behave as either an acid or a base, depending on the chemical environment?

The conjugate acidand base and the term would be Amphoteric.

Conjugate acid-

### What is Amphoteric?

Amphoteric is described as the term employed to denote a substance that possesses the characteristics of both an acid, as well as, a base.

Given equilibrium:

Therefore, the dissolution of in water leads to the display acid that is conjugate and the conugate base .

In case, the properties of both are reflected, it shows amphoteric nature.

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Conjugate acid- H^+

Conjugate base- SO4^2-

Terminology- Amphoteric

Explanation:

Consider the equilibrum shown below;

HSO4^-(aq)<-------> H^+(aq) + SO4^2-(aq)

Hence, When HSO4^- is dissolved in aqueous solution, it's conjugate acid is H^+ and it's conjugate base is SO4^2- as shown in the equation above.

If a substance behaves both as an acid and as a base, then the substance is Amphoteric in nature.