Solve the equation
3(x + 1) = 9+ 2x

Answers

Answer 1
Answer:

Answer:

x=6

Step-by-step explanation:

So we have the equation:

3(x+1)=9+2x

Distribute the left side:

3x+3=9+2x

Subtract 2x from both sides. The right side cancels:

(3x+3)-2x=(9+2x)-2x\nx+3=9

Subtract 3 from both sides:

(x+3)-3=(9)-3\nx=6

So, x is 6.

Answer 2
Answer: 3x(x)=3x
3x1=3
3x+3=9+2x

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An author argued that more basketball players have birthdates in the months immediately following July​ 31, because that was the age cutoff date for nonschool basketball leagues. Here is a sample of frequency counts of months of birthdates of randomly selected professional basketball players starting with​ January: 390​, 392​, 360​, 318​, 344​, 330​, 322​, 496​, 486​, 486​, 381​, 331 . Using a 0.05 significance​ level, is there sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency? Do the sample values appear to support the​ author's claim?

Answers

Answer:

There is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

Step-by-step explanation:

In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

H₀: The observed frequencies are same as the expected frequencies.

Hₐ: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

 \chi^(2)=\sum{((O-E)^(2))/(E)}

The values are computed in the table.

The test statistic value is \chi^(2)=128.12.

The degrees of freedom of the test is:

n - 1 = 12 - 1 = 11

Compute the p-value of the test as follows:

p-value < 0.00001

*Use a Chi-square table.

p-value < 0.00001 < α = 0.05.

So, the null hypothesis will be rejected at any significance level.

Thus, there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

The tax on a property with an assessed value of $90,000 is $1,350. Find the tax on a property with anassessed value of $140,000.
a. $1500.00
b. $150.00
c. $2100.00
d. $210.00
e. $750.00

Answers

Answer:

0.015 or 1.5% tax

Step-by-step explanation:

90000x0.015 = 1350

let’s go to the beach each let’s go get away say say what they gonna say the patron on

1, 3, 7, 9 whats next ?

Answers

Maybe 13... because it goes +2 then +4 then +2 so next it would be +4

11? We need more of an explanation to understand your question.

6(2x-5y)-2(x+9y) simplified

Answers

Answer:

10x-48y

Step-by-step explanation:

N<2^2. mathematical induction​

Answers

Answer:

Inequality Form:
n < 4

Interval Notation:
(-, 4)


God bless you have a beautiful blessed day and I hope this makes it!

Wisconsin Public Radio wants to duplicate a survey conducted in 2011 that found that 68% of adults living in Wisconsin felt that the country was going in the wrong direction. How many people would need to be surveyed for a 90% confidence interval to ensure the margin of error would be less than 3%? Be sure to show all your work and round appropriately

Answers

Answer:

655 people would need to be surveyed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{(\pi(1-\pi))/(n)}

In which

z is the zscore that has a pvalue of 1 - (\alpha)/(2).

In this question, we have that:

\pi = 0.68

The margin of error is:

M = z\sqrt{(\pi(1-\pi))/(n)}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - (0.1)/(2) = 0.95, so Z = 1.645.

How many people would need to be surveyed for a 90% confidence interval to ensure the margin of error would be less than 3%?

We need to survey n adults.

n is found when M = 0.03. So

M = z\sqrt{(\pi(1-\pi))/(n)}

0.03 = 1.645\sqrt{(0.68*0.32)/(n)}

0.03√(n) = 1.645√(0.68*0.32)

√(n) = (1.645√(0.68*0.32))/(0.03)

(√(n))^(2) = ((1.645√(0.68*0.32))/(0.03))^(2)

n = 654.3

Rounding up

655 people would need to be surveyed.