Answer:

**Answer:**

its 45 over 6

**Explanation:the answer is in the question**

Answer:

**Answer: Only the melted cube's shape changed.**

**Explanation:**

Select all the statements regarding electric field line drawings that are correct. Group of answer choices: 1. Electric field lines are the same thing as electric field vectors. 2. Electric field line drawings allow you to determine the approximate direction of the electric field at a point in space. 3. The number of electric field lines that start or end at a charged particle is proportional to the amount of charge on the particle. 4. The electric field is strongest where the electric field lines are close together.

What it the Zeeman effect and what does it tell us about the Sun?

If the intensity of a loud car horn is 0.005 W/m^2 when you are 2 meters away from the source. Calculate the sound intensity level. A. 1.6 WB. 0.06 WC. 97 dBD. 223 dBE. 179 dB

Find the speed of light in carbon tetrachlorideethyl alcohol. The refraction index is 1.461 using 3 x 10^8 m/s as the speed of light in vacuum. Answer in units of m/s.

What is the angular width of a person's thumb viewed at arm's length? Assume that the width of the thumb is 17.3 mm and that the distance between the eyes and the thumb is 71.9 cm. Use the small-angle approximation and then convert the answer to degrees.

What it the Zeeman effect and what does it tell us about the Sun?

If the intensity of a loud car horn is 0.005 W/m^2 when you are 2 meters away from the source. Calculate the sound intensity level. A. 1.6 WB. 0.06 WC. 97 dBD. 223 dBE. 179 dB

Find the speed of light in carbon tetrachlorideethyl alcohol. The refraction index is 1.461 using 3 x 10^8 m/s as the speed of light in vacuum. Answer in units of m/s.

What is the angular width of a person's thumb viewed at arm's length? Assume that the width of the thumb is 17.3 mm and that the distance between the eyes and the thumb is 71.9 cm. Use the small-angle approximation and then convert the answer to degrees.

The three given moon phases are:

Waxing Crescent Moon

Waning Crescent Moon

Full Moon

The things we need to match to the above three topicsare:

*visible near western horizon an hour after sunset

*rises about the same time the sun sets

*visible near eastern horizon just before sun rises

*occurs about 3 days before new moon (i know this is waningcrescent)

*visible due south at midnite

*occurs 14 days after new moon (i know this is full moon)

**Answer:**

**Explanation:**

*visible near western horizon an hour aftersunset **WAXING CRESCENT**

*rises about the same time the sun sets **FULLMOON**

*visible near eastern horizon just before sun rises **WANING CRESCENT**

*occurs about 3 days before new moon **WANING CRESCENT**

*visible due south at midnite ** FULL MOON**

*occurs 14 days after new moon ** FULL MOON**

B. It won't move.

C. It will move at the same speed that the large object was moving initially.

D. It will move slower than the large object was moving initially.

**Answer:**

a ut will move faster than the large object was moving initially

**Answer: It will move faster than the large object was moving initially.**

**Explanation:**

b) 1/r^2

c) 1/r

d) None of above

When an underwater **sound **source emits waves of frequency 30 kHz in all directions, the **intensity **of the waves (in Watts/m2) vary with distance r from the source by the relation** 1/r²**

As the intensity mechanical **sound **wave is **inversely **proportional to the square of the **distance **from the source, therefore the correct option is **B**.

Wavelength can be understood in terms of the **distance **between any two similar **successive **points across any wave for example wavelength can be calculated by measuring the **distance **between any two successive crests.

It is the total length of the **wave **for which it completes one cycle.

The intensity of a mechanical wave is **inversely **proportional to the **square **of the distance from the source.

An underwater sound source emits waves of **frequency **of 30 kHz in all directions, the **intensity **of the waves (in Watts/m2) varies with distance r from the source by the **relation **1/r², therefore the **correct **option is B.

Learn more about **wavelength **from here

#SPJ2

b or c not sure but try

**Answer:**

Following are the solution to the given question:

**Explanation:**

Please find the complete question in the attached file.

The cost after 30 days is 60 dollars. As energy remains constant, the cost per hour over 30 days will be decreased.

Thus,

The electricity used is continuously 694W over 30 days.

If just resistor loads (no reagents) were assumed,

Energy usage reduction percentage =

This bulb accounts for of the energy used, hence it saves when you switch it off.

i will answer both versions assuming what you want to know is the distance it travels up from and over the ground. and how long until it reaches space. 540 meters per second up and over. to reach space which is 100km above sea level, it would take about 5400 minutes

**Answer:**

the lowest frequency is

**Explanation:**

In the question it is given that wavelength(L) in the range of 200μm to 400μm.

let ν be frequency of wave v velocity = 3\times 10^8

velocity v= Lν

therefore ν=

frequency ν be lopwest when L will be heighest

ν(lowest)=

ν=