A 135 g sample of H20 at 85°C is cooled. The water loses a total of 15 kJ of energy in the coolingprocess. What is the final temperature of the water? The specific heat of water is 4.184 J/g.°C.
In this case, the relationship among heat, mass, specific heat and temperature for water is mathematically by:
In such a way, solving for the final temperature we obtain:
Therefore, we final temperature is computed as follows, considering that the involved heat is negative as it is lost for water:
Thereby, answer is B. 58°C.
The final temperature of the water is approximately 58°C (Option B) after it has lost 15 kJ of energy in the cooling process.
To calculate the final temperature of the water, we can use the formula of heat loss or gain, Q = mcΔT, where Q is the heat loss or gain, m is the mass, c is the specific heat, and ΔT is the change in temperature.
Setting the given values into our formula: -15,000 J = (135 g) * (4.184 J/g°C) * (T_final - 85°C).
Solving this equation for T_final gives us T_final ≈ 58°C. Hence, the suitable answer would be option B: 58°C.
What is the only gaseous component of the atmosphere whose concentration is routinely contained in all weather reports?
In weather report generally the temperature conditions and the extent of humidity is described. Humidity is nothing but presence of water in its vapour form. Hence the only gas which is being reported in a weather report must be water vapour. The other gases like oxygen carbon dioxide or noble gases or nitrogen are never mentioned in a normal weather report issued in public interest
A rock has a mass of 15 grams and a volume of 5 cm3 what is the density of the object￼￼
The answer is
To find the density of a substance when given the mass and volume we use the formula
From the question
mass = 15 g
volume of rock = 5 cm³
The density of the substance is
We have the final answer as
Hope this helps you
The density of an object is calculated by dividing its mass by its volume. In this case, the rock's density is 3 g/cm3.
The process to determine the density of an object involves dividing its mass by its volume. Here, the rock has a mass of 15 grams and a volume of 5 cm3. Thus, the density can be calculated by the formula:
Density = Mass / Volume.
Plugging the given numbers into this formula results in:
How much is each gallon or how far are you going is the question you should be asking
Abigail obtained 36.6 grams of calcium carbonate after performing a reaction. From her calculations, she knew she should have obtained 44.1 grams. What was her percent yield
it would be 1
1. What structural property of sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water? 2. You will have to look up the structure of this compound and comment on why it is water-soluble. Simply stating that it's polar
1. Sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water as it contains a hydrate salt sodium sulfate .
2. In the structure of this compound, sodium sulphate is polar in nature.
The molecular structure of sodium 4-amino-1-naphthalenesulfonate is .
The polar part of the structure sodium sulfate makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.
Find more information about Molecular formula here:
Answer: it contains a hydrate salt sodium sulfate NaO4S.
4-amino-1-naphthalenesulfonate is a sodium salt. Sodium sulfate is Polar.
The molecular structure of sodium 4-amino-1-naphthalenesulfonate is
The polar part of the structure sodium sulfate NaO4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.
What is the answer? Please
To instill a high degree of personal honor, self-reliance, and confidence in each cadet by presenting a military environment in which cadets will be forced to rely upon themselves and their shipmates to study, work, and learn.