A 135 g sample of H20 at 85°C is cooled. The water loses a total of 15 kJ of energy in the coolingprocess. What is the final temperature of the water? The specific heat of water is 4.184 J/g.°C.

A. 112°C

B. 58°C

C. 70°C

D. 84°C

E. 27°C

Answers

Answer 1
Answer:

Answer:

B. 58°C

Explanation:

Hello,

In this case, the relationship among heat, mass, specific heat and temperature for water is mathematically by:

Q=mCp\Delta T=mCp(T_2-T_1)

In such a way, solving for the final temperature T_2 we obtain:

T_2=T_1+(Q)/(mCp)

Therefore, we final temperature is computed as follows, considering that the involved heat is negative as it is lost for water:

T_2=85\°C+(-15kJ*(1000J)/(1kJ) )/(135g*4.184(J)/(g\°C) )\n\nT_2=58\°C

Thereby, answer is B. 58°C.

Regards.

Answer 2
Answer:

Final answer:

The final temperature of the water is approximately 58°C (Option B) after it has lost 15 kJ of energy in the cooling process.

Explanation:

To calculate the final temperature of the water, we can use the formula of heat loss or gain, Q = mcΔT, where Q is the heat loss or gain, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Setting the given values into our formula: -15,000 J = (135 g) * (4.184 J/g°C) * (T_final - 85°C).

Solving this equation for T_final gives us T_final ≈ 58°C. Hence, the suitable answer would be option B: 58°C.

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A rock has a mass of 15 grams and a volume of 5 cm3 what is the density of the object

Answers

Answer:

The answer is

3.0 g/cm³

Explanation:

To find the density of a substance when given the mass and volume we use the formula

density =  (mass)/(volume)

From the question

mass = 15 g

volume of rock = 5 cm³

The density of the substance is

density =  (15)/(5)

We have the final answer as

3.0 g/cm³

Hope this helps you

Final answer:

The density of an object is calculated by dividing its mass by its volume. In this case, the rock's density is 3 g/cm3.

Explanation:

The process to determine the density of an object involves dividing its mass by its volume. Here, the rock has a mass of 15 grams and a volume of 5 cm3. Thus, the density can be calculated by the formula:

Density = Mass / Volume.

Plugging the given numbers into this formula results in:

Density = 15 grams / 5 cm3.

Therefore, the density of the rock is 3 g/cm3.

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A car averages 27.5 miles per gallon

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How much is each gallon or how far are you going is the question you should be asking

Abigail obtained 36.6 grams of calcium carbonate after performing a reaction. From her calculations, she knew she should have obtained 44.1 grams. What was her percent yield

Answers

Answer:

it would be 1

Explanation:

1. What structural property of sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water? 2. You will have to look up the structure of this compound and comment on why it is water-soluble. Simply stating that it's polar

Answers

1. Sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water as it contains a hydrate salt sodium sulfate NaO_4S.

2. In the structure of this compound, sodium sulphate is polar in nature.

Molecular formula:

The molecular structure of sodium 4-amino-1-naphthalenesulfonate is C_(10)H_(10)NNaO_4S.

The polar part of the structure sodium sulfate NaO_4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.

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Answer: it contains a hydrate salt sodium sulfate NaO4S.

4-amino-1-naphthalenesulfonate is a sodium salt. Sodium sulfate is Polar.

Explanation:

The molecular structure of sodium 4-amino-1-naphthalenesulfonate is

C10H10NNaO4S

The polar part of the structure sodium sulfate NaO4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.

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Answers

Answer:

To instill a high degree of personal honor, self-reliance, and confidence in each cadet by presenting a military environment in which cadets will be forced to rely upon themselves and their shipmates to study, work, and learn.