Theoretical yield
2.05 g salicylic acid x (180g aspirin/1 mol) x (1 mol/138 g salicylic acid)


Answer 1

The question is incomplete; part of the data required in the question are shown:

Theoretical Yield: 2.05 g salicylic acid x (180g aspirin/1 mol) x (1 mol/138 g salicylic acid) 2. Mass of filter paper 2.56 g 3. Mass of filter paper and aspirin 5.42 g 4. Mass of aspirin (3-2) g. Percent Yield [(4)/(1)] x 100




We can calculate the theoretical yield as shown;

2.05g salicylic acid × 180g aspirin/1mol × 1 mol/138g of salicylic acid

Theoretical yield= 2.67 g of aspirin

Actual yield of aspirin is obtained from the experimental data;

Mass aspirin + filter paper= 5.42 g

Mass of filter paper= 2.56 g

Mass of aspirin= 5.42 g -2.56 g = 2.86 g

Hence actual yield of aspirin = 2.86 g

Percentage yield = actual yield/theoretical yield × 100

Percentage yield = 2.86/2.67 ×100 = 107%

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stoichiometry of H₂ to N₂ is 3:1
number of H₂ moles reacted - 2.79 g / 2 g/mol  = 1.40 mol 
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A rigid container of gas has a pressure of 1.72 atm and temperature of 21 oC. If the temperature increases to 85 oC, what is the new pressure in atm?



the new pressure is 2.09 atm


you have to use gay lussac's law so the formula is

p1/t1 = p2/t2

and convert C to Kelvin k=C+273.15

1.72atm/294.15 = p2/358.15

solve for p2 by multiplying 358.15 on both sides

p2=2.09 atm

What do lactate dehydrogenase, aspartate aminotransfcrase, and creatine kinase all have in common? a. they all are allosteric enzymes b. they are all zymogens c, they are all used to diagnose medical conditions d. they all function at abeornally high temperatures



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The standard free energy change for a reaction can be calculated using the equation ΔG∘′=−nFΔE∘′ ΔG∘′=−nFΔE∘′ where nn is the number of electrons transferred, FF is Faraday's constant, 96.5 kJ·mol−1·V−1, and ΔE∘′ΔE∘′ is the difference in reduction potential. For each of the given reactions, determine the number of electrons transferred (n)(n) and calculate standard free energy (ΔG∘′)(ΔG∘′) . Consider the half-reactions and overall reaction for reaction 1. half-reactions:fumarate 2−+2H+CoQH2↽−−⇀succinate−↽−−⇀CoQ+2H+ half-reactions:fumarate−+2H+↽−−⇀succinate2−CoQH2↽−−⇀CoQ+2H+ overall reaction:fumarate2−+CoQH2↽−−⇀succinate2−+CoQΔE∘′=−0.009 V



ΔG°′ = 1.737 KJ/mol


The reaction involves the transfer of two electrons in the form of hydride ions from reduced coenzyme Q, CoQH₂ to fumarae to form succinate and oxidized coenzyme Q, CoQ.

The overall equation of reaction is as follows:

fumarate²⁻ + CoQH₂ ↽⇀ succinate²⁻ + CoQ ;    ΔE∘′=−0.009 V

Using the equation  for standard free energy change; ΔG°′ = −nFΔE°′

where n = 2; F = 96.5 KJ.V⁻¹.mol⁻¹; ΔE°′ = 0.009 V

ΔG°′ = - 2 * 96.5 KJ.V⁻¹.mol⁻¹ * 0.009 V

ΔG°′ = 1.737 KJ/mol

Write the expression for the equilibrium constant Kp for the following reaction. Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH3 )2 as (P NH3)2. If either the numerator or denominator is 1, please enter 1 2 MoO3(s) ↔ 2 MoO2(s) + O2(g)


The expression  for the equilibrium constant Kp for the following reaction is  K_p = (po_2)

Equilibrium constant:

It refers to the ratio of the concentration of products to the concentration of reactants where each raised to the power of their stoichiometric ratios. It is expressed as K.

Since the given expression is

MoO3(s) ↔ 2 MoO2(s) + O2(g)

So, the above expression should be considered for constant kp

Learn more about reaction here;

Answer: K_p={(p_(O_2))}


Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K

K_p is the constant of a certain reaction at equilibrium for gaseous reactants and products.

For the given chemical reaction:

MoO_3(s)\rightleftharpoons 2MoO_2(s)+O_2(g)

The expression of  for above equation follows:


As solids do not exert pressure, MoO_3 and MoO_2  are not involved.

The material the start all reactions are ______ and the materials that are formed are called _____.


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I think the second space is chemical bonds