# X=3/5 y=1/3 z=24/5 work out the value of z+x x y

## Related Questions

87 1/3% into a fraction

87 1/3 / 100 or 8.73/10

Step-by-step explanation:

Since this is a percent, put it out of 100

87 1/3 / 100 or 8.73/10

If this answer is correct, please make me Brainliest!

- Use the unit circle to evaluate
the six trigonometric functions
of theta= 4pi

## The six trigonometric functions, , ,, , and .

Step-by-step explanation:

We have,

To write the six trigonometric functions = ?

∴ The six trigonometric functions, , ,, , and .

1/2 + 2/5=​

9/10 or 0.9

Step-by-step explanation:

1/2 + 2/5 =

1 × 5 + 2 × 2/2 × 5

5 + 4 = 10

9/10 or 0.9

InFraction=9/10

InDecimal=0.9

Thus,The answer is 9/10 or 0.9

-TheUnknownScientist

9/10 or 0.9.

Step-by-step explanation:

1/2 + 2/5 =

5/10 + 4/10 =

5 + 4/10 =

9/10

Evaluate. Write your answer as a fraction or whole number.
1/3(1)
=

The answer is 1/3. Any number/ fraction multiplied by 1 remains the original number. Hope this helps!

Step-by-step explanation:

Writing on the SAT Exam It has been found that scores on the Writing portion of the SAT (Scholastic Aptitude Test) exam are normally distributed with mean 484 and standard deviation 115. Use the normal distribution to answer the following questions. Required:
a. What is the estimated percentile for a student who scores 425 on Writing?
b. What is the approximate score for a student who is at the 87th percentile for Writing?

a) The estimated percentile for a student who scores 425 on Writing is the 30.5th percentile.

b) The approximate score for a student who is at the 87th percentile for Writing is 613.5.

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

a. What is the estimated percentile for a student who scores 425 on Writing?

This is the pvalue of Z when X = 425. So

has a pvalue of 0.3050.

The estimated percentile for a student who scores 425 on Writing is the 30.5th percentile.

b. What is the approximate score for a student who is at the 87th percentile for Writing?

We have to find X when Z has a pvalue of 0.87. So X for Z = 1.126.

The approximate score for a student who is at the 87th percentile for Writing is 613.5.

Solve for the given variable: 4. 24 - 9x = -3x

5. 4(5x + 2) + 11 = 18x + 3

6. 3x - 8x = -27 – 13

4. x=4

5. x=-8

6. x=8

Step-by-step explanation:

It may take one extra step to get to the solution, but this method always works.

1. find the variable term that is smallest or most negative. Subtract all the terms on that side of the equation from both sides of the equation.

2. collect terms

3. divide the equation by the coefficient of the variable

4. add the opposite of the constant

___

4. The most negative variable term is -9x, which is on the left side. Subtracting (24-9x) from both sides of the equation, we have ...

0 = -3x -24 +9x

0 = -24 +6x

0 = -4 +x . . . . . divide by 6

4 = x . . . . . . . . add the opposite of -4

__

5. The smallest variable term is 18x, on the right. (The variable term on the left is 20x.)

4(5x +2) +11 -18x -3 = 0 . . . subtract the right side

2x +16 = 0 . . . collect terms

x +8 = 0 . . . . . . divide by 2

x = -8 . . . . . . . . add -8

__

6. All variables are on the left side, so we can just collect terms and divide by the coefficient of the variable.

-5x = -40 . . . collect terms

x = 8 . . . . . divide by -5

If you were to literally follow the steps above, you would recognize that -5x is less than 0x (the x-term on the right side of the equation), so you would subtract the left side, giving ...

0 = 5x -40

0 = x -8 . . . . . divide by 5

8 = x . . . . . . . . add 8

_____

Comment on this solution technique

You will often be told to solve these equations by separating the variable terms from the constant terms. This method actually puts the variable terms and constant terms together (and zero on the other side of the equal sign). The constant is separated from the variable as the last step of this solution process, rather than as one of the first steps. By doing this, we don't have to worry about which variable term or which constant term we're going to mess with.

The only reason for choosing the variable term with the smallest (least) coefficient in the first step is to ensure that the resulting variable coefficient is positive. This tends to reduce errors later on. You can also use that same strategy when solving the equation following the "separate constant terms and variable terms" approach.