Answer:

**Answer:**

3.16

**Step-by-step explanation:**

Three is equal to well, 3.

Sixteen hundredths gives you 0.16.

Three and sixteenth hundredths is the same as saying 3 and 0.16, which is just 3.16.

Answer:
Three and sixteen hundredths in expanded form is 3.16

Why might Jules use a credit card rather than a check to make a purchase

A group of friends has gotten very competitive with their board game nights. They have found that overall, they each have won an average of 18 games, with a population standard deviation of 6 games. If a sample of only 2 friends is selected at random from the group, select the expected mean and the standard deviation of the sampling distribution from the options below. Remember to round to the nearest whole number.

Solve used the basic percent equation 10% of 600 is what ??? Remember Percent×base=amount

Please helppp it’s urgent , I’ll give a crown !!

Find the acute angle between the diagonal of rectangle whose sides are 5cm and 7cm

A group of friends has gotten very competitive with their board game nights. They have found that overall, they each have won an average of 18 games, with a population standard deviation of 6 games. If a sample of only 2 friends is selected at random from the group, select the expected mean and the standard deviation of the sampling distribution from the options below. Remember to round to the nearest whole number.

Solve used the basic percent equation 10% of 600 is what ??? Remember Percent×base=amount

Please helppp it’s urgent , I’ll give a crown !!

Find the acute angle between the diagonal of rectangle whose sides are 5cm and 7cm

B. an arrangement in which you receive goods or services in exchange for other goods and services

C. an arrangement in which you receive money now and pay it back later with fees

the answer is C.an arrangement in which you receive money now and pay it back later with fees

**Answer:**

C

**Step-by-step explanation:**

**Answer:**

See explanation below

**Step-by-step explanation:**

Here a coin was tossed three times.

Let H = head & T = tail

Find the following:

a) The sample space:

Since a coin is tossed thrice, all possible outcome would be:

**S = { HHH, HHT, HTH, HTT, TTT, TTH, THH, THT}**

b) i) A = Exactly 2 tails: Here exactly 2 tails were recorded.

**A = {HTT, TTH, THT}**

ii) B = at least two tails: Here 2 or more tails were recorded.

**B = {HTT, TTT, TTH, THT}**

iii) C = the last two tosses are heads:

**C = { HHH, THH}**

c) List the elements of the following events:

i) A. This means all outcomes in A

**= {HTT, TTH, THT}**

ii) A∪B. A union B, means all possible outcomes present in A or B or in both

**= {HTT, TTH, THT, TTT}**

iii) A∩B. This means all possible outcomes of A that are present in B.

**= {HTT, TTH, THT}**

iv) A∩C. All outcomes A that are present in B

**= {∅}**

The **sample **space of tossing a coin three times consists of eight possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT. Events A, B, and C can be determined by listing the appropriate outcomes. The intersection and union of events A and B can also be determined.

(a) The sample space, Ω, of **tossing **a coin three times can be **determined **by listing all the possible outcomes: HHH, HHT, HTH, THH, TTH, THT, HTT, and TTT.

(b) i. A = {HHT, HTH, THH}

ii. B = {TTT, TTH, THT, HTT, HHT, HTH, THH}

iii. C = {HTH, TTH}

(c) i. A = {HHT, HTH, THH}

ii. A∪B = {HHT, HTH, THH, TTT, TTH, THT, HTT, HHT}

iii. A∩B = {HHT, HTH, THH}

iv. A∩C = {HHT, HTH}

#SPJ3

Answer: The answer is (19, 17), (20, 18), (21, 19), (22, 20), and (23, 21).

Step-by-step explanation:

**Answer:**

**Step-by-step explanation:**

Hello!

X₁: Life span of a battery of Brand X

X₁~N(μ₁;σ₁²)

μ₁= 102hours

σ₁= 6.8hours

X₂: Life span of a battery of Brand Y

X₂~N(μ₂;σ²)

μ₂= 100hours

σ₂= 1.4hours

To complete the first two sentences, you have to use the empirical rule:

μ±δ= 68% of the distribution

μ±2δ= 95% of the distribution

μ±3δ= 99% of the distribution

**1. About 68% of brand x’s batteries have a lifespan between **__95.2 __**and **__108.8 hours__**.**

μ₁±σ₁= 102 ± 6.8= 95.2; 108.8

**2. About 68% of brand y’s batteries have a lifespan between **__98.6 __**and **__101.4 hours__**. **

μ₂±σ₂= 100 ± 1.4= 98.6; 101.4

**3. The life span of brand **__Y __**’s battery is more likely to be consistently close to the mean.**

The standard deviations show you the dispersion of the distribution. A low standard deviation indicates that the values are close to the mean. A high standard deviation indicates that the values are further away the values are from the mean.

The standard deviation for the X batteries is σ₁= 6.8hours and the Y batteries are σ₂= 1.4hours since the standard deviation for the Y batteries is less than the standard deviation for the X batteries, you'd expect that the life span of the Y batteries will be closer to the mean than the life span of the X batteries.

I hope it helps!

6m+30 is the answer.

Multiply 6 and m and you get 6m.

Multiply 6 and 6 and you get 30.

6m+30

Multiply 6 and m and you get 6m.

Multiply 6 and 6 and you get 30.

6m+30

6m+30 is the answer.

Multiply 6 and m and you get 6m.

Multiply 6 and 6 and you get 30.

6m+30

Multiply 6 and m and you get 6m.

Multiply 6 and 6 and you get 30.

6m+30

**Answer:**

There are 2,000 grams left after 300 years.

**Step-by-step explanation:**

Giving the following information:

The half-life of a radioactive substance is 200 years. There are 8000 grams of the substance initially.

**First, we need to calculate the reduction of the substance each year:**

Yearly reduction= 8,000/400= 20 grams per year

**Now, for 300 years:**

300 year reduction= 20*300= 6,000

There are 2,000 grams left after 300 years.