# The following information is needed to reconcile the cash balance for Discount Dry​ Cleaning, Inc. ​ A deposit of \$ 5,600 is in transit. ​Outstanding checks total \$ 1,500. ​The book balance is \$ 6,100 on February​ 28, 2019. ​The bookkeeper recorded a \$ 1,700 check as \$ 17,300 in payment of the current​ month's rent. ​The bank balance on February​ 28, 2019, was \$ 16,210. A deposit of \$ 200 was credited by the bank for \$ 2, 000. ​ A​ customer's check for \$ 3,100 was returned for non-sufficient funds. ​The bank service charge is \$ 90. What was the adjusted book​ balance?

\$18,510.

Explanation:

Book Balance                                               \$6,100

Less: NSF                                                       3,100

Bank Service Charges                                       90

Transposition Error - Company has understated its Cash Balance by recording 17,300 instead of 1,700. So, add the error to the Account.

NSF - Company has recorded a collection of receivable. But the bank termed the Check as "NSF" because of insufficient funds. So, deduct it from the Cash balance.

Deposit in-Transit and Outstanding Checks are already recorded in the Company's books of accounts. These transactions should be adjusted in the Bank Account.

## Related Questions

In June 2007 General Motors (GM) posted a price-earnings ratio of 9.84. Ifthe price of the stock at that time was \$36 per share, which of the following
must have been true?
a. GMâs earnings per share was 3.66.
b. GMâs coupon payment was \$35 per year.
c. GMâs dividend yield for the year was 26%.
d. GMâs revenues that month were \$366 million.

General Motors (GM)

If  the price of the stock at that time was \$36 per share, the true statement is:

a. GM's earnings per share was 3.66.

Explanation:

a) Data and Calculations:

Price-earnings ratio = 9.84

Market price of stock at that time = \$36 per share

Earnings per share = Market price per share/Price-earnings ratio

= \$36/9.84 = 3.659

= \$3.66

Check:

Price-earnings ratio = Market price per share/Earnings per share

= 9.84 (\$36/\$3.66)

You buy one Home Depot June 60 call contract and one June 60 put contract. The call premium is \$5 and the put premium is \$3. Your maximum loss from this position could be a. \$300. b. \$800. c. None of the options are correct. d. \$200. \$500.

b. \$800

Explanation:

The calculation of maximum loss from this position is shown below:-

Maximum Loss from this position = (Assume figure × Call premium) + (Assume figure × Put premium)

= (100 × \$5) + (100 × \$3)

= \$500 + \$300

= \$800

Therefore for computing the maximum loss from this position we simply applied the above formula.

Barnett Industries, Inc., issued \$600,000 of 8% bonds on January 1, 2019. The bonds pay interest semiannually on July 1 and January 1. The maturity date on these bonds is December 31, 2028. The firm uses the effective interest method of amortizing discounts and premiums. The bonds were sold to yield an effective interest rate of 9%. Barnett incurred legal and investment banking fees of \$22,000 in issuing the bonds and amortizes these costs annually on a straight-line basis.Required:

1. Calculate the selling price of the bonds.
2. Prepare journal entry for the issuance of the bonds and bond issue costs.
3. Assume that Barnett uses IFRS. Prepare the journal entry for the issuance of the bonds.

1. The selling price of the bonds is \$590.976.46

2 .The journal entry for the issuance of the bonds and bond issue costs would be as follows:

Debit                          Credit

Cash                                             \$538,976.26

Discount on bonds payable       \$39,023.74

Unamortized bonds issue costs \$22,000

Bonds Payable                       \$600,000

3. Assuming that Barnett uses IFRS,  the journal entry for the issuance of the bonds would be as follows:

Debit                      Credit

Cash             \$600,000

Bonds Payable             \$600,000

Explanation:

In order to calculate the selling price of the bonds we would have to calculate first the present value of particular and present value of interest, hence:

present value of particular=(\$600,000×0.414643)=\$248,785.80

present value of interest=\$600,000×4%13.007936=\$312,190.46

Therefore, selling price of the bonds=present value of particular+present value of interest

1. Selling price of the bonds=\$248,785.80+\$312,190.46=\$590.976.46

2. The journal entry for the issuance of the bonds and bond issue costs would be as follows:

Debit                          Credit

Cash                                             \$538,976.26

Discount on bonds payable       \$39,023.74

Unamortized bonds issue costs \$22,000

Bonds Payable                       \$600,000

3. Assuming that Barnett uses IFRS,  the journal entry for the issuance of the bonds would be as follows:

Debit                      Credit

Cash             \$600,000

Bonds Payable             \$600,000

The Skulls, a student social organization, has two different locations under consideration for constructing a new chapter house. The Skulls' president, a POM student, estimates that due to differing land costs, utility rates, etc., both fixed and variable costs would be different for each of the proposed sites, as follows LocationAnnual FixedVariableAlpha Ave.\$5,000 \$200per personBeta Blvd.\$8,000 \$150per person If it is estimated that 30 persons will be living in this new chapter house, which location should the Skulls select

The Skulls

The location that Skulls should select is:

Alpha Avenue.

Explanation:

a) Data and Calculations:

Estimated number of persons living in this new chapter house = 30

Fixed       Variable                   Total Cost

Alpha Ave. \$5,000       \$200 per person     \$11,000

Beta Blvd.  \$8,000        \$150 per person    \$12,500

b) The location that Skulls should select must minimize the total cost.  The location which meets this criterion is Alpha Avenue, with a total cost of \$11,000.  This is purely because of the number of persons living in the chapter house.  Assuming that this number would increase, then it may be considered economically better to choose the Beta Boulevard instead of the Alpha Avenue.

What would you include in a recommendation to the CEO for a better method for evaluating the performance of the divisions?a.The method used to evaluate the performance of the divisions should be reevaluated.

b.A better divisional performance measure would be the rate of return on investment

c.A better divisional performance measure would be the residual income.

d.None of these choices would be included.

e.All of these choices (a, b & c) would be included.

Option D

Explanation:

In simple words, method of performance division is considered to be effective when it depicts a true picture, not because it gives a sound position of the organisation as waned by the managers.

Thus, reticulation should not be done. Also, Divisional performance should be judged by some other aspects like time taken to perform the job or wastage done by them etc.

The Model E extender fits with the 2 inch heavy duty hitches.The contract calls for 247 Model E extenders per week to be delivered in equal installments over the 16 weeks of the contract. The goal of Alpha Assemblies is to work 40 hours per week. The actual work time for completing the Model E extenders has been broken down by process in the table below. Also provided is the anticipated learning rate for each process. All processes must be performed in sequence and each step has its own separate and unique workcenter. To achieve the goal of working 40 hours per week or less, the cycle time must be lower than the takt time. What is the expected Cycle Time for Model E in Week 16? Note: learning is applied to the batch quantity per week. Do not try to break out the units within a week.Process Time Required per Unit Predecessor Task Learning RateA 9 82B 12 A 86C 18 B 81D 9 C 90E 12 D 80F 17 E 88G 14 F 83H 12 G 85I 8 H 82

Cycle Time = 10.19482 minute

Explanation:

From the question :

The Model E can be illustrated perfectly as shown below:

Process Time Required         Predecessor Task           Learning Rate

per Unit

A                  9                                                                          82

B                 12                                     A                                  86

C                 18                                     B                                  81

D                 9                                      C                                  90

E                 12                                     D                                  80

F                 17                                     E                                   88

G                 14                                     F                                   83

H                 12                                     G                                  85

I                   8                                      H                                  82

Now For the minutes per week for each Process; we have :

Process Time Required         Predecessor      Learning      Minutes

per Unit                    Task                   Rate               (Week 16)

A                  9                                                      82               4.069096

B                 12                           A                         86              6.564098

C                 18                          B                          81               7.74841

D                 9                           C                          90              5.9049

E                 12                           D                         80               4.9152

F                 17                            E                         88               10.19482

G                 14                           F                         83              6.644165

H                 12                           G                        85              6.264075

I                   8                            H                        82              3.616974

The objective here is to determine the expected Cycle Time for Model E in Week 16

So, we can equally regard the Cycle Time = Bottleneck of Activity for Week 16.

Cycle Time = 10.19482 minute   in as much as it is the the largest activity time for the week 16

Given that the demand per week is : = 247

The available time per week = 40 hours = 40 × 60 hours = 2400 minutes

Talk Time = Available Time Per Week/Demand Per Week

Talk Time = 2400/247

Talk Time = 9.716599

Thus; here  the cycle time is greater than the talk time.