A balloon filled with 0.500 L of air at sea level is submerged in the water to a depth that produces a pressure of 3.25 atm. What is the volume of the balloon at this depth? a. 0.154 L b. 6.50 L c. 0.615 L d. 1.63 L d. None of the above


Answer 1

"0.154 L" is the volume of the balloon.



  • P_1 = 1 \ atm
  • P_2 = 3.25 \ atm


  • V_1 = 0.5 \ L
  • V_2 = ?

As we know,

P_1. V_1 = P_2 .V_2


→      V_2 = (P_1. V_1)/(P_1)

By substituting the values, we get

            = (0.5* 1)/(3.25)

            = (0.5)/(3.25)

            = 0.154 \ L

Thus the above answer i.e., "option a" is correct.

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Answer 2


Option a . 0.154L


P₁ . V₁ = P₂ . V₂

when we have constant temperature and constant moles for a certain gas.

At sea level, pressure is 1 atm so:

0.5 L . 1atm = V₂ . 3.25 atm

(0.5L . 1atm) / 3.25 atm = 0.154 L

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The gas-phase reaction follows an elementary rate law and is to be carried out first in a PFR and then in a separate experiment in a CSTR. When pure A is fed to a 10 dm 3 PFR at 300 K and a volumetric flow rate of 5 dm 3 /s, the conversion is 80%. When a mixture of 50% A and 50% inert (I) is fed to a 10 dm 3 CSTR at 320 K and a volumetric flow rate of 5 dm 3 /s, the conversion is also 80%. What is the activation energy in cal/mol



The activation energy is =8.1\,kcal\,mol^(-1)


The gas phase reaction is as follows.

A \rightarrow B+C

The rate law of the reaction is as follows.


The reaction is carried out first in the plug flow reactor with feed as pure reactant.

From the given,

Volume "V" = 10dm^(3)

Temperature "T" = 300 K

Volumetric flow rate of the reaction v_(o)=5dm^(3)s

Conversion of the reaction "X" = 0.8

The rate constant of the reaction can be calculate by the following formua.

V= (v_(0))/(k)[(1+\epsilon )ln((1)/(1-X)-\epsilon X)]

Rearrange the formula is as follows.

k= (v_(0))/(V)[(1+\epsilon )ln((1)/(1-X)-\epsilon X)]............(1)

The feed has Pure A, mole fraction of A in feed y_{A_(o)} is 1.

\epsilon =y_{A_(o)}\delta

\delta = change in total number of moles per mole of A reacte.


Substitute the all given values in equation (1)

k=(5m^(3)/s)/(10dm^(3))[(1+1)ln (1)/(1-0.8)-1 * 0.8] = 1.2s^(-1)

Therefore, the rate constant in case of the plug flow reacor at 300K is1.2s^(-1)

The rate constant in case of the CSTR can be calculated by using the formula.

(V)/(v_(0))= (X(1+\epsilon X))/(k(1-X)).............(2)

The feed has 50% A and 50%  inerts.

Hence, the mole fraction of A in feed y_{A_(o)} is 0.5

\epsilon =y_{A_(o)}\delta

\delta = change in total number of moles per mole of A reacted.


Substitute the all values in formula (2)


Therefore, the rate constant in case of CSTR comes out to be 2.8s^(-1)

The activation energy of the reaction can be calculated by using formula


In the above reaction rate constant at the two different temperatures.

Rearrange the above formula is as follows.

E= R *((T_(1)T_(2))/(T_(1)-T_(2)))ln(k(T_(2)))/(k(T_(1)))

Substitute the all values.

=1.987cal/molK((300K *320K)/(320K *300K))ln (2.8)/(1.2)=8.081 *10^(3)cal\,mol^(-1)


Therefore, the activation energy is =8.1\,kcal\,mol^(-1)

how many grams of F2 are needed to react with 3.50 grams of Cl2 Equation needed for question- Cl2+3F2-->2ClF3 please explain how to get the answer.



5.62 g of F2


We have to start with the chemical reaction:


We have a balanced reaction, so we can continue with the mol calculation. For this, we need to know the molar mass of Cl_2  (70.906 g/mol), so:


Now, with the molar ratio between Cl_2  and F_2  we can convert from moles of Cl_2  and F_2  (1:3), so:


Finally, with the molar mass of F_2 we can calculate the gram of F_2 (37.99 g/mol), so:


I hope it helps!

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a) V = 1.542 E11 ft³

b) V = 4367011968 m³

c) V = 1.1535 E12 us gal


Acre surface is defined as 66 by 660 feet at a depth of one foot:

⇒ Vacre-foot = 66ft*660ft*1ft = 43560 ft³


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Which of the following describes a way in which chemistry affects how youuse a computer?
A. The colors in the computer display are the result of substances
that glow.
B. By clicking a mouse, you can select an object or text on a
computer screen.
C. Eye stress can be reduced by sitting a certain distance from the
D. You are able to play video games by moving your body instead of a


A way in which chemistry affects how To use a computer is  The colors in the computer display are the result of substances that glow. Option A

In modern computers, the display technology commonly used is Liquid Crystal Display (LCD) or Light Emitting Diode (LED) technology. These displays rely on the principles of chemistry to produce the colors that we see on the screen.

In LCD screens, tiny liquid crystal cells are controlled by an electric current, which causes them to either block or allow the passage of light. Each cell represents a pixel on the screen, and by controlling the intensity of light passing through each pixel, different colors can be produced.

The liquid crystals used in LCD screens are organic compounds that exhibit unique optical properties, allowing them to manipulate light in a controlled manner.

LED screens, on the other hand, use arrays of light-emitting diodes to generate light. These diodes are made of semiconducting materials, often composed of compounds like gallium, arsenic, and phosphorus. When an electric current passes through these compounds, they emit light of a specific wavelength, resulting in the different colors displayed on the screen.

So, the colors we see on a computer display are a direct result of the chemical properties and behavior of the substances used in the LCD or LED technology. Chemistry plays a crucial role in the design and functionality of computer displays, enabling us to view vibrant and accurate colors while using our computers.

Option A

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Write the equation for the alpha decay of C-11. Write the equation for the beta decay of Be-10



We know that in the decay process the sum of molecular number as well as molecular weight should be constant.

The following three reaction are as follows

1 .


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164 g