A 2100 g block is pushed by an external force against a spring (with a 22 N/cm spring constant) until the spring is compressed by 11 cm from its uncompressed length. The compressed spring and block rests at the bottom of an incline of 28◦ with the spring lying along the surface of the ramp.After all the external forces are removed (so the compressed spring releases the mass) how far D along the plane will the block move before coming to a stop? Answer in units of m.
We need to solve this question using law of conservation of energy
Energy at the bottom of the incline= energy at the point where the block will stop
Therefore, Energy at the bottom of the incline consists of the potential energy stored in spring and gravitational potential energy=
Energy at the point where the block will stop consists of only gravitational potential energy=
Hence from Energy at the bottom of the incline= energy at the point where the block will stop
Therefore, the vapor pressure at 60.0°C is 2.416 atm.
What is the magnitude of a vector that has the following components: x = 32 m y = -59 m
Since the x and y components are given
The vectors Magnitude = √32²+(-59)²
A hemispherical surface (half of a spherical surface) of radius R is located in a uniform electric field of magnitude E that is parallel to the axis of the hemisphere. What is the magnitude of the electric flux through the hemisphere surface?
According to the definition of electric flux, it can be calculated integrating the product E*dA, across the surface.
As the electric field E is uniform and parallel to the hemisphere axis, and no charge is enclosed within it, the net flux will be zero, so, in magnitude, the flux across the opening defining the hemisphere, must be equal to the one across the surface.
The flux across the open surface can be expressed as follows:
As E is constant, and parallel to the surface vector dA at any point, can be taken out of the integral, which is just the area of the surface, π*R².
⇒Flux = E*π*R²
(a) Is the velocity of car A greater than, less than, or the same as thevelocity of car B? (b) Is the initial position of car A greater than, less than, or equal to the initial position of car B? (c) In the time period from t = 0 tot = 1 s, is car A ahead of car B, behind car B, or at the same position as car B?
a. ) Is the velocity of car A less than the velocity of car B b. the initial position of car A greater than the initial position of car B c. ahead In the time period from t = 0 tot = 1 s, is car A ahead of car B?.
what is velocity ?
Velocity is the parameter which is different from speed, can be defined as the rate at which the position of the object is changed with respect to time, it is basically speeding the object in a specific direction in a specific rate.
Velocity is a vector quantity which shows both magnitude and direction and The SI unit of velocity is meter per second (ms-1). If there is a change in magnitude or the direction of velocity of a body, then it is said to be accelerating.
Finding the final velocity is simple but few calculations and basic conceptual knowledge are needed.
7. If the impact of the golf club on the ball in the previous question occurs over a time of 2 x 10 seconds, whatforce does the ball experience to accelerate from rest to 73 m/s?
3.65 x mass
Time = 20s
Initial velocity = 0m/s
Final velocity = 73m/s
Force the ball experience = ?
To solve this problem, we apply the equation from newton's second law of motion:
F = m
m is the mass
v is the final velocity
u is the initial velocity
t is the time taken
F = m ( ) = 3.65 x mass
To calculate the force experienced by the ball to accelerate from rest to 73 m/s, use Newton's second law of motion.
To calculate the force experienced by the ball to accelerate from rest to 73 m/s, we can use Newton's second law of motion, which states that force equals mass times acceleration (F = m * a).
Since the ball starts from rest, its initial velocity (vi) is 0 m/s. The final velocity (vf) is 73 m/s. The time (t) taken for the impact is given as 2 x 10 seconds. So, the acceleration (a) can be calculated using the formula a = (vf - vi) / t.
Substituting the given values into the equation, we have a = (73 - 0) / (2 x 10) = 3.65 m/s^2.
Now, we can find the force (F) using the formula F = m * a. If the mass of the ball is known, we can substitute it into the equation to find the force experienced by the ball.