Answer:

**Answer:**

**6.5e-4 m**

**Explanation:**

We need to solve this question using law of conservation of energy

**Energy at the bottom of the incline= energy at the point where the block will stop**

Therefore,** Energy at the bottom of the incline consists of the potential energy stored in spring and gravitational potential energy=**

**Energy at the point where the block will stop consists of only gravitational potential energy=**

Hence from Energy at the bottom of the incline= energy at the point where the block will stop

⇒

⇒

Also

where is the mass of block

is acceleration due to gravity=9.8 m/s

is the difference in height between two positions

⇒

Given m=2100kg

k=22N/cm=2200N/m

x=11cm=0.11 m

∴

⇒

⇒

**⇒h=0.0006467m=**

The graphs display velocity data Velocity is on the y-axis (m/s), while time is on the x-axis (s). Based on the graphs, which data set represents constant acceleration?

. Using your knowledge of circular (centripetal) motion, derive an equation for the radius r of the circular path that electrons follow in terms of the magnetic field B, the electrons' velocity v, charge e, and mass m. You may assume that the electrons move at right angles to the magnetic field.2. Recall from electrostatics, that an electron obtains kinetic energy when accelerated across a potential difference V. Since we can directly measure the accelerating voltage V in this expierment, but not the electrons' velocity v, replace velocity in your previous equation with an expression containing voltage. The electron starts at rest. Now solve this equation for e/m.You should obtain e/m = 2V/(B^2)(r^2)3. The magnetic field on the axis of a circular current loop a distance z away is given byB = mu I R^2 / 2(R^2 + z^2)^ (3/2)where R is the radius of the loops and I is the current. Using this result , calculate the magnetic field at the midpoint along the axis between the centers of the two current loops that make up the Helmholtz coils, in terms of their number of turns N, current I, and raidus R.Helmholtz coils are separated by a distance equal to their raidus R. You should obtain:|B| = (4/5)^(3/2) *mu *NI/R = 9.0 x 10^-7 NI/Rwhere B is magnetic field in tesla, I is in current in amps, N is number of turns in each coil, and R is the radius of the coils in meters

A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm under her weight. Find the spring constant and the total work done on it during the compression.

An electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +6.18 x 105 m/s to a final velocity of 2.59 x 106 m/s while traveling a distance of 0.0708 m. The electron's acceleration is due to two electric forces parallel to the x axis: = 8.87 x 10-17 N, and , which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force .

Much of our knowledge of the interior of the Earth comes from the study of planetary vibrations, which is the science of

. Using your knowledge of circular (centripetal) motion, derive an equation for the radius r of the circular path that electrons follow in terms of the magnetic field B, the electrons' velocity v, charge e, and mass m. You may assume that the electrons move at right angles to the magnetic field.2. Recall from electrostatics, that an electron obtains kinetic energy when accelerated across a potential difference V. Since we can directly measure the accelerating voltage V in this expierment, but not the electrons' velocity v, replace velocity in your previous equation with an expression containing voltage. The electron starts at rest. Now solve this equation for e/m.You should obtain e/m = 2V/(B^2)(r^2)3. The magnetic field on the axis of a circular current loop a distance z away is given byB = mu I R^2 / 2(R^2 + z^2)^ (3/2)where R is the radius of the loops and I is the current. Using this result , calculate the magnetic field at the midpoint along the axis between the centers of the two current loops that make up the Helmholtz coils, in terms of their number of turns N, current I, and raidus R.Helmholtz coils are separated by a distance equal to their raidus R. You should obtain:|B| = (4/5)^(3/2) *mu *NI/R = 9.0 x 10^-7 NI/Rwhere B is magnetic field in tesla, I is in current in amps, N is number of turns in each coil, and R is the radius of the coils in meters

A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm under her weight. Find the spring constant and the total work done on it during the compression.

An electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +6.18 x 105 m/s to a final velocity of 2.59 x 106 m/s while traveling a distance of 0.0708 m. The electron's acceleration is due to two electric forces parallel to the x axis: = 8.87 x 10-17 N, and , which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force .

Much of our knowledge of the interior of the Earth comes from the study of planetary vibrations, which is the science of

**Answer:**

The vapor pressure at 60.0°C is** 2.416 atm**

**Explanation:**

To solve this problem, we use Clausius-Clapeyron equation

where;

Initial pressure P₁ = 0.703 atm

Initial Temperature T₁ = 25+273 = 298K

Final temperature T₂ = 60+273 = 333K

Change in enthalpy of vaporization ΔH = 29.1 KJ/mol = 29100J/mol

R is Boltzman constant = 8.314 J/K.mol

⇒

P₂ = P₁ (3.43663) = (0.703 atm)(3.43663) = 2.416 atm

P₂ = 2.416 atm

Therefore, **the vapor pressure at 60.0°C is 2.416 atm**.

Answer:

Explanation:

Since the x and y components are given

The vectors Magnitude = √32²+(-59)²

=67.12m

**Answer:**

**π*R²*E**

**Explanation:**

According to the definition of electric flux, it can be calculated integrating the product E*dA, across the surface.

As the electric field E is uniform and parallel to the hemisphere axis, and no charge is enclosed within it, the net flux will be zero, so, in magnitude, the flux across the opening defining the hemisphere, must be equal to the one across the surface.

The flux across the open surface can be expressed as follows:

As E is constant, and parallel to the surface vector dA at any point, can be taken out of the integral, which is just the area of the surface, π*R².

⇒**Flux = E*π*R²**

(b) Is the initial position of car A greater than, less than, or equal to the

initial position of car B?

(c) In the time period from t = 0 tot = 1 s, is car A ahead of car B,

behind car B, or at the same position as car B?

a. ) Is the** velocity **of car A less than the velocity of car B b. the initial position of car A greater than the **initial position** of car B c. ahead In the time period from t = 0 tot = 1 s, is car A ahead of car B?.

**Velocity **is the parameter which is different from speed, can be defined as the rate at which the position of the object is changed with respect to time, it is basically **speeding **the object in a specific direction in a specific rate.

**Velocity** is a **vector quantity** which shows both magnitude and direction and The **SI unit **of velocity is meter per second (ms-1). If there is a change in magnitude or the direction of velocity of a body, then it is said to be** accelerating.**

Finding the** final velocity** is simple but few calculations and basic conceptual knowledge are needed.

For more details regarding** velocity,** visit

#SPJ2

**Answer:**

a. less than, b. greater than, c. ahead

**Explanation:**

**Answer:**

**3.65 x mass**

**Explanation:**

Given parameters:

Time = 20s

Initial velocity = 0m/s

Final velocity = 73m/s

Unknown:

Force the ball experience = ?

Solution:

To solve this problem, we apply the equation from newton's second law of motion:

F = m

m is the mass

v is the final velocity

u is the initial velocity

t is the time taken

So;

F = m ( ) = **3.65 x mass**

To calculate the force experienced by the ball to accelerate from rest to 73 m/s, use Newton's **second law of motion.**

To calculate the **force** experienced by the ball to accelerate from rest to 73 m/s, we can use Newton's second law of motion, which states that force equals mass times acceleration (F = m * a).

Since the ball starts from rest, its** initial velocity **(vi) is 0 m/s. The final velocity (vf) is 73 m/s. The time (t) taken for the impact is given as 2 x 10 seconds. So, the **acceleration** (a) can be calculated using the formula a = (vf - vi) / t.

Substituting the given values into the equation, we have a = (73 - 0) / (2 x 10) = 3.65 m/s^2.

Now, we can find the force (F) using the formula F = m * a. If the mass of the ball is known, we can substitute it into the equation to find the force experienced by the ball.

#SPJ3

**Answer:**

The time for final 15 cm of the jump equals 0.1423 seconds.

**Explanation:**

The initial velocity required by the basketball player to be able to jump 76 cm can be found using the third equation of kinematics as

where

'v' is the final velocity of the player

'u' is the initial velocity of the player

'a' is acceleration due to gravity

's' is the height the player jumps

Since the final velocity at the maximum height should be 0 thus applying the values in the above equation we get

Now the veocity of the palyer after he cover'sthe initial 61 cm of his journey can be similarly found as

Thus the time for the final 15 cm of the jump can be found by the first equation of kinematics as

where symbols have the usual meaning

Applying the given values we get