Solve the inequality. 3x + 7 > 4x + 2 A) x > 5
B) x < 5
C) x > 9
D) x < 9


Answer 1


answer is b

Step-by-step explanation:

explanation in the pic!

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Step-by-step explanation:


This is the two that go together, but are separate questions



Option 1)

6a + 8s = 102

14a + 4s = 150

each adult ticket costs 9 dollars



6 adult tickets and 8 student tickets bring in $102, so that means 6a+8s = 102

14 adult tickets and 4 students tickets bring in $150, so 14a+4s = 150

The system of equations is

\begin{cases}6a+8s = 102\n14a+4s = 150\end{cases}

If we multiply both sides of the second equation by -2, we get this updated system

\begin{cases}6a+8s = 102\n-28a-8s = -300\end{cases}

Add the equations straight down

6a+(-28a) = -22a

8s+(-8s) = 0s = 0 ... the 's' terms go away

102+(-300) = -198

So we end up with the equation -22a = -198 and that solves to a = 9 after dividing both sides by -22.

Each adult ticket costs $9

If you want the value of s, then

6a+8s = 102

6(9)+8s = 102

54 + 8s = 102

8s = 102-54

8s = 48

s = 48/8

s = 6

Meaning each student ticket costs $6

Or you could use the other equation

14a+4s = 150

14(9)+4s = 150

126+4s = 150

4s = 150-126

4s = 24

s = 24/4

s = 6

We get the same value of s

Which situation is most likely to have a constant rate of change?



the answer i would go with is A

Good luck on your Test :)

Step-by-step explanation:

B doesnt really have a constant rate of change as it depends on how many games happen and usually the longer an arena stays open has no correlation on how many people attend the games there

C has no real constant rate of change as it always ends up stopping after a little bit, and the change is usually not a constant one

D this could count, but since its a number that would go down if its not brought back up, its not a real constant rate of change, since it cant go below or above a certain range

so by process of elimination, A is the answer. also seeing as how its saying the distance with the number of times, that means that its an objective thing, as a track is a set distance, and the distance of a run or the track cant be affected by time or anything and could technically never end. so its a constant thing, meaning the longer the distance is, the higher the laps around the track are, and it could theoretically go on forever.

i hope this helped answer your question! :)

The answer is the question is most definitely A

QuestionCalculate the arc length for a circle whose radius is 6 with a central angle θ=135°. S=


9514 1404 393


  S = 4.5π ≈ 14.14 units

Step-by-step explanation:

The arc length is given by ...

  s = rθ . . . . . r = radius; θ = central angle in radians

The angle 135° is ...

 135° = 135°(π/180°) = 3π/4 radians

The arc of interest has length ...

  s = 6×3π/4 = 9/2π ≈ 14.14 . . . units

7+16y=;1/4 solution or no solution?



the answer is, Y= -27/64

Which expression is equivalent to the given expression?12(x – 17)

12x – 29

12 + 12 • 17

12x – 12 • 17

12x – 17



the answer would be C