P (0.5<= V <=0.54) (±0.0001)=

(b) In fact, 50% of the respondents said they planned to vote for Barack Obama V = 0.5. If respondents answer truthfully, What is P(V <=0.5)?

P (V <=0.5) (±0.0001) =

Answer:

**Answer:**

a) 97.37%

b) 1.31%

**Step-by-step explanation:**

**a) **

Here we want to calculate the area under the Normal curve with mean 0.52 and standard deviation 0.009 between 0.5 and 0.54

This can be easily done with a spreadsheet and we get

*P (0.5くV < 0.54) = 0.9737 or 97.37%*

**(See picture 1)**

**b)**

Here we want the area under the Normal curve with mean 0.52 and standard deviation 0.009 to the left of 0.5.

*P(V ≤ 0.5) = 0.0131 or 1.31%*

**(See picture 2)**

Which is bigger 0.159 or 1.590

James walked 11 miles in 4 hours. If he walkedthe same distance every hour, how many feetdid he walk in one hour?A 14,520 ftB 21,120 ftC 29,040 ftD 58,080 ftHelp?

Solve the following system by elimination x - 4y= 2 and 4x - 16y = 8

According to the Insurance Institute of America, a family of four spends between $400 and $3,800 per year on all types of insurance. Suppose the money spent is uniformly distributed between these amounts.a. What is the mean amount spent on insurance?b. What is the standard deviation of the amount spent?c. If we select a family at random, what is the probability they spend less than $2,000 per year on insurance per year?d. What is the probability a family spends more than $3,000 per year?

The commute times (in minutes) of 30 employees are listed below. (a) Find Qi, Q3, and the interquartile range (IQR). (b) Find the fences and determine if there are any outliers in the sample. 20 4 45 48 52 55 56 60 63 65 67 68 6 70 74 75 77 78 79 80 81 82 8 85 87 88 90 92 95 99

James walked 11 miles in 4 hours. If he walkedthe same distance every hour, how many feetdid he walk in one hour?A 14,520 ftB 21,120 ftC 29,040 ftD 58,080 ftHelp?

Solve the following system by elimination x - 4y= 2 and 4x - 16y = 8

According to the Insurance Institute of America, a family of four spends between $400 and $3,800 per year on all types of insurance. Suppose the money spent is uniformly distributed between these amounts.a. What is the mean amount spent on insurance?b. What is the standard deviation of the amount spent?c. If we select a family at random, what is the probability they spend less than $2,000 per year on insurance per year?d. What is the probability a family spends more than $3,000 per year?

The commute times (in minutes) of 30 employees are listed below. (a) Find Qi, Q3, and the interquartile range (IQR). (b) Find the fences and determine if there are any outliers in the sample. 20 4 45 48 52 55 56 60 63 65 67 68 6 70 74 75 77 78 79 80 81 82 8 85 87 88 90 92 95 99

(Do not round until the final answer. Then round to three decimal places as? needed.)

b. How many subjects were included in the study?

The total number of subjects in the study was___.

c. How many subjects did not use marijuana?

A total of ___subjects did not use marijuana.

**Answer:**

(a)0.615

(b)304

(c)183

**Step-by-step explanation:**

Among 147 subjects with positive test results, there are 30 false positive (actually negative) results;

Among 157 negative results, there are 4 false-negative (actual positive) results.

The table below summarises the given data.

(a)The probability that a randomly selected subject tested negative or did not use marijuana

P(negative or did not use marijuana)

=P(negative)+P(did not use marijuana)-P(both)

(b)There were a total of 304 subjects in the study.

(c)A total of 183 subjects did not use marijuana.

**Answer:**

0.087 = 8.7% probability that this person made a day visit.

0.652 = 65.2% probability that this person made a one-night visit.

0.261 = 26.1% probability that this person made a two-night visit.

**Step-by-step explanation:**

**Conditional Probability**

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

**In this question:**

Event A: Made a purchase.

**Probability of making a purchase:**

10% of 20%(day visit)

30% of 50%(one night)

20% of 30%(two night).

So

**How likely is it that this person made a day visit?**

Here event B is a day visit.

10% of 20% is the percentage of purchases and day visit. So

So

0.087 = 8.7% probability that this person made a day visit.

**A one-night visit?**

Event B is a one night visit.

The percentage of both(one night visit and purchase) is 30% of 50%. So

So

0.652 = 65.2% probability that this person made a one-night visit.

**A two-night visit?**

Event B is a two night visit.

The percentage of both(two night visit and purchase) is 20% of 30%. So

Then

0.261 = 26.1% probability that this person made a two-night visit.

A total of 634 tickets were sold for the school play. They were either adult tickets or student tickets. There were 66 fewer student tickets sold than adult tickets. How many adult tickets were sold?

So say adult sold would be x, then student sold would be x-66

add them

x+x-66=634 solve for x

2x=700 divide each side by 2

x=350

so 350 adult and 350-66=**284 student**

So say adult sold would be x, then student sold would be x-66

add them

x+x-66=634 solve for x

2x=700 divide each side by 2

x=350

so 350 adult and 350-66=

x= student tickets

y= adult tickets

x+y=634

y=x-66

x+y=634 x-y=66 2x=700 x=350

350+y=634 y=284

y= adult tickets

x+y=634

y=x-66

x+y=634 x-y=66 2x=700 x=350

350+y=634 y=284

Answer is lots of god Which equation is the inverse of *y *= 100 – *x*2?

￼

￼

￼

￼

y=2x-3

**Answer:**

(0, -3) and (4, 5)

**Step-by-step explanation:**

y = x² − 2x − 3

y = 2x − 3

2x − 3 = x² − 2x − 3

0 = x² − 4x

0 = x (x − 4)

x = 0 or 4

3

it’s just how far away that number is from zero

it’s just how far away that number is from zero