Answer:
### What is angular speed of a body?

The value of final **angular **speed of the uniform **rod **which **rests **on the frictionless **horizontal surface **is,

The **angular speed **of a body is the rate by which the **body **changed its angle with respect to the **time**. It can be given as,

A **uniform **rod of length L rests on a **frictionless **horizontal surface. The rod pivots about a fixed **frictionless** axis at one end.

The rod is **initially **at rest. A bullet traveling parallel to the **horizontal **surface and **perpendicular **to the rod with speed v strikes the rod at its center and becomes **embedded **in it.

The **mass **of the bullet is one-fourth the **mass **of the rod. The diagram for the above condition is **attached **below.

In the attached image the **angular** momentum about the point A is **constant **just before and after the **collision**. Thus,

Put the value of **inertia **as,

Solving it further we get,

Hence, the value of final **angular speed **of the uniform rodwhich rests on the frictionless **horizontal surface **is,

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Answer:

Answer: a) 0.315 (V/L)

Explanation:

From Conservation of angular momentum, we know that

L1 = L2 ,

Therefore MV L/2 = ( Irod + Ib) x W

M/4 x V x L/2 = (M (L/2)^2 + 1/3xMxL^2) x W

M/8 X VL = (ML^2/16 + ML^2 /3 )

After elimination we have,

V/8 = 19/48 x L x W

W = 48/8 x V/19L = 6/19 x V/L

Therefore W = (0.136)X V/L

When an external magnetic field is applied, what happens to the protons in a sample?A) All protons align with the field.B) All protons align opposite to the field.C) Some protons align with the field and some align opposite to it.D) All protons assume a random orientation.

Which best describes a reference frame?

When dots are further apart on a ticker-tape diagram, it indicates an object is moving

Assume we are given an electric field set up by an unknown charge distribution. U0 is the amount of work needed to bring a point charge of charge q0 in from infinity to a point P. If the charge q0 is returned to infinity, how much work would it take to bring a new charge of 4 q0 from infinity to point P?

An ordinary drinking glass is filled to the brim with water (268.4 mL) at 2.0 ° C and placed on the sunny pool deck for a swimmer to enjoy. If the temperature of the water rises to 32.0 ° C before the swimmer reaches for the glass, how much water will have spilled over the top of the glass? Assume the glass does not expand.

Which best describes a reference frame?

When dots are further apart on a ticker-tape diagram, it indicates an object is moving

Assume we are given an electric field set up by an unknown charge distribution. U0 is the amount of work needed to bring a point charge of charge q0 in from infinity to a point P. If the charge q0 is returned to infinity, how much work would it take to bring a new charge of 4 q0 from infinity to point P?

An ordinary drinking glass is filled to the brim with water (268.4 mL) at 2.0 ° C and placed on the sunny pool deck for a swimmer to enjoy. If the temperature of the water rises to 32.0 ° C before the swimmer reaches for the glass, how much water will have spilled over the top of the glass? Assume the glass does not expand.

Answer:

The BOD concentration 50 km downstream when the velocity of the river is 15 km/day is 63.5 mg/L

Explanation:

Let the initial concentration of the BOD = C₀

Concentration of BOD at any time or point = C

dC/dt = - KC

∫ dC/C = -k ∫ dt

Integrating the left hand side from C₀ to C and the right hand side from 0 to t

In (C/C₀) = -kt + b (b = constant of integration)

At t = 0, C = C₀

In 1 = 0 + b

b = 0

In (C/C₀) = - kt

(C/C₀) = e⁻ᵏᵗ

C = C₀ e⁻ᵏᵗ

C₀ = 75 mg/L

k = 0.05 /day

C = 75 e⁻⁰•⁰⁵ᵗ

So, we need the BOD concentration 50 km downstream when the velocity of the river is 15 km/day

We calculate how many days it takes the river to reach 50 km downstream

Velocity = (displacement/time)

15 = 50/t

t = 50/15 = 3.3333 days

So, we need the C that corresponds to t = 3.3333 days

C = 75 e⁻⁰•⁰⁵ᵗ

0.05 t = 0.05 × 3.333 = 0.167

C = 75 e⁻⁰•¹⁶⁷

C = 63.5 mg/L

The BOD concentration 50 km downstream from the wastewater treatment plant is approximately** 15.865 mg/L.**

To calculate the** BOD concentration **50 km downstream, we need to consider the rate of dilution due to the flow of the river and the first-order reaction that destroys BOD. The concentration of BOD **downstream **can be calculated using the equation C2 = C1 * exp(-k * d/v), where C1 is the initial concentration, k is the rate constant, d is the distance, and v is the velocity of the river.

Plugging in the given values, we have C2 = 75 * exp(-0.05 * 50/15), which gives us a BOD concentration of approximately 15.865 mg/L 50 km downstream from the wastewater treatment plant.

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**Answer:**

**0.9 cm**

**Explanation:**

The computation in the increase in the length of the joined rod is shown below:

As we know that

**Increase in length = increase in the length of aluminum rod + increase in The length of steel rod**

= **0.9 cm**

We simply added the length of aluminium rod and length of steel rod so that the length of the joined rod could come and the same is to be considered

The increase in length of the joined rod when the **temperature **is raised from 15°C to 90°C is 0.090 cm.

To determine the increase in length of the joined rod when the temperature is raised from 15°C to 90°C, we need to use the formula for linear expansion: AL = aLAT, where AL is the change in length, AT is the change in temperature, and a is the coefficient of linear expansion. First, we need to calculate the change in temperature for each rod: ΔT = 90°C - 15°C = 75°C. For the aluminum rod, using a linear expansion coefficient of 2.4 × 10-5 K-1 and a length of 10.0 cm, we can calculate the change in length using the formula: **ALaluminum **= (2.4 × 10-5 K-1)(10.0 cm)(75°C) = 0.018 cm. Similarly, for the steel rod, using a linear expansion coefficient of 1.2 × 10-5 K-1 and a length of 80.0 cm, we can calculate the change in length: ALsteel = (1.2 × 10-5 K-1)(80.0 cm)(75°C) = 0.072 cm. Since the rods are joined end-to-end, the total change in length of the joined rod is the sum of the individual changes: ΔL = ALaluminum + ALsteel = 0.018 cm + 0.072 cm = 0.090 cm. Therefore, the increase in the length of the joined rod is 0.090 cm.

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b. 6.7106 kg at [(5.72 cm),(11.44 cm)]

c. 2.46181 kg at [(16.7024 cm),(0 cm)].

How far is the center of mass of the three particles from the origin? Answer in units of cm

The **distance** of the **center of mass** of the three **particles** from the **origin** is ** 6.1428 cm **and **5.9316 cm.**

Since

m1 = 3.77 kg (0, 0 )

m2 = 6.7106 kg ( 5.72 cm, 11.44 cm)

m3 = 2.46181 kg (16.7024 cm, 0 cm )

Now here we **assume** x and y be the coordinates with respect to the centre of mass.

So,

We know that

= 6.1428 cm

Now

= 5.9316 cm

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**Answer:**

**Explanation:**

m1 = 3.77 kg (0, 0 )

m2 = 6.7106 kg ( 5.72 cm, 11.44 cm)

m3 = 2.46181 kg (16.7024 cm, 0 cm )

Let x and y be the coordinates of centre of mass.

x = 6.1428 cm

y = 5.9316 cm

**infrared **radiant **energy **is sensed by human skin as **warmth**. Hence option** C i**s correct.

**Radiation **in physics is the emission or transmission of energy as waves, particles, or both, via space or a material medium.[1][2] This comprises:

electromagnetic radiation, which **includes **gamma radiation, x-rays, microwaves, infrared, visible light, **and **ultraviolet radiation

Particle radiation includes beta radiation, proton radiation, neutron radiation, and other particles with non-zero rest energies.

ultrasonography, sound, and **seismic **waves (reliant on a physical transmission medium) are examples of acoustic radiation.

gravity radiation, which manifests as gravitational waves or ripples in spacetime's curvature

Depending on the **energy **of the emitted particles, radiation is frequently divided into ionising and non-ionizing categories. More than 10 eV is carried by ionising **radiation**, which is sufficient to ionise atoms, molecules.

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i think it is infared

**Answer:**

**Explanation:**

Cart A is moving to the right with constant speed i.e. net acceleration is zero

because acceleration is change in velocity in given time

Cart B is moving towards right with gradually speed up so there is net acceleration which helps to increase the velocity s

This indicates the net force acting on the cart towards right

For cart C there is gradual slow down of cart which indicates cart is decelerating and a net force is acting towards which opposes its motion.

**Answer: representative sample**

**Explanation:**

A representative sample can be defined as a subset of the population. This sample includes subgroups that reflect the features of the larger group and are chosen for a specific purpose of study. For example, a classroom with 60 students having 30 females and 30 males, can generate a representative sample based on the gender differences.