Answer:

**Answer:**

Part a)

Part b)

Yes it is the expected value of electric field at the surface of an atom

Part c)

**Explanation:**

Since negative charge of electrons in uniformly distributed in the atom while positive charge is concentrated at the nucleus

So the electric field due to positive charge of the nucleus is given as

now charge due to electrons inside a radius "r" is given as

now we will have electric field given as

now net electric field is given as

Part b)

At the surface of an atom

Yes it is the expected value of electric field at the surface of an atom

Part c)

If Z = 92

R = 0.10 nm

so we will have

A hollow sphere of radius 0.25 m is rotating at 13 rad/s about an axis that passes through its center. the mass of the sphere is 3.8 kg. assuming a constant net torque is applied to the sphere, how much work is required to bring the sphere to a stop?

Two particles are traveling through space. At time t the first particle is at the point (−1 + t, 4 − t, −1 + 2t) and the second particle is at (−7 + 2t, −6 + 2t, −1 + t). (a) (5 Points) Do the paths of the two particles cross? If so, where?

Which is true about the radiation force of light shining on a surface? The force is greater if the light reflects back along its incident path than in some other direction. The force is greater if the light is absorbed instead of being reflected. The force is greater if the light is reflected in some direction other than back along the incident path.

An object essentially at infinity is moved to a distance of 90 cm in front of a thin positive lens. In the process its image distance triples. Determine the focal length of the lens.

Question 7 of 10A railroad freight car with a mass of 32,000 kg is moving at 2.0 m/s when itruns into an at-rest freight car with a mass of 28,000 kg. The cars locktogether. What is their final velocity?A.1.1 m/sB. 2.2 m/sC. 60,000 kg•m/sD. 0.5 m/s

Two particles are traveling through space. At time t the first particle is at the point (−1 + t, 4 − t, −1 + 2t) and the second particle is at (−7 + 2t, −6 + 2t, −1 + t). (a) (5 Points) Do the paths of the two particles cross? If so, where?

Which is true about the radiation force of light shining on a surface? The force is greater if the light reflects back along its incident path than in some other direction. The force is greater if the light is absorbed instead of being reflected. The force is greater if the light is reflected in some direction other than back along the incident path.

An object essentially at infinity is moved to a distance of 90 cm in front of a thin positive lens. In the process its image distance triples. Determine the focal length of the lens.

Question 7 of 10A railroad freight car with a mass of 32,000 kg is moving at 2.0 m/s when itruns into an at-rest freight car with a mass of 28,000 kg. The cars locktogether. What is their final velocity?A.1.1 m/sB. 2.2 m/sC. 60,000 kg•m/sD. 0.5 m/s

Answer:

maximum speed of the car to prevent sliding is 13.1m/s

Explanation:

Given data

Radius of curve r=50m

Mass of car m=4907kg

Coefficient of friction u=0.35

Limiting for R=?

Hence limiting force R=ma

R=4907*9.81

R=48137.7N

We know that the force to overcome friction is

F=uR

Hence

F=0.35*48137.7

F=16848.2N

Centripetal force along the curve is given as

Fc=mv²/r

Fc = centripetal force

m = mass

v = velocity

r = radius

To solve for velocity we have to equate both force required to overcome friction and the centripetal force

Fc=mv²/r=F=uR

mv²/r=uR

Making velocity subject of formula we have

v²=u*r*R/m

v²=(0.35*50*48137.7)/4907

v²=842409.75/

v²=171.67

v=√171.67

v=13.1m/s

the speed at which the person falls

the change in kinetic and potential energy

the location where potential energy is zero

Answer:

the location where potential energy is zero

Explanation:

**Answer:**

Air resistance

**Explanation:**

Air resistance encountered as the person falls

I can't really tell what (I) is, but F) blender def converts electric into motion of spinning blades

The **Columb's law is the same as Gravitational law**

As we see the formula of both Coulomb and Gravitational Law,

(1)

(2)

The masses (M) in formula (1) experiencing the force of gravitational pull with each other which varies with changing the distance. In the formula (2), the charges also are felling the forces on each other which varies with distance. The charges and masses are just like the objects which are experiencing the forces which have a common factor as distance. The gravitational force is also called the mutual forces.

**Answer:**

**Explanation:**

The maximum expected measurement error for a pressure gauge measuring 0-10 bar with an inaccuracy of 1% of full-scale reading is 0.1 bar. When the gauge measures 1 bar, the expected inaccuracy is 10%.

The inaccuracy mentioned here is related to the full-scale reading which means the error is calculated based on the **top measurement value**. The pressure gauge range is 0-10 bar, so the inaccuracy is one percent of this. (a) Thus, the **maximum measurement error** expected for this instrument is 1.0% of 10 bar i.e., 0.1 bar. (b) If the gauge is measuring a pressure of **1 bar**, then the relative error expressed as a percentage would be the absolute error (0.1 bar) divided by the observed reading (1 bar) i.e., 10%. It means, when measuring 1 bar pressure, the expected measurement error is 10%. **This is an example of how instrument inaccuracy is properly interpreted and employed when working with various measurements**.

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**Complete Question **

If you are lying down and stand up quickly, you can get dizzy or feel faint. This is because the blood vessels don’t have time to expand to compensate for the blood pressure drop. If your brain is 0.4 m higher than your heart when you are standing, how much lower is your blood pressure at your brain than it is at your heart? The density of blood plasma is about 1025 kg/m3 and a typical maximum (systolic) pressure of the blood at the heart is 120 mm of Hg (= 0.16 atm = 16 kP = 1.6 × 104 N/m2).

**Answer:**

The pressure at the brain is

**Explanation:**

Generally is mathematically denoted as

Substituting for (the density) , for g (acceleration due to gravity) , 0.4m for h (the height )

We have that the pressure difference between the heart and the brain is

But the pressure of blood at the heart is given as

Now the pressure at the brain is mathematically evaluated as

When you stand up quickly, the blood pressure at your brain is lower than at your heart. The decrease in blood pressure can be calculated using the equation ΔP = ρgh, where ΔP is the change in pressure, ρ is the density of the blood, g is the acceleration due to gravity, and h is the height difference between the two points. In this case, the blood pressure at the brain is approximately **416.32 Pa** lower than at the heart.

When you stand up quickly, your blood pressure drops because the blood vessels don't have enough time to expand and compensate for the change in posture. The brain, which is 0.4 m higher than the heart when standing, experiences a decrease in blood pressure. To calculate how much lower the blood pressure is at the brain compared to the heart, we need to use the equation: ΔP = ρgh, where ΔP is the change in pressure, ρ is the density of the blood, g is the acceleration due to gravity, and h is the height difference between the two points. In this case, we can use the height difference of 0.4 m and the density of blood to find the change in pressure.

Using the equation, ΔP = ρgh, we can calculate the change in pressure:

- ρ = density of blood = 1060 kg/m³ (approximately)
- g = acceleration due to gravity = 9.8 m/s² (approximately)
- h = height difference = 0.4 m

Plugging in the values into the equation, we get:

ΔP = (1060 kg/m³)(9.8 m/s²)(0.4 m) = 416.32 Pa

Therefore, the blood pressure at the brain is approximately **416.32 Pa **lower than at the heart when standing up quickly.

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