You just measured a metal cylinder and obtained the following information: mass - 3.543 g diameter -0.53 cm height = 4.40 cm. 265 • Determine the volume (V). (V=nrºh, where r = radius, h = height, T - 3.14) V= (3.14 36205² 4.402.17cm? • Determine density of the cylinder D. 3. SMS-365923 197

Answers

Answer 1
Answer:

The density of the cylinder would be 3.652 gram/ cm³

.

What is density?

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

As given in the problem, you just measured a metal cylinder and obtained the following information: mass - 3.543 grams, diameter 0.53 cm, height = 4.40 cm , and we have to calculate the density of the cylinder,

mass of the cylinder = 3.543 grams

the volume of the cylinder = πr²h

                                            = 3.14 ×.265²×4.4

                                            =0.97 cm³

By using the above formula for density

ρ = mass of the cylinder/volume of the cylinder

  = 3.543 grams/0.97 cm³

  =3.652 grams/ cm³

Thus,the density of the cylinder would be 3.652 grams/ cm³.

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Answer 2
Answer:

Answer:

V cylinder = \pi r^2 h = \pi(0.53 cm/2)^24.4cm= 0.97 cm^3

note that r=diameter/2

density = m/V= 3.543/0.97= 3.65 g/cm^3


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Transpiration is the loss of water from the leaves of plants. The stomata of leaves must open to allowcarbon dioxide to enter the leaf for photosynthesis, but when they are open, water vapor escapes into
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HYPOTHESIS: As the intensity of light is increased, the rate of transpiration will increase, as
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Independent variable:
Dependent variable:

Answers

Independent variable are the light intensity that what we change and dependent variable are the rate of transpiration that what we measure.

What is photosynthesis ?

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The dependent variable is the rate of transpiration and the independent variable is time.The dependent variable is the rate of transportation because it is depends on the environmental factor the plant is placed.

Thus,Independent variable are the light intensity that what we change and dependent variable are the rate of transpiration that what we measure.

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Answer:

Independent variable: The light intensity (what YOU CHANGE)

Dependent variable: The rate of transpiration (what YOU MEASURE)

Consider the following reaction at equilibrium: NO2(g) + CO(g) = NO(g) + CO2(g) Suppose the volume of the system is decreased at constant temperature, what change will this cause in the system? A shift to produce more NO A shift to produce more CO A shift to produce more NO2 No shift will occur

Answers

Answer: Option (d) is the correct answer.

Explanation:

According to Le Chaltelier's principle, when there occurs any change in an equilibrium reaction then the equilibrium will shift in a direction that will oppose the change.

This means that when pressure is applied on reactant side with more number of moles then the equilibrium will shift on product side that has less number of moles.

For example, NO_(2)(g) + CO(g) \rightleftharpoons NO(g) + CO_(2)(g)

Since here, there are same number of moles on both reactant and product side. So, when volume is decreased at a constant temperature in this system then there will occur no change in the equilibrium state.

Thus, we can conclude that in the given when volume of the system is decreased at constant temperature, then no shift will occur.

The solubility of glucose at 30°C is125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.

Answers

Answer:

Saturated solution

We should raise the temperature to increase the amount of glucose in the solution without adding more glucose.

Explanation:

Step 1: Calculate the mass of water

The density of water at 30°C is 0.996 g/mL. We use this data to calculate the mass corresponding to 400 mL.

400 mL * (0.996g)/(1mL) =398g

Step 2: Calculate the mass of glucose per 100 g of water

550 g of glucose were added to 398 g of water. Let's calculate the mass of glucose per 100 g of water.

100gH_2O * (550gGlucose)/(398gH_2O) = 138 gGlucose

Step 3: Classify the solution

The solubility represents the maximum amount of solute that can be dissolved per 100 g of water. Since the solubility of glucose is 125 g Glucose/100 g of water and we attempt to dissolve 138 g of Glucose/100 g of water, some of the Glucose will not be dissolved. The solution will have the maximum amount of solute possible so it would be saturated. We could increase the amount of glucose in the solution by raising the temperature to increase the solubility of glucose in water.

The solution made by adding 550 g of glucose to 400 mL of water at 30°C is saturated. If you want to increase the amount of glucose in the solution without adding more glucose, you can increase the temperature.

The solution made by adding 550 g of glucose to 400 mL of water at 30°C is saturated.

Since the solubility of glucose at 30°C is 125 g/100 g water, adding 550 g of glucose to 400 mL of water exceeds the maximum amount of glucose that can dissolve in the given amount of water.

To increase the amount of glucose in the solution without adding more glucose, you can increase the temperature. Higher temperatures generally increase the solubility of solutes in water. By increasing the temperature, you can dissolve more glucose in the solution.

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A balloon filled with 0.500 L of air at sea level is submerged in the water to a depth that produces a pressure of 3.25 atm. What is the volume of the balloon at this depth? a. 0.154 L b. 6.50 L c. 0.615 L d. 1.63 L d. None of the above

Answers

"0.154 L" is the volume of the balloon.

Given:

Pressure,

  • P_1 = 1 \ atm
  • P_2 = 3.25 \ atm

Volume,

  • V_1 = 0.5 \ L
  • V_2 = ?

As we know,

P_1. V_1 = P_2 .V_2

or,

→      V_2 = (P_1. V_1)/(P_1)

By substituting the values, we get

            = (0.5* 1)/(3.25)

            = (0.5)/(3.25)

            = 0.154 \ L

Thus the above answer i.e., "option a" is correct.

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Answer:

Option a . 0.154L

Explanation:

P₁ . V₁ = P₂ . V₂

when we have constant temperature and constant moles for a certain gas.

At sea level, pressure is 1 atm so:

0.5 L . 1atm = V₂ . 3.25 atm

(0.5L . 1atm) / 3.25 atm = 0.154 L

The sulfuric acid–catalyzed reaction of isopentyl alcohol with acetic acid to form isopentyl acetate is performed. This reaction does not proceed to completion. After the reaction is heated under reflux for an hour, the product mixture is washed with aqueous sodium bicarbonate solution, and the organic layer is thoroughly dried. A distillation of the organic layer is then performed. Given the boiling points listed below, select the compound that will distill first.Compound Boiling point, ℃
acetic acid 118
isopentyl acetate 142
isopentyl alcohol 130
sulfuric acid water 290

Answers

Answer:

The correct option is acetic acid

Explanation:

Distillation is the process of separating a mixture of substances based on differences in boiling points. During distillation, the compound with the lowest/least boiling point is distilled and collected first and then the one with the next least boiling point and it goes on like that.

From the explanation above, acetic acid has the least boiling point (in the organic layer) with 118°C and thus will distill first. This is then followed by isopentyl alcohol (130°C) and then isopentyl acetate (142°C) and finally sulfuric acid water (290°C).

The density of an element is 11.3 g/cm'. What is its density in kg/mº? ​

Answers

The density of the element in grams per cubic centimeter can be rewritten in kilograms per cubic meter as 11,300 kg/m³

What is the density of the element in kilograms per cubic meter?

Given the parameter:

The density of an element is 11.3 g/cm³

To convert the density from grams per cubic centimeter to kilograms per cubic meter, we can use the following conversion factors:

1 gram = 0.001 kilograms

1 cm³ = 1000000m³

Density in kg/m³ = Density in g/cm³ × (0.001 kg/g) × ( 1000000 m³/cm³)

Density in kg/m³ = 1000

Now, given the density of the element as 11.3 g/cm³:

Density in kg/m³ = 11.3 × 1000

Density in kg/m³ = 11,300 kg/m³

Therefore, the density of the element is approximately 11,300 kg/m³.

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Answer:

11.3 g/cm³ = 11.3x100x100x100/ 1000 = 11300kg/m³

Explanation: