Answer:

While a power supply tester can be a useful tool for quickly checking voltage output, it might not reveal all the **potential **issues a **faulty **power **supply **can cause.

Even if a power supply tester shows that the **voltage **output of a power **supply **is within acceptable limits, it's still **possible **that the power supply may be faulty. Here's why:

1. Voltage Under **Load**: A power supply tester might only measure the voltage output under **no load **or very light load conditions.

A **faulty **power supply might provide the **correct **voltage at low loads but **fail **to deliver stable voltage under high loads, which could lead to system instability or crashes.

2. Voltage Ripple and **Noise**: Power supplies are expected to provide a stable and clean output voltage.

3. **Short Circuits **or Overloads: A power supply tester typically doesn't simulate the behavior of a real system.

4. Intermittent Issues: Faulty power supplies can exhibit **intermittent **issues. The power supply might work fine during the testing but fail when subjected to extended periods of operation or specific conditions.

5. Quality of Components: A power supply **tester **might not assess the **quality **of individual components within the power supply.

6. Compatibility Issues: Some power supplies might not be fully compatible with certain computer hardware. Even if the **voltage **seems **fine**, compatibility **issues **can still cause problems.

Learn more about **Short Circuit **here:

#SPJ12

Determine whether the following statements are true and give an explanation or counterexample.(A) If the acceleration of an object remains constant, its velocity is constant.(B) If the acceleration of object moving along a line is always 0, then its velocity is constant.(C) It is impossible for the instantaneous velocity at all times a(D) A moving object can have negative acceleration and increasing speed.

When an external magnetic field is applied, what happens to the protons in a sample?A) All protons align with the field.B) All protons align opposite to the field.C) Some protons align with the field and some align opposite to it.D) All protons assume a random orientation.

When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to make this force twice as strong, the distance would have to be changed toA) √2dB) d/√2C) d/4D) 2dE) d/2

Name the four forces in physics?

What can you infer from the fact that metals are good conductors of electricity?

When an external magnetic field is applied, what happens to the protons in a sample?A) All protons align with the field.B) All protons align opposite to the field.C) Some protons align with the field and some align opposite to it.D) All protons assume a random orientation.

When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to make this force twice as strong, the distance would have to be changed toA) √2dB) d/√2C) d/4D) 2dE) d/2

Name the four forces in physics?

What can you infer from the fact that metals are good conductors of electricity?

**Answer:**

Rocket will go to a height of 8.678 m

**Explanation:**

Mass of the rocket m = 50 gram = 0.05 kg

Spring constant k = 1050 N /m

Spring is stretched to 9 cm

So x = 0.09 m

Work done in stretching the spring

From energy conservation this energy will convert into potential energy

Potential energy is equal to , here m is mass, g is acceleration due to gravity and h is height

So

So rocket will go to a height of 8.678 m

**Answer:**

8.68 m

**Explanation:**

compression in spring, x = 9 cm = 0.09 m

Spring constant, K = 1050 N/m

mass of rocket, m = 50 g = 0.05 kg

Let it go upto height h.

Use conservation of energy

Potential energy stored in spring = potential energy of the rocket

0.5 x 1050 x 0.09 x 0.09 = 0.05 x 9.8 x h

h = 8.68 m

Thus, the rocket will go upto height 8.68 m.

**Answer:**

L > 0.08944 m or L > 8.9 cm

**Explanation:**

**Given:**

- Flux intercepted by antenna Ф = 0.04 N.m^2 / C

- The uniform electric field E = 5.0 N/C

**Find:**

- What is the minimum side length of the antenna L ?

**Solution:**

- We can apply Gauss Law on the antenna surface as follows:

Ф =

- Since electric field is constant we can pull it out of integral. The surface at hand is a square. Hence,

Ф = E.(L)^2

L = sqrt (Ф / E)

L > sqrt (0.04 / 5.0)

**L > 0.08944 m**

The area of a square antenna needed to intercept a flux of 0.040 N⋅m2/C in a uniform electric field of magnitude 5.0 N/C is 0.008 m². Consequently, each side of the antenna must be about 0.089 meters (or 8.9 cm) long.

The question pertains to the **relationship between electric field** and **flux**. The electric flux through an area is defined as the electric field multiplied by the area through which it passes, oriented perpendicularly to the field.

We are given that the electric field (E) is 5.0 N/C and the flux Φ must be 0.040 N⋅m2/C.

Hence, to intercept this amount of flux, the antenna must have an area (A) such that A = Φ / E.

That is, A = 0.040 N⋅m2/C / 5.0 N/C = 0.008 m².

Since the antenna is square, each side will have a length of √(0.008) ≈ 0.089 meters (or 8.9 cm).

#SPJ3

Hi, thank you for posting your question here at Brainly.

To solve this problem, we use Coulomb's Law:

F = kQ1Q2/d^2, where k = 9x10^9

Q1 = 3.5 uC

Q2 = -3.5 uC

Q3 = 4.0 uC

But first, we find the distance between Q1 and Q3 and between Q2 and Q3.

d between Q1 and Q2:

d = sqrt[(0-0.4)^2+(0.3-0)^2]

d = 0.5 m

d between Q1 and Q3:

d = sqrt[(0-0.4)^2+(-0.3-0)^2]

d = 0.5 m

Through force balance, F between Q2 and Q3 - F between Q1 and Q3:

Thus, the net force is -1 x 10^-12 C

To solve this problem, we use Coulomb's Law:

F = kQ1Q2/d^2, where k = 9x10^9

Q1 = 3.5 uC

Q2 = -3.5 uC

Q3 = 4.0 uC

But first, we find the distance between Q1 and Q3 and between Q2 and Q3.

d between Q1 and Q2:

d = sqrt[(0-0.4)^2+(0.3-0)^2]

d = 0.5 m

d between Q1 and Q3:

d = sqrt[(0-0.4)^2+(-0.3-0)^2]

d = 0.5 m

Through force balance, F between Q2 and Q3 - F between Q1 and Q3:

Thus, the net force is -1 x 10^-12 C

The total electric force exerted by point charges -3.5 μC and 3.5 μC on a point charge 4.0 μC is zero. This is because the forces due to each of these charges on the third charge are equal in magnitude but opposite in direction, hence they cancel each other completely.

The question asks for the magnitude and direction of the total electric force exerted by point charges -3.5 μC and 3.5 μC on a point charge 4.0 μC. This is related to **Coulomb's Law**, which describes the force between charged objects. Specifically, Coulomb's Law states that the force (F) between *two point charges* is directly proportional to the product of their charges (q1*q2) and inversely proportional to the square of the distance (r) between them. It also depends on the permittivity of free space (ε₀).

First, you would determine the force between each of the point charges and the third charge separately, and then superpose these forces to find the total force. The force in each case can be calculated using the equation F = k*|q1*q2|/r², where k is Coulomb's constant (8.99 * 10^9 N.m²/C²). You would need to make sure you take into account the signs of the charges when deciding the directions of the forces and when superposing the separate forces.

Assume upwards to be the positive direction. The 3.5 uC charge forces and -3.5 uC charge forces on the 4 uC charge would be opposite in direction (one downwards and one upwards) and identical in magnitude. Therefore, they will cancel each other out, and hence, the total electric force on the third charge (4 uC) will be zero.

#SPJ2

The **average **wavelength of radio waves ranges from roughly two millimeters to more than 150 kilometers. The **wavelengths **of radio waves are the **longest **in the electromagnetic spectrum

It can be understood in terms of the **distance **between any two similar **successive **points across any wave for example wavelength can be calculated by measuring the **distance **between any two successive crests.

It is the total length of the wave for which it **completes** one cycle.

The wavelength is **inversely **proportional to the frequency of the wave as from the following relation.

C = νλ

They also have the **lowest **frequencies, ranging from around 4,000 cycles per second, or 3 kilohertz, to roughly 280 billion hertz, or 280 **gigahertz**.

The wavelengths of **radio **waves are the longest in the electromagnetic **spectrum**, ranging from roughly two **millimeters **to more than 150 kilometers.

To learn more about **wavelength **from here, refer to the link given below;

#SPJ6

**Answer:**

Radio waves have frequencies as high as 300 gigahertz(GHz)to as low as 30 hertz(Hz).At 300 GHz the corresponding wavelength is 1mm and at 30Hz is 10,000 km

**Given Information:**

Mass of ball = m = 0.320 kg

Initial height = h₁ = 19 m

Final height = h₂ = 15 m

**Required Information:**

Impulse = I = ?

**Answer:**

Impulse = 11.77 kg.m/s

**Explanation:l**

We know that impulse is equal to change in momentum

I = Δp

I = p₁ - p₂

I = mv₁ - mv₂

I = m(v₁ - v₂)

Where m is the mass of ball, v₂ is the final velocity of the ball, and v₁ is the initial velocity of the ball.

So first we need to find the initial and final velocities of the ball

The relation between initial potential energy and final kinetic energy before the collision is given by

PE₁ = KE₂

mgh₁ = ½mv₂²

gh₁ = ½v₂²

v₂² = 2gh₁

v₂ = √2gh₁

v₂ = √2*9.8*19

v₂ = 19.3 m/s

The relation between initial kinetic energy and final potential energy after the collision is given by

KE₁ = PE₂

½mv₁² = mgh₂

½v₁² = gh₂

v₁² = 2gh₂

v₁ = √2gh₂

v₁ =√2*9.8*15

v₁ = 17.15 m/s

Finally, we can now find the magnitude of the impulse delivered to the ball by the floor.

I = 0.320(17.5 - (-19.3))

I = 11.77 kg.m/s

**Answer:**

**Explanation:**

Speed experimented by the ball before and after collision are determined by using Principle of Energy Conservation:

**Before collision**:

**After collision**:

The magnitude of the impulse delivered to the ball by the floor is calculated by the Impulse Theorem:

**Answer:**

The man ate eggs.

**Explanation:**

**He should brush his teeth before seeing his girlfriend.**