Answer:

**Answer:**

8.08 grams

**Explanation:**

Given;

Mass of the steam, m = 100 g

Change in temperature of water = (95°C - 35°C) = 60°C

Change in temperature of steam = (110°C - 100°C) = 10°C

let the mass of water by 'M'

also,

We know

specific heat of water, c = 4.184 J/Kg.°C

And, specific heat of steam, C = 2.03 J/Kg.°C

Now,

Heat released = Mass × specific heat × change in temperature

thus, for the condition given in the question

M × 4.184 × 60 = 100 × 2.03 × 10

or

M = **8.08 grams**

Answer:
### Final answer:

### Explanation:

### Learn more about Heat Transfer here:

The mass of water that will provide the same amount of heat when cooled **from 95.0 to 35.0 C as a 100 g of steam cooling from 110C to 100C is 125 grams**. To solve this question, we used the specific heat of water, calculated the heat produced in the latter scenario, and deduced the mass needed from that.

To determine the mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110 to 100C, we need to first calculate the amount of heat produced in the latter situation. Using the specific heat of water which is **4.184 J/g °C**, the heat produced when cooling 100g of steam from 110C to 100C is Q=msΔT, where m is mass, s is specific heat, and ΔT is temperature difference. So, **Q = 100g * 4.184 J/g°C * (110°C - 100°C) = 4184 J. **

Now, we have to calculate the mass of water that will produce the same amount of heat when cooled from 95°C to 35°C. We rearrange the equation to solve for mass. Hence, m = Q/sΔT = 4184 J / 4.184 J/g°C / (95.0 °C - 35.0 °C) = 125g. Therefore, 125g of water will provide the same amount of heat when cooled **from 95.0 to 35.0 C.**

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Calculate the mass of the air contained in a room that measures 2.50 m × 5.50 m × 3.00 m (density of air = 1.29 g/dm3 at 25°C).

22. What is the molar mass of oxygen (O2)?A- 15.9994 g/molB- 1.204 x 1024 g/molC- 6.02 x 1023 g/molD- 31.9988 g/mol

Based on your knowledge of waves and fider optic cables, which type of wave would be found in a fiber optic cable? Explain how you got the answer and i will mark brainliest!!!! Thank you sooooo much!

A piece of charcoal used for cooking is found at the remains of an ancient campsite. a 0.94 kg sample of carbon from the wood has an activity of 1580 decays per minute. find the age of the charcoal. living material has an activity of 15 decays/minute per gram of carbon present and the half-life of 14c is 5730 y. answer

How many milliliters of a 70.0 ml solution of 1.51 m bacl2 must be used to make 12.0 ml of a solution that has a concentration of 0.300 m cl–?

22. What is the molar mass of oxygen (O2)?A- 15.9994 g/molB- 1.204 x 1024 g/molC- 6.02 x 1023 g/molD- 31.9988 g/mol

Based on your knowledge of waves and fider optic cables, which type of wave would be found in a fiber optic cable? Explain how you got the answer and i will mark brainliest!!!! Thank you sooooo much!

A piece of charcoal used for cooking is found at the remains of an ancient campsite. a 0.94 kg sample of carbon from the wood has an activity of 1580 decays per minute. find the age of the charcoal. living material has an activity of 15 decays/minute per gram of carbon present and the half-life of 14c is 5730 y. answer

How many milliliters of a 70.0 ml solution of 1.51 m bacl2 must be used to make 12.0 ml of a solution that has a concentration of 0.300 m cl–?

**Answer:**

13440 J

**Explanation:**

c ≈ 4200 J / (kg * °C)

m = 80 g = 0,08 kg

= 10 °C

= 50 °C

The formula is: Q = c * m * ()

Calculating:

Q = 4200 * 0,08 * (50 - 10) = 13440 (J)

nonpolar amino acids: glycine, alanine, valine, leucine, isoleucine

polar amino acids: serine, threonine, cysteine, asparagine, glutamine

positively charged (basic) amino acids: lysine, arginine, histidine

negatively charged (acidic) amino acids: aspartic acid, glutamic acid

polar amino acids: serine, threonine, cysteine, asparagine, glutamine

positively charged (basic) amino acids: lysine, arginine, histidine

negatively charged (acidic) amino acids: aspartic acid, glutamic acid

not all reactions occur spontaneously. An explosion occurs when the reaction is so favorable that there is a large release of energy. An explosion can then drive more reactions.

No, they do not always produce explosions for an example baking can have a chemical reaction but you dont see my scrambled eggs explode when i make them

b. 50.00 mL

c. 75.00 mL

d. 100.00 mL

e. 25.00 mL

**Answer:**

We need 75 mL of 0.1 M NaOH ( Option C)

**Explanation:**

__Step 1: __Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

__Step 2:__ The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

__Step 3:__ Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH = 0.0075 moles

__Step 4__: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

__Step 5:__ Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

The **number **of protons **neutrons**, and electrons in each of the following species given are below;

The total number of **protons **present in an atom is known as the **atomic number **of that atom. The atomic number has no correlation either with the number of neutrons or the number of **electrons **present inside an atom.

15N7 ⇒ 7 electrons, 8 neutrons, 7 **protons**

33S16 ⇒ 16 protons, 16 electrons, 17 **neutrons**

63Cu29 ⇒ 29 **electrons**, 34 neutrons,29 protons

84Sr38 ⇒ 38 electrons, 46 **neutrons**,38 protons

130Ba56 ⇒ 56 **electrons**, 74 neutrons,56 protons

186W74⇒ 74 electrons, 112 neutrons,74 protons

202Hg80 ⇒ 80 electrons, 122 neutrons ,80 **protons**

To learn more about the **atomic number **from here, refer to the link ;

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**Answer:**

1. 7 protons, 7 electrons, 8 neutrons

2. 16 protons, 16 electrons, 17 neutrons

3. 29 protons, 29 electrons, 34 neutrons

4. 38 protons, 38 electrons, 46 neutrons

5. 56 protons, 56 electrons, 74 neutrons

6. 74 protons, 74 electrons, 112 neutrons

7. 80 protons, 80 electrons, 122 neutrons

**Answer:**

s = 22.352 m/s

**Explanation:**

**Given data:**

Time taken = 0.5 hours

Distance cover = 25 miles

Car speed = ?

**Solution:**

First of all we will convert the units.

1 hour = 3600 sec

0.5 hr ×3600 sec / 1hr = 1800 sec

**miles to meter:**

25 mi × 1609 m/ 1 mi = 40233.6 m

**Formula:**

s = d/t

s = speed

d = distance

t = time

Now we will put the values in formula.

s = 40233.6 m / 1800 sec

s = 22.352 m/s

The speed of the car, calculated by dividing the **distance travelled **(25 miles) by the time taken (0.5 hours), is 50 miles per hour.

The subject of the question falls under **Mathematics**, specifically a section of it named rate, time, and distance problems. The problem is asking us to calculate the speed of a car which can be obtained by dividing the distance travelled by the time taken. Given that the distance travelled by the car is 25 miles and the time taken is 0.5 hours, we can calculate the speed as follows.

- Denote the Speed as
*S*, the distance as*D*, and the time as*T*. - Since Speed = Distance/Time, we substitute our values into this equation
- Therefore, Speed = 25 miles / 0.5 hour =
**50 miles/hour**

So, the speed of the car is 50 miles per hour.

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