Homes may be heated by pumping hot water through radiators. What mass of water will provide the same amount of heat when cooled from 95.0 to 35.0 C, as the heat provided when 100g of steam is cooled rom 110C to 100C.

Answers

Answer 1
Answer:

Answer:

8.08 grams

Explanation:

Given;

Mass of the steam, m = 100 g

Change in temperature of water = (95°C - 35°C) = 60°C

Change in temperature of steam = (110°C - 100°C) = 10°C

let the mass of water by 'M'

also,

We know

specific heat of water, c = 4.184 J/Kg.°C

And, specific heat of steam, C = 2.03 J/Kg.°C

Now,

Heat released = Mass × specific heat × change in temperature

thus, for the condition given in the question

M × 4.184 × 60 = 100 × 2.03 × 10

or

M = 8.08 grams

Answer 2
Answer:

Final answer:

The mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110C to 100C is 125 grams. To solve this question, we used the specific heat of water, calculated the heat produced in the latter scenario, and deduced the mass needed from that.

Explanation:

To determine the mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110 to 100C, we need to first calculate the amount of heat produced in the latter situation. Using the specific heat of water which is 4.184 J/g °C, the heat produced when cooling 100g of steam from 110C to 100C is Q=msΔT, where m is mass, s is specific heat, and ΔT is temperature difference. So, Q = 100g * 4.184 J/g°C * (110°C - 100°C) = 4184 J.

Now, we have to calculate the mass of water that will produce the same amount of heat when cooled from 95°C to 35°C. We rearrange the equation to solve for mass. Hence, m = Q/sΔT = 4184 J / 4.184 J/g°C / (95.0 °C - 35.0 °C) = 125g. Therefore, 125g of water will provide the same amount of heat when cooled from 95.0 to 35.0 C.

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How many joules of heat energy are absorbed when 80.0 g of water are heated from 10.0°C to 50.0°C? *

Answers

Answer:

13440 J

Explanation:

c ≈ 4200 J / (kg * °C)

m = 80 g = 0,08 kg

t_(1) = 10 °C

t_(2) = 50 °C

The formula is: Q = c * m * (t_(2) - t_(1))

Calculating:

Q = 4200 * 0,08 * (50 - 10) = 13440 (J)

Describe the classification of the R group OF AMINO ACID GIVE THE THE EXAMPLES OF EACH CLASS

Answers

nonpolar amino acids: glycine, alanine, valine, leucine, isoleucine
polar amino acids: serine, threonine, cysteine, asparagine, glutamine
positively charged (basic) amino acids: lysine, arginine, histidine
negatively charged (acidic) amino acids: aspartic acid, glutamic acid

Chemical reactions always produce explosions yes or no

Answers

not all reactions occur spontaneously. An explosion occurs when the reaction is so favorable that there is a large release of energy. An explosion can then drive more reactions.
No, they do not always produce explosions for an example baking can have a chemical reaction but you dont see my scrambled eggs explode when i make them

How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? a. 37.50 mL
b. 50.00 mL
c. 75.00 mL
d. 100.00 mL
e. 25.00 mL

Answers

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

Step 1: Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH =  0.0075 moles

Step 4: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

Step 5: Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

Indicate the number of protons, neutrons, and electrons in each of the following species: 15N7, 33S16, 63Cu29, 84Sr38, 130Ba56, 186W74, 202Hg80

Answers

The number of protons neutrons, and electrons in each of the following species given are below;

What is the atomic number?

The total number of protons present in an atom is known as the atomic number of that atom. The atomic number has no correlation either with the number of neutrons or the number of electrons present inside an atom.

15N7 ⇒ 7 electrons, 8 neutrons, 7 protons

33S16 ⇒ 16 protons, 16 electrons, 17 neutrons

63Cu29 ⇒ 29 electrons, 34 neutrons,29 protons

84Sr38 ⇒ 38 electrons, 46 neutrons,38 protons

130Ba56 ⇒  56 electrons, 74 neutrons,56 protons

186W74⇒  74 electrons, 112 neutrons,74 protons

202Hg80 ⇒ 80 electrons, 122 neutrons ,80 protons

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Answer:

1. 7 protons, 7 electrons, 8 neutrons

2. 16 protons, 16 electrons, 17 neutrons

3. 29 protons, 29 electrons, 34 neutrons

4. 38 protons, 38 electrons, 46 neutrons

5. 56 protons, 56 electrons, 74 neutrons

6. 74 protons, 74 electrons, 112 neutrons

7. 80 protons, 80 electrons, 122 neutrons

A car travels for 0.5 hours and goes 25 miles. What is the car's speed? (Remember sad + t)

Answers

Answer:

s = 22.352 m/s

Explanation:

Given data:

Time taken = 0.5 hours

Distance cover = 25 miles

Car speed = ?

Solution:

First of all we will convert the units.

1 hour = 3600 sec

0.5 hr ×3600 sec / 1hr = 1800 sec

miles to meter:

25 mi × 1609 m/ 1 mi = 40233.6 m

Formula:

s =  d/t

s = speed

d = distance

t = time

Now we will put the values in formula.

s = 40233.6 m / 1800 sec

s = 22.352 m/s

Final answer:

The speed of the car, calculated by dividing the distance travelled (25 miles) by the time taken (0.5 hours), is 50 miles per hour.

Explanation:

The subject of the question falls under Mathematics, specifically a section of it named rate, time, and distance problems. The problem is asking us to calculate the speed of a car which can be obtained by dividing the distance travelled by the time taken. Given that the distance travelled by the car is 25 miles and the time taken is 0.5 hours, we can calculate the speed as follows.

  1. Denote the Speed as S, the distance as D, and the time as T.
  2. Since Speed = Distance/Time, we substitute our values into this equation
  3. Therefore, Speed = 25 miles / 0.5 hour = 50 miles/hour

So, the speed of the car is 50 miles per hour.

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