# What is half of 3 5/10?

Therefore, (35/10)/2
= 35/20

## Related Questions

(4x ^2+2x+1) (x^2-3x+5)

You need to multiply the polynomials. Please see attached picture for answer.

= 4x ^4 + -10x^3 + 15x^2 + 7x +5

Step-by-step explanation:

You need to multiply each term step by step

(4x ^2+2x+1)*(x^2) + (4x ^2+2x+1)*(-3x) + (4x ^2+2x+1)*5

= (4x ^4 + 2x^3 +x^2) + (-12x ^3 - 6x^2 -3x) + (20x ^2+10x+5)

= 4x ^4 + -10x^3 + 15x^2 + 7x +5

Is 28/49=4/7 a ratio proportion

28 / 49
divide by 7 at top and bottom

(28/7) / (49/7)
4 / 7

F(x) = 3x+2
What is f(5)?

f(5) = 17

Step-by-step explanation:

f(x) = 3x+2

Let x =5

f(5) = 3(5) +2

f(5) = 15+2

f(5) = 17

4) At the end of the summer, I decide to drain the swimming pool. I noticed that it drains faster when there is more water in the pool. That was interesting to me, so I decided to measure rate at which it drains. I found that it was draining at a rate of 3% every 5 minutes How many gallons are left in the pool after 50 minutes?

After 50 minutes, the pool has 73.74% of its initial water left, meaning it drained 26.26% of the initial water. To represent this remaining amount in gallons, it would be 0.7324 times the initial volume (in gallons).

### Explanation:

To answer your question regarding the amount of water left after draining the pool for 50 minutes with a drain rate of 3% every five minutes, it is important to understand that the reduction occurs in a compound manner. This means each time we are dealing with 97% (100% - 3%) of the previous total.

So after 10 iterations (equaling to your 50 minutes since each iteration is 5 minutes long), we are left with (0.97)^10 = 73.74% of the initial total. That means 26.26% of the water has been drained.

In terms of gallons, if X represents the initial volume of water in the pool, then 0.7324 * X gallons remain after 50 minutes. Without knowing the initial volume of the pool, it is impossible to give a precise value in gallons.

brainly.com/question/35909343

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+8=54